My function is not called a second time why [duplicate] - php

Question

The following code doesn't print out anything:
$bool_val = (bool)false;
echo $bool_val;
But the following code prints 1:
$bool_val = (bool)true;
echo $bool_val;
Is there a better way to print 0 or false when $bool_val is false than adding an if statement?

Answer 1

echo $bool_val ? 'true' : 'false';
Or if you only want output when it's false:
echo !$bool_val ? 'false' : '';

Answer 2

This is the easiest way to do this:
$text = var_export($bool_value,true);
echo $text;
or
var_export($bool_value)
If the second argument is not true, it will output the result directly.

Answer 3

This will print out boolean value as it is, instead of 1/0.
$bool = false;
echo json_encode($bool); //false

Answer 4

No, since the other option is modifying the Zend engine, and one would be hard-pressed to call that a "better way".
Edit:
If you really wanted to, you could use an array:
$boolarray = Array(false => 'false', true => 'true');
echo $boolarray[false];

Answer 5

Try converting your boolean to an integer?
echo (int)$bool_val;

Answer 6

I like this one to print that out
var_dump ($var);

Answer 7

var_export provides the desired functionality.
This will always print a value rather than printing nothing for null or false. var_export prints a PHP representation of the argument it's passed, the output could be copy/pasted back into PHP.
var_export(true); // true
var_export(false); // false
var_export(1); // 1
var_export(0); // 0
var_export(null); // NULL
var_export('true'); // 'true' <-- note the quotes
var_export('false'); // 'false'
If you want to print strings "true" or "false", you can cast to a boolean as below, but beware of the peculiarities:
var_export((bool) true); // true
var_export((bool) false); // false
var_export((bool) 1); // true
var_export((bool) 0); // false
var_export((bool) ''); // false
var_export((bool) 'true'); // true
var_export((bool) null); // false
// !! CAREFUL WITH CASTING !!
var_export((bool) 'false'); // true
var_export((bool) '0'); // false

Answer 8

echo(var_export($var));
When $var is boolean variable, true or false will be printed out.

Answer 9

This gives 0 or 1:
intval($bool_val);
PHP Manual: intval function

Answer 10

The %b option of sprintf() will convert a boolean to an integer:
echo sprintf("False will print as %b", false); //False will print as 0
echo sprintf("True will print as %b", true); //True will print as 1
If you're not familiar with it: You can give this function an arbitrary amount of parameters while the first one should be your ouput string spiced with replacement strings like %b or %s for general string replacement.
Each pattern will be replaced by the argument in order:
echo sprintf("<h1>%s</h1><p>%s<br/>%s</p>", "Neat Headline", "First Line in the paragraph", "My last words before this demo is over");

Answer 11

You can use a ternary operator
echo false ? 'true' : 'false';

Answer 12

Your'e casting a boolean to boolean and expecting an integer to be displayed. It works for true but not false. Since you expect an integer:
echo (int)$bool_val;

Answer 13

json_encode will do it out-of-the-box, but it's not pretty (indented, etc):
echo json_encode(array('whatever' => TRUE, 'somethingelse' => FALSE));
...gives...
{"whatever":true,"somethingelse":false}

Answer 14

You can try this if you want debug an array:
function debug_array($a){
return array_map(function($v){
return is_bool($v) ? ($v ? 'true' : 'false') : $v;
}, $a);
}
To use it:
$arr = debug_array(['test' => true, 'id' => false]);
print_r($arr); // output Array ( [test] => true [id] => false )