I would like in EasyAdmin 4 at the menu level to add an element which allows to display a pdf containing the instructions for use of the administration. I can't find a tutorial. Do you know how to do it ? Thank you
In method configureMenuItems in your DashboardController add link to route with the PDF. Like following:
<?php
use EasyCorp\Bundle\EasyAdminBundle\Config\MenuItem;
use EasyCorp\Bundle\EasyAdminBundle\Controller\AbstractDashboardController;
class DashboardController extends AbstractDashboardController
{
// ...
public function configureMenuItems(): iterable
{
return [
MenuItem::linkToRoute('PDF', 'fa ...', 'route_name'),
];
}
}
It can be found in the official documentation: https://symfony.com/bundles/EasyAdminBundle/current/dashboards.html#route-menu-item
You can also use MenuItem::linkToUrl if you don't have route for the PDF file.
Related
I'm making a presonification menu on my navbar so that i can access from any page i don't want to use the getRepository inside a controller and pass to the frontend.
Is there a way on symfony 4 that I can get all the users from my database and call it to front? like the app.session.user (to get info on the logged user) for example?
Thanks!
As Cerad mentioned, you can embed a Controller in your templates : https://symfony.com/doc/current/templates.html#embedding-controllers
Instead of doing {% include 'base/navbar.html.twig' %} you will do
In your template :
{{ render(controller('App\\Controller\\BaseController::renderNavbar')) }}
In BaseController
public function renderNavbar(UserRepository $userRepository) {
return $this->render('base/navbar.html.twig', [
'activeUsers' => $userRepository->findActiveUsers(),
]);
}
It's not a route, it's simply a function that renders html, so you don't need to add annotations.
I have a partial view in master layout which is the navigation bar. I have a variable $userApps. This variable checks if the user has enabled apps (true), if enabled then I would like to display the link to the app in the navigation bar.
homepage extends master.layout which includes partials.navbar
My code in the navbar.blade.php is this:
#if ($userApps)
// display link
#endif
However I get an undefined variable error. If I use this in a normal view with a controller it works fine after I declare the variable and route the controller to the view. I dont think I can put a controller to a layout since I cant route a controller to a partial view, so how do I elegantly do this?
What version of Laravel you use? Should be something like this for your case:
#include('partials.navbar', ['userApps' => $userApps])
Just for a test purpose, I did it locally, and it works:
routes.php
Route::get('/', function () {
// passing variable to view
return view('welcome')->with(
['fooVar' => 'bar']
);
});
resources/views/welcome.blade.php
// extanding layout
#extends('layouts.default')
resources/views/layouts/default.blade.php
// including partial and passing variable
#include('partials.navbar', ['fooVar' => $fooVar])
resources/views/partials/navbar.blade.php
// working with variable
#if ($fooVar == 'bar')
<h1>Navbar</h1>
#endif
So the problem must be in something else. Check your paths and variable names.
The other answers did not work for me, or seem to only work for older versions. For newer versions such as Laravel 7.x, the syntax is as follows.
In the parent view:
#include('partial.sub_view', ['var1' => 'this is the value'])
In the sub view:
{{ $var1 }}
I have gone through all the answers but below is the best way to do because you can also run queries in serviceProvider.
You need to create a separate service or you can use AppServiceProvider
<?php
namespace App\Providers;
use Illuminate\Support\Facades\View;
use Illuminate\Support\ServiceProvider;
class AppServiceProvider extends ServiceProvider
{
/**
* Register any application services.
*
* #return void
*/
public function register()
{
//
}
/**
* Bootstrap any application services.
*
* #return void
*/
public function boot()
{
View::composer('layouts.admin-layout', function ($view) {
$view->with('name', 'John Doe');
});
}
}
In your layout
{{$name}}
This approach is very simple:
In parent view :
#include('partial.sub_view1', ['This is value1' => $var1])
In sub view :
{{ $var1 }}
You can use view composer to send your variable to partial view.
Check the laravel documentation on laravel.com about view composer.
Also you can check the following link that will help you resolve this problem.
https://scotch.io/tutorials/sharing-data-between-views-using-laravel-view-composers
I'm working with laravel pagination, however I wish to display the pagination links regardless of if there is only a single page, or multiple pages.
Currently, it is only displayed if there are multiple pages of results.
Eloquent Call
$products = Product::where('username', Sentry::getUser()->username)->paginate(25);
and then displayed in the view using
{!! $products->links() !!}
How can I force Laravel to display it when there is only a single page?
Publish pagination views:
php artisan vendor:publish --tag=laravel-pagination
This command will place the views in the resources/views/vendor/pagination directory.
Default view is bootstrap-4.blade.php and just delete the #if ($paginator->hasPages()) in this file.
Following Alexey Mezenin's answer, I extended the BootstrapThreePresenter class:
<?php namespace App\Extend;
use Illuminate\Pagination\BootstrapThreePresenter;
class CustomPaginationLinks extends BootstrapThreePresenter {
public function hasPages()
{
return true;
}
}
And was then able to render in the view like so:
{!! with(new App\Extend\CustomPaginationLinks($products))->render() !!}
There is no easy way, because it's hardcoded. However you could extend SimpleBootstrapThreePresenter and override hasPages() method:
public function hasPages()
{
return true;
}
Instead of:
public function hasPages()
{
return $this->paginator->hasPages() && count($this->paginator->items()) > 0;
}
I have an installation of Laravel 5.1 and I want to share the route name with all my views. I need this for my navigation so I can highlight the corresponding navigation menu button depending on which page the user is on.
I have this code in my app\Providers\AppServiceProvider:
public function boot()
{
$path = Route::getCurrentRoute()->getName();
view()->share('current_route_name', $path);
}
and I am using this namespace:
use Illuminate\Support\Facades\Route;
but I am getting this error in my view:
Call to a member function getName() on a non-object
the interesting part is that if I write this in view it works with no problems at all:
{{ Route::getCurrentRoute()->getName() }}
Could anyone help me? am I not using the correct namespace or maybe it is not even possible to use Route at this point in the application?
Thank you!
you can use view share under view composer.
view()->composer('*', function($view)
{
$view->with('current_route_name',Route::getCurrentRoute()->getName());
});
Or
view()->composer('*', function($view)
{
view()->share('current_route_name',Route::getCurrentRoute()->getName());
})
I'm learning Laravel, and for my first project I'd like to create my portfolio. However, the first task I have to do is confusing me.
So I created my templates, layout.blade.php and home.blade.php. That makes sense to me, but now how do I tell Laravel, or how do I route to home.blade.php?
I'm looking for an explanation rather then just code. I'm trying to learn.
Actually, a view in MVC application is just a part of the application and it's only for presentation logic, the UI and one doesn't call/load a view directly without the help of another part (controller/function) of the application. Basically, you make a request to a route and that route passes the control over to a controller/function and from there you show/load the view. So it's not a tutorial site and it's also not possible to explain about MVC here, you should read about it and for Laravel, it's best place to understand the basics on it's documentation, well explained with examples, anyways.
In case of Laravel, you should create a controller/class or an anonymous function in your apps/routes.php file and show the view from one of those. Just follow the given instruction step by step.
Using a Class:
To create a route to your Home Controller you should add this code in your app/routes.php
// This will call "showWelcome" method in your "HomeController" class
Route::any('/', array( 'as' => 'home', 'uses' => 'HomeController#showWelcome' ));
Then create the HomeController controller/class (create a file in your controllers folder and save this file using HomeController.php as it's name) then paste the code given below
class HomeController extends BaseController {
public function showWelcome()
{
// whatever you do, do it here
// prepare some data to use in the view (optional)
$data['page_title'] = 'Home Page';
// finally load the view
return View::make('home', $data);
}
}
If you have {{ $title }} in your home.blade.php then it'll print Home Page. So, to use a view you need a controller or an anonymous function and load the view from the controller/function.
Using an anonymous function:
Also, you can use an anonymous function instead of a controller/class to show the view from directly your route, i.e.
Route::any('/', function(){
// return View::make('home');
// or this
$data['page_title'] = 'Home Page'; // (optional)
return View::make('home', $data);
});
Using this approach, whenever you make a request to the home page, Laravel will call the anonymous function given in/as route's callback and from there you show your view.
Make sure to extend the the master/main layout in sub view (home):
Also, remember that, you have following at the first line of your home.blade.php file
#extends('layouts.layout')
It looks confusing, you may rename the main layout (layout.blade.php) to master.blade.php and use following in your home.blade.php instead
#extends('layouts.master')
Read the doc/understand basics:
You should read Laravel's documentation properly, (check templates to understand blade templating) and also read some MVC examples, that may help you too understand the basics of an MVC framework (you may find more by googling) and some good posts about MVC on SO.
Check it routing in Laravel.
You need to use route file and controllers
Create needed function in your Controller file and create a template file for example
class UserController extends BaseController {
/**
* Show the profile for the given user.
*/
public function showProfile($id)
{
$user = User::find($id);
return View::make('user.profile', array('user' => $user));
}
}
you need to create view file views/user/profile.blade.php
View::make('user.profile', array('user' => $user)) == views/user/profile.blade.php
And you should read it http://laravel.com/docs/responses and also this http://laravel.com/docs/quick#creating-a-view