I have a picture url like this http://www.address.com/image.jpg
I want do dynamically save this image on my server
How can i achieve this using php
Thanks
You can get it using file_get_contents() and saving it using file_put_contents(). Something like:
$image = file_get_contents('http://www.address.com/image.jpg');
file_put_contents('image.jpg', $image);
You also might want look into cURL to fetch the image; it should perform better than file_get_contents() (unless you compile curl with --with-curlwrappers)
Related
I am trying to migrate some content from one resources into another and need to save some images (several hundred) located at a remote resource.
Suppose I have only the URL to an image:
https://www.example.com/some_image.jpg
And I would like to save it into the filesystem using PHP.
If I were uploading the image, I essentially would do the following:
<input type="file" name="my_image" />
move_uploaded_file($_FILES['my_image']['tmp_name'], '/my_img_directory');
But since I only have the URL, I would imagine something like:
$img = 'https://www.example.com/some_image.jpg';
$file = readfile($img);
move_uploaded_file($file, '/my_img_directory');
Which of course wouldnt work since move_uploaded_file() doesn't take an output buffer as a first argument.
Essentially, I would need to get $img into the $_FILES[] array under this approach. Or may some other approach?
You can use PHP's copy function to copy remote files to a location on your server:
copy("https://example.com/some_image.jpg", "/path/to/file.jpg");
http://php.net/manual/en/function.copy.php
$image = file_get_contents('http://www.url.com/image.jpg');
file_put_contents('/images/image.jpg', $image); //Where to save the image on your server
I am trying to save to disk an image that is served to me via a JSON result. The returned JSON result property that I am interested in is this:
https://i.scdn.co/image/6cd03f58ddf30a1393f06d6469973ba16ac908df
Which is the correct image. The problem is that, while the above URL does display the image, it does not allow me to download it, yet I can download it by right-clicking on it.
What I need to be able to do is, using my PHP code, save it to disk.
I have no issues saving results from other sites that give results that link to a direct image extension (.jpg, .gif or .png). But I have not been able to figure out how to programmatically download the image from the above URL.
Is it possible?
This is the code that I use, which works correctly on results that give a URL that has a correct image extension. The URL returned is loaded into the $largeimg variable.
$input = $largeimg;
$output = 'image.jpg';
file_put_contents($output, file_get_contents($input));
How do I achieve this?
file_get_contents() is able to accept raw URI arguments. Your code works perfectly for me, if modified in the way:
$input = 'https://i.scdn.co/image/6cd03f58ddf30a1393f06d6469973ba16ac908df';
So, file_get_contents() can download the image directly. I think, the problem is your $largeimg variable.
What are some possible ways to save an image or make use of it that is generated from a PHP script. Using save as it does not help though.
This is not an image created by me that's why I want to avoid get_contents.
here is the picture
and here is the url
https://render01.fontshop.com/fonts/font_rend.php?idt=f&id=38005&rbe=fsifr&rt=how+do+I+save+this?&rs=38&w=500&bg=ffffff&fg=000000&tp=0.0
Just write the content of the URL to a file
<?php
file_put_contents("img.png", file_get_contents("http://render01.fontshop.com/fonts/font_rend.php?idt=f&id=38005&rbe=fsifr&rt=how+do+I+save+this?&rs=38&w=500&bg=ffffff&fg=000000&tp=0.0"));
Using file_put_contents() function. If you don't have data in variable and want to readout use file_get_contents()
Since you are not generating the image in your own code, the simplest would be a combo of file_get_contents and file_put_contents:
$url = '...'; // your url here
$data = file_get_conents($url);
file_put_conents('image.png', $data);
In this specific case the render is a PNG image, but if there's a possibility of it being a JPEG or something else then you need to somehow detect that as well. I 'm not giving any suggestions for this because there's not enough info to go by.
You can define a filename in imgpng() or the other functions to tell PHP to store the picture instead of sending it to the calling browser.
I understand you want to save it on the client, with a browser, not on the server.
"Save as" worked fine for me (Firefox 7). In Chrome you'll have to specify the extension of the filename manually. Did not test other browsers, but it should work similarly
You can do this from the terminal using the curl command.
curl -o out.png 'http://render01.fontshop.com/fonts/font_rend.php?idt=f&id=38005&rbe=fsifr&rt=how+do+I+save+this?&rs=38&w=500&bg=ffffff&fg=000000&tp=0.0'
This will save the file as out.png
use imagepng function.
It will return file to browser or save it specified location.
Need to set parameter for function to save image on specified location.
I want be able to upload an image or just paste the URL of an image in order to upload it a sa profile picture for my website users.
the point is i dont wanna store the url but i want to have a copy of that image on my server because if that external image will be lost i dont want to lose it either...
i believe facebook and tumblr etc do so... what the php script or best practice to do that?
thanks!
You can get the contents (bytes) from the image using the PHP function (http://php.net/manual/en/function.file-get-contents.php)
$contents = file_get_contents('http://www.google.com/images/logos/ps_logo2.png');
You can use CURL library as well... Here's an example of how you can downloadImageFromUrl with and save it in a local SaveLocation
function downloadImageFromUrl($imageLinkURL, $saveLocationPath) {
$channel = curl_init();
$curl_setopt($channel, CURLOPT_URL, $imageLinkURL);
$curl_setopt($channel, CURLOPT_POST, 0);
$curl_setopt($channel, CURLOPT_RETURNTRANSFER, 1);
$fileBytes = curl_exec($channel);
curl_close($channel);
$fileWritter = fopen($saveLocationPath, 'w');
fwrite($fileWritter, $fileBytes);
fclose($fileWritter);
}
You can use this as follows:
downloadImageFromUrl("http://www.google.com/images/logos/ps_logo2.png", "/tmp/ps_logo2.png")
You can also get the same name of the image by parsing the URL as well...
I think this is you are looking for: Copy Image from Remote Server Over HTTP
You can use a function called imagecreatefromjpeg or something. It takes a URL path to the image and creates a new image off of that. Have a look at http://php.net/manual/en/function.imagecreatefromjpeg.php
There's different functions for different extensions, though (if you prefer using such). You may need to check for the image extension from the URL and use the appropriate function I suppose.
Handling uploads is covered in this documentation, and if users paste a URL, I'd recommend using file_get_contents to save a copy of the image to your server, and then you can simply store the path to that image, rather than the external image.
I am trying to save PhpThumb output. As what I could find on-line was not sufficient or too complex, I would like to ask if any one knows how to it?
$thumb_src="\"phpThumb/phpThumb.php?src=../apartmentsPhotos/".$num['ref']."/1.JPG&h=119&q=100\"";
echo" '<'img src=".$thumb_src />";
So what I want to do is to save the img src into an Image.
(So far I was creating the thumbnails on the fly but it seems that google and my web server don´t like it too much. Saving the thumbnails will ensure that in no time I will have all my thumbnails in real files and then I will use this function just for new content.)
From phpThumb's FAQ
The best way is to call phpThumb as an object and call RenderToFile() to save the
thumbnail to whatever filename you want. See /demo/phpThumb.demo.object.php for an example. The other way is to use the 'file' parameter (see /docs/phpthumb.readme.txt) but this parameter is deprecated and does not work in phpThumb v1.7.5 and newer.
Once you have generated the URL with this line you posted:
$thumb_src="\"phpThumb/phpThumb.php?src=../apartmentsPhotos/".$num['ref']."/1.JPG&h=119&q=100\"";
Pass it as a $_GET variable to another page, call it serveThumb.php:
if (!isset($_GET['img']))
exit;
header('Content-type: application/pdf');
echo file_get_contents($_GET['img']);
You might have to add your own validation to serveThumb.php. Now you can save the result of serveThumb.php as a JPG.
Alternatively, save the contents of the image as a JPG file.
if (!isset($_GET['img']))
exit;
$img = file_get_contents($_GET['img']);
file_put_contents("myImage.jpg", $img);