Currently in my file
controller/common/home.php
$this->load->model('catalog/category');
$homepageProductTest = $this->model_catalog_category->homepageProductTest();
And when i echo $homepageProductTest , there is bunch of array.
What i wanted:
How do i pass the variable to my view file (home.tpl)
The error i always get (view/theme/xxx/template/common/home.tpl)
Undefined variable: homepageProductTest
if you want to use any variable in your view file from controller file then you have to pass your value in data variable like below,
like in your case, you want "homepageProductTest"
$data['homepageProductTest'] = $homepageProductTest; //write this code in your controller file
OR
$this->data['homepageProductTest'] = $homepageProductTest; //write this code in your controller
in .tpl file you can use this variable using PHP like,
<?php foreach($homepageProductTest as $producttest){ ?>
//your code here
<?php } ?>
So I have an HTML file that is a basic form. Say
<form method="POST" action="test1.php">
Name: <input type="text" name="name" id="name" />
<input type="submit" value="Submit" />
</form>
Now I have that execute my test1.php file which goes as follows:
<?php
$name = $_POST['name'];
?>
So all it is doing is getting the value from the HTML form. Now I have a second PHP file test2.php that needs to get the value from the first test1.php file $name and output it via an echo statement.
I'm new to PHP and am fine with using one PHP file to output values from an HTML form, but I don't know how to approach a second one.
I'm aware that you can use the include statement to carry over the variables and their values, but it didn't seem to work in my instance. I'm almost positive the issue is that I don't have test2.php actually being executed. And I don't know how to approach that. Any help is appreciated.
EDIT: This is all I want test2.php to do. $name has to be the same value as retrieved from the HTML form in test1.php
<?php
echo $name;
?>
Just use include your file test2.php inside test1.php:
<?php
$name = $_POST['name'];
include('test2.php');
?>
Whenever you include a file using either include() or require(), the file always gets "executed", so maybe there's something else wrong in you code.
EDIT
test1.php:
<?php
$name = $_POST['name'];
include('test2.php');
?>
test2.php:
<?php
echo $name;
?>
I would suggest starting a session in test1, assign the var $name to the session and then picking the session up on test2.
test1.php
session_start();
$name = filter_var($_POST['name'],FILTER_SANITIZE_STRING);
$_SESSION['test1']['name'] = $name;
test2.php
session_start();
$name = $_SESSION['test1']['name'];
Try that.
#bloodyKnuckles, Your assignment was left open ended because there are a number of ways you can accomplish what you're looking to do.
include('test2.php');
Is one option. Another would be
header("Location: test2.php");
exit();
Using the header option, $_SESSION variable would work. If test1.php had any HTML output, you could consider an AJAX call or urlencode() your string.
test1.php
echo 'Click Me';
test2.php
$name = $_GET['name'];
I'm guessing your assignment task was designed to demonstrate various ways to pass values from script to script.
Good Luck
I have a php file where I am using it to setup dynamically generated pages based on the input variables. It starts on and index.html page where the variables are gathered some of which are not simple strings but complex Google Earth objects. On the submit of that page it is posted to another page and you are redirected to the created file. The trouble is coming when I try to use that variable within the php include file that is used to generate the pages.How do i properly get a variable from this form and then pass it through to be able to use it on the new generated page. Here is what I am trying currently.
On the click of this button the variable flyto1view is set.
$("#flyto1").click(function(){
if (!flyto1view){
flyto1view = ge.getView().copyAsLookAt(ge.ALTITUDE_RELATIVE_TO_GROUND);
$("#flyto1view1").val(flyto1view)
}
else {
ge.getView().setAbstractView(flyto1view);
}
});
Then from here I have tried setting the value to an hidden field but Im not sure if that kinda of variable has a value that can be set like that. Whats the best way to get this variable to here after post
<?
if (isset($_POST['submit']) && $_POST['submit']=="Submit" && !empty($_POST['address'])) {//if submit button clicked and name field is not empty
$flyto1view1 = $_POST['flyto1'];
$address = $_POST['address']; //the entered name
$l = $address{0}; // the first letter of the name
// Create the subdirectory:
// this creates the subdirectory, $l, if it does not already exists
// Note: this subdirectory is created in current directory that this php file is in.
if(!file_exists($l))
{
mkdir($l);
}
// End create directory
// Create the file:
$fileName = dirname(__FILE__)."/$address.html"; // names the file $name
$fh = fopen($fileName, 'w') or die("can't open file");
// The html code:
// this will outpout: My name is (address) !
$str = "
<? php include ('template.php') ?>
";
fwrite($fh, $str);
fclose($fh);
// End create file
echo "Congradualations!<br />
The file has been created.
Go to it by clicking here.";
die();
}
// The form:
?>
Firstly. creating files from user input is pretty risky. Maybe this is only an abstract of your code but doing a mkdir from the first letter of the input without checking that the first letter is actually a letter and not a dot, slash, or other character isn't good practice.
Anyway, on to your question. I would probably use $_GET variables to pass to the second file. So in the second file you use <?php $_GET['foo'] ?> and on the first file you do:
echo "Congradualations!<br />
The file has been created.
Go to it by clicking here.";
You could also echo the variable into your template like so:
$str = '
<?php
$var = \'' . $flyto1view1 . '\';
include (\'template.php\')
?>';
How to pass variables from a php file to another while it is not html inputs ,just i have a link refer to the other file and i want to pass variables or values to it
Example:
File1.php
<?php
$name='OdO';
echo "<a href='File2.php'>Go To File2</a>";
?>
File2.php
<?php
echo $name;
?>
Use sessions to store any small value that needs to persist over several requests.
File1.php:
session_start();
$_SESSION['var'] = 'foo';
File2.php:
session_start();
$var = $_SESSION['var']; // $var becomes 'foo'
Try to use sessions. Or you can send a GET parameters.
You can use URLs to pass the value too.
like
index.php?id=1&value=certain
and access it later like
$id = $_GET['id'];
$value = $_GET['value'];
However, POST might be much reliable. Sessions/Cookies and database might be used to make the values globally available.
Here's one (bad) solution, using output buffering:
File 1:
<?php
$name = 'OdO';
echo 'Go To File2';
?>
File 2:
<?php
ob_start();
include 'File1.php';
ob_end_clean();
echo $name;
?>
I have to show a page from my php script based on certain conditions. I have an if condition and am doing an "include" if the condition is satisfied.
if(condition here){
include "myFile.php?id='$someVar'";
}
Now the problem is the server has a file "myFile.php" but I want to make a call to this file with an argument (id) and the value of "id" will change with each call.
Can someone please tell me how to achieve this?
Thanks.
Imagine the include as what it is: A copy & paste of the contents of the included PHP file which will then be interpreted. There is no scope change at all, so you can still access $someVar in the included file directly (even though you might consider a class based structure where you pass $someVar as a parameter or refer to a few global variables).
You could do something like this to achieve the effect you are after:
$_GET['id']=$somevar;
include('myFile.php');
However, it sounds like you are using this include like some kind of function call (you mention calling it repeatedly with different arguments).
In this case, why not turn it into a regular function, included once and called multiple times?
An include is just like a code insertion. You get in your included code the exact same variables you have in your base code. So you can do this in your main file :
<?
if ($condition == true)
{
$id = 12345;
include 'myFile.php';
}
?>
And in "myFile.php" :
<?
echo 'My id is : ' . $id . '!';
?>
This will output :
My id is 12345 !
If you are going to write this include manually in the PHP file - the answer of Daff is perfect.
Anyway, if you need to do what was the initial question, here is a small simple function to achieve that:
<?php
// Include php file from string with GET parameters
function include_get($phpinclude)
{
// find ? if available
$pos_incl = strpos($phpinclude, '?');
if ($pos_incl !== FALSE)
{
// divide the string in two part, before ? and after
// after ? - the query string
$qry_string = substr($phpinclude, $pos_incl+1);
// before ? - the real name of the file to be included
$phpinclude = substr($phpinclude, 0, $pos_incl);
// transform to array with & as divisor
$arr_qstr = explode('&',$qry_string);
// in $arr_qstr you should have a result like this:
// ('id=123', 'active=no', ...)
foreach ($arr_qstr as $param_value) {
// for each element in above array, split to variable name and its value
list($qstr_name, $qstr_value) = explode('=', $param_value);
// $qstr_name will hold the name of the variable we need - 'id', 'active', ...
// $qstr_value - the corresponding value
// $$qstr_name - this construction creates variable variable
// this means from variable $qstr_name = 'id', adding another $ sign in front you will receive variable $id
// the second iteration will give you variable $active and so on
$$qstr_name = $qstr_value;
}
}
// now it's time to include the real php file
// all necessary variables are already defined and will be in the same scope of included file
include($phpinclude);
}
?>
I'm using this variable variable construction very often.
The simplest way to do this is like this
index.php
<?php $active = 'home'; include 'second.php'; ?>
second.php
<?php echo $active; ?>
You can share variables since you are including 2 files by using "include"
In the file you include, wrap the html in a function.
<?php function($myVar) {?>
<div>
<?php echo $myVar; ?>
</div>
<?php } ?>
In the file where you want it to be included, include the file and then call the function with the parameters you want.
I know this has been a while, however, Iam wondering whether the best way to handle this would be to utilize the be session variable(s)
In your myFile.php you'd have
<?php
$MySomeVAR = $_SESSION['SomeVar'];
?>
And in the calling file
<?php
session_start();
$_SESSION['SomeVar'] = $SomeVAR;
include('myFile.php');
echo $MySomeVAR;
?>
Would this circumvent the "suggested" need to Functionize the whole process?
I have ran into this when doing ajax forms where I include multiple field sets. Taking for example an employment application. I start out with one professional reference set and I have a button that says "Add More". This does an ajax call with a $count parameter to include the input set again (name, contact, phone.. etc) This works fine on first page call as I do something like:
<?php
include('references.php');`
?>
User presses a button that makes an ajax call ajax('references.php?count=1'); Then inside the references.php file I have something like:
<?php
$count = isset($_GET['count']) ? $_GET['count'] : 0;
?>
I also have other dynamic includes like this throughout the site that pass parameters. The problem happens when the user presses submit and there is a form error. So now to not duplicate code to include those extra field sets that where dynamically included, i created a function that will setup the include with the appropriate GET params.
<?php
function include_get_params($file) {
$parts = explode('?', $file);
if (isset($parts[1])) {
parse_str($parts[1], $output);
foreach ($output as $key => $value) {
$_GET[$key] = $value;
}
}
include($parts[0]);
}
?>
The function checks for query params, and automatically adds them to the $_GET variable. This has worked pretty good for my use cases.
Here is an example on the form page when called:
<?php
// We check for a total of 12
for ($i=0; $i<12; $i++) {
if (isset($_POST['references_name_'.$i]) && !empty($_POST['references_name_'.$i])) {
include_get_params(DIR .'references.php?count='. $i);
} else {
break;
}
}
?>
Just another example of including GET params dynamically to accommodate certain use cases. Hope this helps. Please note this code isn't in its complete state but this should be enough to get anyone started pretty good for their use case.
You can use $GLOBALS to solve this issue as well.
$myvar = "Hey";
include ("test.php");
echo $GLOBALS["myvar"];
If anyone else is on this question, when using include('somepath.php'); and that file contains a function, the var must be declared there as well. The inclusion of $var=$var; won't always work. Try running these:
one.php:
<?php
$vars = array('stack','exchange','.com');
include('two.php'); /*----- "paste" contents of two.php */
testFunction(); /*----- execute imported function */
?>
two.php:
<?php
function testFunction(){
global $vars; /*----- vars declared inside func! */
echo $vars[0].$vars[1].$vars[2];
}
?>
Try this also
we can have a function inside the included file then we can call the function with parametrs.
our file for include is test.php
<?php
function testWithParams($param1, $param2, $moreParam = ''){
echo $param1;
}
then we can include the file and call the function with our parameters as a variables or directly
index.php
<?php
include('test.php');
$var1 = 'Hi how are you?';
$var2 = [1,2,3,4,5];
testWithParams($var1, $var2);
Your question is not very clear, but if you want to include the php file (add the source of that page to yours), you just have to do following :
if(condition){
$someVar=someValue;
include "myFile.php";
}
As long as the variable is named $someVar in the myFile.php
I was in the same situation and I needed to include a page by sending some parameters... But in reality what I wanted to do is to redirect the page... if is the case for you, the code is:
<?php
header("Location: http://localhost/planner/layout.php?page=dashboard");
exit();
?>