I am trying to do a str_replace without success.. for some reason the data from MySql isn't working inside the str_replace function...
Code to bring all strings which will be used to replace the string:
$aspas = "'";
$sql2 = '
SELECT
GROUP_CONCAT(
DISTINCT CONCAT("'.$aspas.'", prefixo, "-'.$aspas.','.$aspas.'-", posfixo, "'.$aspas.'")
) AS prefixo_posfixo
FROM
profissionais
';
$stm2 = $pdo->prepare($sql2);
$stm2->execute();
$resultado = $stm2->fetch();
Produces with no error this output:
echo $resultado[0] >> 'dr-','-advogado','dra-','-advogada'
But when I try to insert inside the str_replace function :
$newstring = str_replace([$resultado[0]], '', 'dra-flavia-barao-advogada');
echo newstring >> dra-flavia-barao-advogada
As you see, the result keep the same, it doesn't replace the string ;(
I think it is something about convert the array to string, but the $resultado[0] isn't in a array format so I cant implode...
Do you know what I am doing wrong?
I forgot to post the solution before, There is:
//SELECT THE STRINGS TO BE USED TO REMOVE FUNCTION
$sql2 = '
SELECT
GROUP_CONCAT(
DISTINCT CONCAT(prefixo, "-,-",posfixo)
) AS prefixo_posfixo
FROM
profissionais
';
$stm2 = $pdo->prepare($sql2);
$stm2->execute();
$prefixo_posfixo = $stm2->fetch();
//REPLACE / REMOVE THE STRINGS
$newstring = str_replace(explode(",", $prefixo_posfixo[0]), '', 'dra-flavia-barao-advogada');
//PRODUCES THE OUTPUT
flavia-barao
Related
I would like to delete one last word of String variable in PHP. I tried to do it according to this code: https://stackoverflow.com/a/29428662/10490051. But it doesn't solve my problem.
I would like to use it for SQL argument:
$sql_request = "SELECT fullname FROM names WHERE lastname='johnson' and city='oxford' ";
$sql_request = preg_replace('/\W\w+\s*(\W*)$/', '$1', $sql_request);
echo $sql_request;
Specifically I need to delete whole last argument: city='oxford'.
(I need to delete all from end to first space)
But result of my code will be:
SELECT fullname FROM names WHERE lastname='johnson' and city='
but I need this:
SELECT fullname FROM names WHERE lastname='johnson' and
So how to delete whole last argument and not only part of them?
Thank you.
If you dont want to dance with the REGEX Devil, you can use the simpler mechanism
$sql_request = "SELECT fullname FROM names WHERE lastname='johnson' and city='oxford' ";
$sql_request = trim($sql_request);
$pos = strrpos($sql_request, ' ');
$sql_request = substr($sql_request, 0, $pos);
echo $sql_request;
RESULT
SELECT fullname FROM names WHERE lastname='johnson' and
Or wrapping it all into a single line
$sql_request = substr( $sql_request, 0, strrpos(trim($sql_request), ' '));
echo $sql_request;
Update based on question in the comment
$pos = strrpos($sql_request, ' and');
$sql_request = substr( $sql_request, 0, $pos);
echo $sql_request;
Or wrapping it all into a single line
$sql_request = substr( $sql_request, 0, strrpos($sql_request, ' and'));
echo $sql_request;
I have Chinese php search queries.
I want to split up any query up into individual characters.
ex: 你好 (ni hao, hello) split into 你 and 好
my query is set like:
$q = $_REQUEST["q"];
the results I want to split is set up like:
$results4 = $db->query( "SELECT CHS, PIN, DEF FROM FOUR
WHERE CHS LIKE '%".$q."%' OR PIN LIKE '%".$q."%'");
while ($row4 = $results4->fetchArray()) {
How can I split up the keyword and look up all the components?
If you want it all in one query you will have to generate the whole query. If you were looking for an exact match you could use something similar to the in_array() function, but with LIKE it doesn't work.
You could however loop through the array of characters and put together the WHERE part programatically.
Like this
$where = array();
foreach ( $qtwo as $word ) {
$where[] = "CHS LIKE '%" . $word . "%'";
}
$where = implode(' OR ', $where);
Use this $where variable in your query
You can use str_split to convert a string in an array of chars
$chars = str_split($q)
In php, if I had a string of comma separated data like this which came from a database:
John,Paul,Ringo,George
how could I convert it to something like this, without using a for loop or any extra processing. Does php have a function that can do this?
$str = 'John','Paul','Ringo','George';
I currently split the string using explode and then reformat it. Anyway to achieve this without doing that?
The formatted string is sent to a SQL where it's used in a MySQL IN() function.
If you absolutely don't want to use explode() you could use
$str = 'John,Paul,Ringo,George';
$newStr = "'" . str_replace(",","','", $str) . "'";
You can use preg_replace with $1 thing.
UPDATED:
See usage example:
echo preg_replace('((\\w+)(,?))', '"$1"$2', 'John,Paul,Ringo,George');
you can use explode like below
$db_data = 'John,Paul,Ringo,George';//from your db
$l = explode(',',$db_data);
echo "select * from table where column IN('".implode("','",$l)."')";
output:
select * from table where column IN('John','Paul','Ringo','George')
You can use the explode and implode functions in PHP.
$names = explode(',', 'John,Paul,Ringo,George');
echo implode(',', $names);
I hope I got you right:
$str_1 = 'John,Paul,Ringo,George';
$str_2 = explode(',', $str_1);
$str_3 = implode('\',\'', $str_2);
$str_4 = '\''.$str_3.'\'';
echo $str_4;
Output: 'John','Paul','Ringo','George'
$l = 'John,Paul,Ringo,George';
$lx = "'" . implode("','", explode(",", $l)) . "'";
echo $lx; // 'John','Paul','Ringo','George'
I have a script which inserts all data in array to MYSQL. But when there is just a single word in the array, the script gives no error, while when there are multiple words, it gives a
Column count doesn't match value count at row 1
Here is my code
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST') {
include("connect.php");
$counter = 0;
$counters = 0;
$string = mysql_real_escape_string($_POST['words']);
$arr = explode(" ", $string);
mysql_query("SET charset utf8");
$sql = mysql_query("SELECT `word` FROM unicode WHERE word IN ('".implode("', '", $arr) . "')") or die (mysql_error());
$dupes = array();
while($r = mysql_fetch_assoc($sql)) {
$dupes[] = $r['word'];
}
$newwords = array_diff($arr, $dupes);
if(count($newwords)) {
$word = implode("'),('", $newwords);
$md5 = md5($word);
$sqli = mysql_query("INSERT INTO unicode (word, word_hash) VALUES ('$word', '$md5')") or die (mysql_error());
}
}
?>
Please help....
As a rule, when I have problems with SQL I do the following things to track down the issue.
ECHO out the SQL query I am trying to run against the DB. This makes sure that I am passing the value of the variable and not the the text '$variable'.
Switch on and check the general.log table in the MySQL DB (assuming you are using MySQL). This will show you the last queries run against the DB and will prove one way or another if your script is even executing anything against the DB.
Lastly I am not as au fait with imploding etc as suggest above to comment, however I would also add the following. Looking at your query it looks as if you are doing I what I talked about in point 1.
$sqli = mysql_query("INSERT INTO unicode (word, word_hash) VALUES ('$word', '$md5')") or die (mysql_error());
The single quotes around $word and $md5 would mean literally pass $word and $md5 into the DB. When using variables within double quote " ... " you do not need to put anything around them just use them as is. Or if you would like to use single quote marks you can concatenate the query string.
$sqli = mysql_query('INSERT INTO unicode (word, word_hash) VALUES ( ' . $word . ', ' . $md5 . ')') or die...
Again echo out the query as you have it (without the mysqli_query function) to confirm.
Hope this helps.
S
You're imploding $newwords, so the resulting query would look something like:
...VALUES ('word1'),('word2'),('word3', 'md5 string')
Add $md5 to implode():
$md5 = 'md5 string';
$word = implode("', '$md5'),('", array('word1', 'word2', 'word3'));
Outputs:
...VALUES ('word1', 'md5 string'),('word2', 'md5 string'),('word3', 'md5 string')
The number of column parameters in your INSERT query is more than 2, but you've only provided 2 values.
$word = implode("'),('", $newwords);
This statement here is the culprit. When you implode the $newwords array, you'd probably get more than 2 values. When inserted into the MySQL query, it won't match with the number of VALUES you've provided. That's causing the error.
I have a form which is a select multiple input which POSTs values like this: option1,option2,option3 etc..
How is the best way to convert this to 'option1','option2','option3' etc...
Currenty I'm doing this, but it feels wrong??
$variable=explode(",", $variable);
$variable=implode("','", $variable);
The reason why I'm doing this is because I want to use the form select multiple inputs in a SQL Query using IN.
SELECT * FROM TABLE WHERE some_column IN ('$variable')
You can wrap whatever code in a function to make the "feels wrong" feeling disapear. E.g.:
function buildSqlInClauseFromCsv($csv)
{
return "in ('" . str_replace(",", "','", $csv) . "') ";
}
If $variable = "option1,option2,option3"
you can use:
"SELECT * FROM TABLE WHERE FIND_IN_SET(some_column, '$variable')"
Here is what I used:
WHERE column IN ('".str_replace(",", "','", $_GET[stringlist])."')
we know that implode converts array to string,we need to provide the separator and then array as shown below, here we have (coma ,) as a separator.
Implode breaks each element of an array with the given separator,I have conceited '(single quotes) with the separator.
$arr = array();
$arr[] = "raam";
$arr[] = "laxman";
$arr[] = "Bharat";
$arr[] = "Arjun";
$arr[] = "Dhavel";
var_dump($arr);
$str = "'".implode("','", $arr)."'";
echo $str;
output: 'raam','laxman','Bharat','Arjun','Dhavel'
There is only one correct way to escape strings for SQL - use the function provided by the database api to escape strings for SQL. While mysyl_* provides mysql_real_escape_string():
$choices = explode(",", $variable);
foreach($choices as &$choice)
$choice = "'".mysql_real_escape_string($choice)."'";
$choices = implode(",", $choices);
PDO provides a method that will add quotes at the same time:
$choices = explode(",", $variable);
foreach($choices as &$choice)
$choice = $pdoDb->quote($choice);
$choices = implode(",", $choices);
Note that PDO::prepare doesn't really work here