PHP: filename without file extension- best way? - php

Question

I am trying to pull the filename out of a directory without the extension.
I am kludging my way through with the following:
foreach ($allowed_files as $filename) {
$link_filename = substr(basename($filename), 4, strrpos(basename($filename), '.'));
$src_filename = substr($link_filename, 0, strrpos($link_filename) - 4);
echo $src_filename;
}
...But that can't work if the extension string length is more than 3.
I looked around in the PHP docs to no avail.

Answer 1

PHP has a handy pathinfo() function that does the legwork for you here:
foreach ($allowed_files as $filename) {
echo pathinfo($filename, PATHINFO_FILENAME);
}
Example:
$files = array(
'somefile.txt',
'anotherfile.pdf',
'/with/path/hello.properties',
);
foreach ($files as $file) {
$name = pathinfo($file, PATHINFO_FILENAME);
echo "$file => $name\n";
}
Output:
somefile.txt => somefile
anotherfile.pdf => anotherfile
/with/path/hello.properties => hello

Answer 2

try this
function file_extension($filename){
$x = explode('.', $filename);
$ext=end($x);
$filenameSansExt=str_replace('.'.$ext,"",$filename);
return array(
"filename"=>$filenameSansExt,
"extension"=>'.'.$ext,
"extension_undotted"=>$ext
);
}
usage:
$filenames=array("file1.php","file2.inc.php","file3..qwe.e-rt.jpg");
foreach($filenames as $filename){
print_r(file_extension($filename));
echo "\n------\n";
}
output
Array
(
[filename] => file1
[extension] => .php
[extension_undotted] => php
)
------
Array
(
[filename] => file2.inc
[extension] => .php
[extension_undotted] => php
)
------
Array
(
[filename] => file3..qwe.e-rt
[extension] => .jpg
[extension_undotted] => jpg
)
------

Answer 3

list($file) = explode('.', $filename);

Answer 4

Try this:
$noExt = preg_replace("/\\.[^.]*$/", "", $filename);
Edit in response to cletus's comment:
You could change it in one of a few ways:
$noExt = preg_replace("/\\.[^.]*$/", "", basename($filename));
// or
$noExt = preg_replace("/\\.[^.\\\\\\/]*$/", "", $filename);
Yes, PHP needs regex literals...