Return sql query as array - php

Question

I'm using jqueryui and its Autocomplete plugin. It use a json to extract items.
I want to modify it so that items will be extracted from my db.
Here is how items should be :
$items = array(
"Great <em>Bittern</em>"=>"Botaurus stellaris",
"Great2 <em>Bittern</em>"=>"Botaurus stellaris 2"
);
How to make an sql query that extract data from a table and write it like the code above into the php file ?
Table : customer
id_customer | name_customer | country_customer
I want that array produce id_customer => name_customer

Answer 1

The query is just:
SELECT id_customer, name_customer FROM customer
and you can generate the array like so (assuming you are using MySQL):
$items = array();
$result = mysql_query($sql);
while(($row = mysql_fetch_assoc($result))) {
$items[$row['id_customer']] = $row['name_customer'];
}
References: MySQL SELECT syntax, mysql_query(), mysql_fetch_assoc()

Answer 2

<?php
//Use mysql_connect for connect to a Db
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
// Select a DB
$db_selected = mysql_select_db('db_name', $link);
if (!$db_selected) {
die ('Can\'t use dbame_n : ' . mysql_error());
}
//Build a query
$sql = "SELECT id_customer, name_customer FROM customer";
//Send de query to db
$result = mysql_query($sql);
if (!$result) {
die('Invalid query: ' . mysql_error());
}
// Initialize Array
$arr_customers = array();
while(($row = mysql_fetch_assoc($result))) {
$arr_customers[$row['id_customer']] = $row['name_customer'];
}
// convert to JSON
$json = json_encode($arr_customers);
// Send to JqueryUI
echo $json;
exit();
?>