Hi Can you help me in my problem?
checking if a time range contains another time range for example I have 2 time range:
$nightShiftStart = strtotime("22:00:00 today");
$nightShiftEnd = strtotime("06:00:00 tomorrow");
$overTimeStart = strtotime("21:00:00 today");
$overTimeEnd = strtotime("07:00:00 tomorrow");
if I check if overtime start and end contains night shift schedule it should return true. And I have a code for that.
if ($overTimeStart >= $nightShiftStart && $overTimeEnd <= $nightShiftEnd ) {
return true;
} else {
return false;
}
the code above will return true. but if I change the overtime range to this:
$nightShiftStart = strtotime("22:00:00 today");
$nightShiftEnd = strtotime("06:00:00 tomorrow");
$overTimeStart = strtotime("17:00:00 today");
$overTimeEnd = strtotime("20:00:00 today");
it also return true, it should return false because the overtime is only from 5pm to 8pm and the time not meet the Night Shift. Can you pls help me with this i've been stuck for 2days.
Take a look at the document: https://www.php.net/manual/en/datetime.formats.relative.php
Exceptions to this rule are: "yesterday", "midnight", "today", "noon" and "tomorrow". Note that "tomorrow 11:00" and "11:00 tomorrow" are different. Considering today's date of "July 23rd, 2008" the first one produces "2008-07-24 11:00" where as the second one produces "2008-07-24 00:00". The reason for this is that those five statements directly influence the current time.
So the correct strings should be:
$nightShiftStart = strtotime("today 22:00:00");
$nightShiftEnd = strtotime("tomorrow 06:00:00");
$overTimeStart = strtotime("today 17:00:00");
$overTimeEnd = strtotime("today 20:00:00");
Related
I have two times like start_time and end_time and also having a time range like a start time and a end time. I want to check start_time and end_time are in the range of start time and end time or not. How to check that.
$start_time1 = 10:15 am; //! time table start time
$end_time1 = 12:30 pm; //! time table end time
$strattime2 = 10:00 am; //! time range - start time
$endtime2 = 1:00 pm; //! time range - end time
How to resolve this problem?
Just check the boundary of the range. The query must be started on or after the range and must be ended on or before the range ends. So
function check($queryStart, $queryEnd, $rangeStart, $rangeEnd) {
return ($queryStart >= $rangeStart && $queryEnd <= $rangeEnd);
}
If you want to check whether the query is overlapping the range or not, you should check whether the query ends before the range start or the query starts after the range end.
function overlap($queryStart, $queryEnd, $rangeStart, $rangeEnd) {
return !($queryEnd < $rangeStart || $queryStart > $rangeEnd);
}
you may convert all the times to DateTime() Objects and then check the difference like so:
<?php
function startStopTimeIsWithinRange($startTime='10:15', $stopTime='12:30') {
$dateStart = new DateTime('2016-10-30 ' . $startTime); //<== IGNORE, THE DATE. NOTICE THE TIME
$dateStop = new DateTime('2016-10-30 ' . $stopTime); //<== IGNORE, THE DATE. NOTICE THE TIME
$rangeStart = new DateTime('2016-10-30 10:00'); //<== IGNORE, THE DATE. NOTICE THE TIME
$rangeStop = new DateTime('2016-10-30 13:00'); //<== IGNORE, THE DATE. NOTICE THE TIME
if($dateStart >= $rangeStart && $rangeStop >= $dateStop){
return true;
}
return false;
}
var_dump( startStopTimeIsWithinRange('10:15', '12:30') ); //<== NOTICE THE COLON (:) AND NOT DOT (.)
I need to check the given period will at least be covers the one night of the weekend(saturday night or sunday night) (refer the wiki article about the rule).
I found this question that, how to check the date whether it is fall on weekend or not,
function isWeekend($date) {
$weekDay = date('w', strtotime($date));
return ($weekDay == 0 || $weekDay == 6);
}
But still I am struggle with how to implement a function to get following sample results for given periods,
Sample periods and results:
04-01-2016 / 07-01-2016 : false
04-01-2016 / 09-01-2016 : false
04-01-2016 / 10-01-2016 : true (covers saturday night)
03-01-2016 / 07-01-2016 : true (covers sunday night)
04-01-2016 / 14-01-2016 : true (covers a full weekend)
The rule should wither start date is falls on weekend or end date is falls on sunday or the period covers at a full weekend.
I presume you're looking for something like this:
function coversWeekend($start, $end) {
$weekend = [0, 6]; // 0 for Sunday, 6 for Saturday.
// Loop over the date period.
while ($start < $end) {
if (in_array($start->format('w'), $weekend)) {
return true;
}
$start->modify('+1 day');
}
return false;
}
Be warned, there isn't on validation on what the user passes in. You may want to add a check that a valid DateTime object was passed for each parameter.
Hope it helps.
Edit: Updated the solution with #honzalilak's feedback.
I am trying to get stripe to set a end_trial date on the next occurrence of whatever day of the month the user chooses. i.e. If today is the 16th and the user chooses the 15th I need the unix timestamp for the 15th of the next month. However if today was the 14th I need the timestamp for tomorrow.
I tried the solution found on this SO question Find the date for next 15th using php .
When i ran the code suggested in that question and substituted 15 for 31
$nextnth = mktime(0, 0, 0, date('n') + (date('j') >= 31), 31);
echo date('Y-m-d', $nextnth);
The result is 2013-03-03
I also tried this one Get the date of the next occurrence of the 18th .
The second one would actually give me 2013-03-31 when i ran it one 2013-1-31.
Both had unexpected results. Is february the problem? Any guidance will be much appreciated.
Here is a way to do it.
function nextDate($userDay){
$today = date('d'); // today
$target = date('Y-m-'.$userDay); // target day
if($today <= $userDay){
$return = strtotime($target);
}
else{
$thisMonth = date('m') + 1;
$thisYear = date('Y');
if($userDay >= 28 && $thisMonth == 2){
$userDay = 28;
}
while(!checkdate($thisMonth,$userDay,$thisYear)){
$thisMonth++;
if($thisMonth == 13){
$thisMonth = 1;
$thisYear++;
}
}
$return = strtotime($thisYear.'-'.$thisMonth.'-'.$userDay);
}
return $return;
}
// usage
echo date('Y-m-d',nextDate(29));
We get the user's choice and compare it today.
If today is less than or equal to user choice, we return the timestamp for this month.
If today is greater than user choice, we loop through dates, adding a month (or a year if it's $thisMonth hits 13). Once this date does exist again, we have our answer.
We check the dates using php's checkdate function, strtotime and date.
I really don't understand the question completely. You can easily determine the date for next 30 days for example
$next_ts = time() + 30 * 86400; // add 30 days to current timestamp
$next = date('Y-m-d', $next_ts); // format string as Y-m-d
echo $next;
If that is not what you need, please explain the problem.
From October 1st to March 31 the fee is $1 (season 1). From April 1st to September 30 the fee is $2 (season 2).
How can I calculate the total fee of a given date range (user input) depending on how many days of this date range fall into season 1 and season 2?
The following gives me the number of days of the user´s date range, but I have no idea how to test against season 1 or season 2:
$user_input_start_date = getdate( $a );
$user_input_end_date = getdate( $b );
$start_date_new = mktime( 12, 0, 0, $user_input_start_date['mon'], $user_input_start_date['mday'], $user_input_start_date['year'] );
$end_date_new = mktime( 12, 0, 0, $user_input_end_date['mon'], $user_input_end_date['mday'], $user_input_end_date['year'] );
return round( abs( $start_date_new - $end_date_new ) / 86400 );
Given that a date range starts and ends in 2012 or starts in 2012 and ends in 2013 alone gives me 10 different possibilities of in which season a date range can start and where it can end.
There must be a better solution than iterating if/else and comparing dates over and over again for the following conditions:
Date range is completely within season 1
Date range starts in season 1 and ends in season 2
Date range starts in season 1, spans across season 2 and ends in the second part of season 1
... and so forth with "Starts in season 2", etc
This not a duplicate of How many days until X-Y-Z date? as that only deals with counting the number of days. It does not address the issue of comparing one date range with another.
The key to this problem is to simplify it as much as possible. I think using an array as a lookup table for the cost of each day of the year is the way to go. The first thing to do then, is to generate the array. The array just represents each day of the year and doesn't represent any particular year. I chose to use 2012 to generate the lookup array as it is a leap year and so has every possible day in it.
function getSeasonArray()
{
/**
* I have chosen 2012 as it was a leap year. All we want to do is
* generate an array which has avery day of the year in it.
*/
$startDate = new DateTime('1st January 2012');
//DatePeriod always drops the last day.
$endDate = new DateTime('1st January 2013');
$season2Start = new DateTime('1st April 2012');
$season2End = new DateTime('1st October 2012');
$allDays = new DatePeriod($startDate, new DateInterval('P1D'), $endDate);
$season2Days = new DatePeriod($season2Start, new DateInterval('P1D'), $season2End);
$seasonArray = array();
foreach($allDays as $day){
$seasonArray[] = $day->format('d-M');
$seasonArray[$day->format('d-M')]['season'] = 1;
}
foreach($season2Days as $day){
$seasonArray[$day->format('d-M')]['season'] = 2;
}
return $seasonArray;
}
Once that is done you just need the period over which to calculate:-
$bookingStartDate = new DateTime();//Or wherever you get this from
$bookingEndDate = new DateTime();
$bookingEndDate->setTimestamp(strtotime('+ 7 month'));//Or wherever you get this from
$bookingPeriod = new DatePeriod($bookingStartDate, new DateInterval('P1D'), $bookingEndDate);
Then we can do the calculation:-
$seasons = getSeasonArray();
$totalCost = 0;
foreach($bookingPeriod as $day){
$totalCost += $seasons[$day->format('d-M')]['season'];
var_dump($day->format('d-M') . ' = $' . $seasons[$day->format('d-M')]['season']);
}
var_dump($totalCost);
I have chosen a long booking period, so that you can scan through the var_dump() output and verify the correct price for each day of the year.
This is a quick stab done between distractions at work and I'm sure that with a bit of thought you can mould it into a more elegant solution. I'd like to get rid of the double iteration for example, unfortunately, work pressures prevent me from spending further time on this.
See the PHP DateTime man page for further information on these useful classes.
At first I suggested using the DateTime class that PHP provides, naively assuming that it has some kind of thought-out API that one could use. It turns out that it does not. While it features very basic DateTime functionality, it is mostly unusable because, for most operations, it relies on the DateInterval class. In combination, those classes represent another masterpiece of bad API design.
An interval should be defined like so:
An interval in Joda-Time represents an interval of time from one millisecond instant to another instant. Both instants are fully specified instants in the datetime continuum, complete with time zone.
In PHP, however, an Interval is just a duration:
A date interval stores either a fixed amount of time (in years, months, days, hours etc) or a relative time string [such as "2 days"].
Unfortunately, PHP's DateInterval definition does not allow for intersection/overlap calculation (which the OP needs) because PHP's Intervals have no specific position in the datetime continuum. Therefore, I've implemented a (very rudimentary) class that adheres to JodaTime's definition of an interval. It is not extensively tested, but it should get the work done:
class ProperDateInterval {
private $start = null;
private $end = null;
public function __construct(DateTime $start, DateTime $end) {
$this->start = $start;
$this->end = $end;
}
/**
* Does this time interval overlap the specified time interval.
*/
public function overlaps(ProperDateInterval $other) {
$start = $this->getStart()->getTimestamp();
$end = $this->getEnd()->getTimestamp();
$oStart = $other->getStart()->getTimestamp();
$oEnd = $other->getEnd()->getTimestamp();
return $start < $oEnd && $oStart < $end;
}
/**
* Gets the overlap between this interval and another interval.
*/
public function overlap(ProperDateInterval $other) {
if(!$this->overlaps($other)) {
// I haven't decided what should happen here yet.
// Returning "null" doesn't seem like a good solution.
// Maybe ProperDateInterval::EMPTY?
throw new Exception("No intersection.");
}
$start = $this->getStart()->getTimestamp();
$end = $this->getEnd()->getTimestamp();
$oStart = $other->getStart()->getTimestamp();
$oEnd = $other->getEnd()->getTimestamp();
$overlapStart = NULL;
$overlapEnd = NULL;
if($start === $oStart || $start > $oStart) {
$overlapStart = $this->getStart();
} else {
$overlapStart = $other->getStart();
}
if($end === $oEnd || $end < $oEnd) {
$overlapEnd = $this->getEnd();
} else {
$overlapEnd = $other->getEnd();
}
return new ProperDateInterval($overlapStart, $overlapEnd);
}
/**
* #return long The duration of this interval in seconds.
*/
public function getDuration() {
return $this->getEnd()->getTimestamp() - $this->getStart()->getTimestamp();
}
public function getStart() {
return $this->start;
}
public function getEnd() {
return $this->end;
}
}
It may be used like so:
$seasonStart = DateTime::createFromFormat('j-M-Y', '01-Apr-2012');
$seasonEnd = DateTime::createFromFormat('j-M-Y', '30-Sep-2012');
$userStart = DateTime::createFromFormat('j-M-Y', '01-Jan-2012');
$userEnd = DateTime::createFromFormat('j-M-Y', '02-Apr-2012');
$i1 = new ProperDateInterval($seasonStart, $seasonEnd);
$i2 = new ProperDateInterval($userStart, $userEnd);
$overlap = $i1->overlap($i2);
var_dump($overlap->getDuration());
I have debugged this legacy code, and would like a sanity check on it.
The purpose of it is to allow someone to choose a delivery frequency for shipping a product. If someone wants their product Every Other Week, the system needs to determine if they should get an order next week, or two weeks from now. We call it A week, or B Week.
Keep in mind I did not write this, I am just trying to make sense of it and would like some help evaluating its accuracy:
if (date("l") == "Monday" ) {
$start = 0;
} else if (date("l") == "Tuesday" || date("l") == "Wednesday" || date("l") == "Thursday" || date("l") == "Friday" || date("l") == "Saturday"|| date("l") == "Sunday") {
$start = -1;
}
// if changing to every other week set to next week's a/b-ness
$a_week_tid = 34;
$b_week_tid = 35;
$every_other_week_frequency_id = 32;
if ($delivery_frequency == $every_other_week_frequency_id) {
$julian = (int) (strtotime('Monday +' . $start . ' week') / 86400);
$julian_week = ($julian-4) / 7;
if ($julian_week % 2) {
$today_a_or_b = $b_week_tid;
$next_week_a_or_b = $a_week_tid;
$a_or_b_week_string = '(A Week)';
} else {
$today_a_or_b = $a_week_tid;
$next_week_a_or_b = $b_week_tid;
$a_or_b_week_string = '(B Week)';
}
} else {
$next_week_a_or_b = NULL;
$a_or_b_week_string = NULL;
}
This code is not commented or documented. The part that confuses me is:
Why is 4 subtracted from Julian, then divided by 7?
If today is Monday, $julian_week is 2129, and 2129 % 2 evaluates TRUE. Is that correct?
Is this even how it should be done? Can't I rewrite this using date('w') a lot easier?
Yeah using date would totally be easier, plus it takes into account leap years, daylight saving time, all that extra stuff you don't want to have to deal with.
if (date('W')%2==1)
That's SOOOO much easier to maintain than the above.
I don't believe you can use date("W") in this case. According to the ISO calculation, on occasion, there will be years with 53 weeks. In those years, Week 53 is followed by Week 01, both odd numbers, and an A/B calculation based on Even/Odd ISO week number would result in two successive A or B weeks.
The original calculation determines the number of days from the UNIX epoch of the present Monday, or of the most recent Monday if today is not a Monday. The -4 causes the A/B week labels to change on Thursdays. Even/oddness of a week is determined from a fixed date (the Unix Epoch), so there will be no discontinuity in the oscillation of A/B-ness using the original code.
The ISO standard for week one in a year is that it is the week that the first Thursday of the year falls. This is the reason for the 4 subtracted from the Julian date. The week number is then found by dividing by 7.
Again the ISO standard implies that week number cannot be greater than 53. I don't understand how your figure of 2129 can arise. However the div operator will not evaluate TRUE for this figure. Checking the div operator on the week number is the way of determining whether you are in week a or b. If it is before Thursday, it is quite likely that the number will be 1 less than you anticipate.
The coding looks fairly good to me, though I have not stepped through all of it. It does look correct.
Using W on consecutive Fridays, mod by 2. Both lines output 1. So doing it this way will occasionally fail.
echo date('W',strtotime('2016-01-01'))%2;
echo date('W',strtotime('2016-01-08'))%2;
Just a simple way.
<?php
$weekNumber = date("W");
echo 'Week number:',$weekNumber;
if($weekNumber&1) {
echo '<strong>Week A.</strong>';
} else {
echo '<strong>Week B.</strong>';
}
?>
$day = '2019-11-10';
$date = new DateTime($day);
$dayOfMonth = $date->format("j"); // month days 1 - 30
$weekNumber = ceil($dayOfMonth / 7); // get the week number
if ($weekNumber % 2 == 0) { //if week number is even
echo "Even Week";
} else {
echo "Odd Week";
}
**// output Even Week**