I am trying to show all of the data in the 'status' column of my table but am having troubles. What am I doing wrong:
<?php
$query1 = "SELECT id, status FROM alerts WHERE customerid='".$_SESSION['customerid']."' ORDER BY id LIMIT $start, $limit ";
$result = mysql_query($query1);
while ($row = mysql_fetch_array($result))
{
echo $row['status'] ;
}
?>
Try this:
$query1 = "SELECT id, `status` FROM alerts WHERE customerid='".$_SESSION['customerid']."' ORDER BY id LIMIT $start, $limit ";
$result = mysql_query($query1) or die(mysql_error());
while ($row = mysql_fetch_array($result))
{
echo $row['status'];
}
Also, make sure that:
$_SESSION['customerid'], $start and $limit are not empty. You can test the constructed query with echo $query1;
Note: Addition of mysql_error() in in the mysql_query will allow you to see if there is an error in the query.
I am trying to show all of the data in
the 'status' column of my table
If you want to show all the rows, your query should be:
$query1 = "SELECT id, `status` FROM alerts ORDER BY id";
But if you want to show for a specific customer, your query should be:
$query1 = "SELECT id, `status` FROM alerts WHERE customerid='".$_SESSION['customerid']."' ORDER BY id";
Related
I have an orders table in mysql and in that for some orders I set particular order status like 'review'.
I want to setup a way if any order placed by a particular customer(first and last name) for whom i have previously set order status as 'review' to display a warning in the list.
$sql = "select * from order where firstname = ".$firstname." AND lastname = ".$lastname." AND order_status = 'review';";
$SQLresult = mysql_query("$sql", $DBcon_MySQL);
while($row = mysql_fetch_array($SQLresult)) {
foreach($row as $row){
$result = "warning!";
echo $result;
}
}
The above code does not display anything. please let me know how to fix this.
[EDIT After Applying Answer]
This is how i am using it.
<td width="200">
<?
$sql = "select * from cust_order where firstname = '$firstname' AND lastname = '$lastname' AND order_status = 'review'";
$SQLResult = mysql_query("$sql", $DBcon_MySQL);
while($row = mysql_fetch_array($SQLResult )) {
//$result;
foreach($row as $row ){
//$result="";
$result = "Warning!";
}
?>
<p><? echo $result;?></p>
<?} ?>
</td>
How should i insert a check that it should display warning only once No matter how many orders from single customer are marked as review, display warning only once?
try this,
$sql = "SELECT
*
FROM
`order`
WHERE
firstname = '$firstname' AND lastname = '$lastname' AND
order_status = 'review' LIMIT 1";
$SQLresult = mysql_query($sql, $DBcon_MySQL);
while($row = mysql_fetch_array($SQLresult)) {
foreach($row as $row){
$result = "warning!";
echo $result;
}
}
Please be informed that mysql functions are deprecated and not recommended. USE MySQLi or PDO instead. have a reference from following queries.
http://php.net/manual/en/book.mysqli.php
http://php.net/manual/en/book.pdo.php
I am trying to display my first 10 users and their information by uid. When I use the code below, it only returns a single uid:
include "db_conx.php";
$sql = ('SELECT uid,username,country FROM users ORDER BY uid DESC LIMIT 10');
$result = mysqli_query($db_conx, $sql);
echo $result->fetch_object()->uid;
What function am I supposed to use to display rows correctly?
include "db_conx.php";
$sql = ('SELECT uid,username,country FROM users ORDER BY uid DESC LIMIT 10');
$result = mysqli_query($db_conx, $sql);
while($var = $result->fetch_object()->uid){
echo $var;
}
Should do the trick
If you get a list of object you should use a loop for show them
include "db_conx.php";
$sql = ('SELECT uid,username,country FROM users ORDER BY uid DESC LIMIT 10');
$result = mysqli_query($db_conx, $sql);
while($row = mysqli_fetch_object($result)) {
$row->uid;
}
I was able to apply this line onto phpMyAdmin and it worked just fine.
SELECT id, date_format(`date`, '%m.%d.%Y') as `date` FROM TABLE ORDER BY date DESC LIMIT 1
The problem is that when I added the rest of the code, the recent date shows up blank on the webpage. Am I missing something in this code?
<?php
$query = "SELECT id, date_format(`date`, '%m.%d.%Y') as `date` FROM TABLE ORDER BY date DESC LIMIT 1";
$result = mysql_query($query);
echo "$date";
?>
Any help is appreciated. Thank you.
. Try this
$query = "SELECT id, date_format(`date`, '%m.%d.%Y') as `date` FROM TABLE ORDER BY. date DESC LIMIT 1";
$result = mysql_query($query);
$r = mysql_fetch_assoc($result);
$date = $r['date'];
echo "$date";
You didn't set $date variable. You need to use mysql_fetch_array function for your $result variable.
Ex:
`
$query = "SELECT id, date_format('date', '%m.%d.%Y') as 'date' FROM TABLE ORDER BY date DESC LIMIT 1";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
print_r($row); }
`
I have a table with a column called 'status'. The defaut value of 'status' is 0. I want to update the value to '1' after using it.
I basically want to check if the status is 0, if it is, do an operation and then change the value to 1.
Here is the code. All works perfectly except that the value of 0 is not changed to 1.
I am a novice so maybe is a very basic mistake :(
<?php
$sql = "SELECT number, status FROM summonerid";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$SummonerID = $row["number"];
$status = $row["status"];
if($status=='0'){
$recentgames=$lol->getRecentGames($SummonerID);
$MatchID1=$recentgames->games[0]->gameId;
$sql = "INSERT INTO matchid (number) SELECT * FROM (SELECT '$MatchID1') AS tmp WHERE NOT EXISTS (SELECT number FROM matchid WHERE number = '$MatchID1') LIMIT 1;";
$sql = "UPDATE summonerid SET status='1' WHERE status='0';"; // THIS IS THE PART THAT DOES NOT WORK WELL
}
}
}
?>
Any help would be highly appreciated
Try this.. you are not executing the sql statements
$sql = "SELECT number, status FROM summonerid";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$SummonerID = $row["number"];
$status = $row["status"];
if($status=='0'){
$recentgames=$lol->getRecentGames($SummonerID);
$MatchID1=$recentgames->games[0]->gameId;
$sql = "INSERT INTO matchid (number) SELECT * FROM (SELECT '$MatchID1') AS tmp WHERE NOT EXISTS (SELECT number FROM matchid WHERE number = '$MatchID1') LIMIT 1;";
$result1 = $conn->query($sql);
$sql = "UPDATE summonerid SET status='1' WHERE status='0';";
$result1 = $conn->query($sql);
}
}
}
?>
I got a table that contains ID, Names, message, and time, I want to select from the table only one message query from each ID, Currently I select all the messages, this is my code
$query= mysql_query("SELECT * FROM `table` ORDER BY `time`")or die(mysql_error());
while($arr = mysql_fetch_array($query)){
$num = mysql_num_rows($query);
$msg = $arr['message'];
echo '</br>';
echo $msg;
}
That Shows all messages ordered by time, Is there is a way to select only one message query from each ID?
Thanks,
Klaus
If you want only one message you can use LIMIT like this
SELECT * FROM table ORDER BY time LIMIT 1
Or if you want only one message from some id then you can use GROUP BY
SELECT * FROM table ORDER BY time GROUP BY id
Sure, pretty straightforward
This will fetch all messages given ID:
$id = 10 //Get your id in any way you need
$query= mysql_query("SELECT `message` FROM `table` WHERE `ID` = $id")or die(mysql_error());
while($arr = mysql_fetch_array($query)){
$num = mysql_num_rows($query);
$msg = $arr['message'];
echo $msg;
}
and this will fetch only the first message given ID
$id = 10
$query= mysql_query("SELECT `message` FROM `table` WHERE `ID` = $id LIMIT 1")or die(mysql_error());
$row = mysql_fetch_array($query));
if($row){
$msg = $row['message'];
echo $msg;
}else{
echo 'no messages for id '.$id;
}