Mysql - display multiple rows under one field header - php

Question

Okay, been thrashing around with this for longer than I care to think about!
I am trying to drag event data from mysql so that it displays the Event Name once and several products under that Event Name
For Example:
Event Name
product 1
product 2
product 3
What is currently happening is that the Event Name is displayed above each product, like this
Event Name
product 1
Event Name
product 2
Event Name
product 3
The PHP Code is:
<?php
// Get the search variable from URL
$var = #$_GET['q'] ;
$trimmed = trim($var); //trim whitespace from the stored variable
// rows to return
$limit=10;
// check for an empty string and display a message.
if ($trimmed == "")
{
echo "<p>Please enter a search...</p>";
exit;
}
// check for a search parameter
if (!isset($var))
{
echo "<p>We dont seem to have a search parameter!</p>";
exit;
}
//connect to your database ** EDIT REQUIRED HERE **
mysql_connect("xxxxxxxx","xxxxxxxx","xxxxx"); //(host, username, password)
//specify database ** EDIT REQUIRED HERE **
mysql_select_db("event_db") or die("Unable to select database"); //select which database we're using
// Build SQL Query
$query = "select * from event where event_name like \"%$trimmed%\"
order by event_name"; // EDIT HERE and specify your table and field names for the SQL query
$numresults=mysql_query($query);
$numrows=mysql_num_rows($numresults);
// If we have no results, offer a google search as an alternative
if ($numrows == 0)
{
echo "<h4>Results</h4>";
echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>";
// google
echo "<p><a href=\"http://www.google.com/search?q="
. $trimmed . "\" target=\"_blank\" title=\"Look up
" . $trimmed . " on Google\">Click here</a> to try the
search on google</p>";
}
// next determine if s has been passed to script, if not use 0
if (empty($s)) {
$s=0;
}
// get results
$query .= " limit $s,$limit";
$result = mysql_query($query) or die("Couldn't execute query");
// display what the person searched for
echo "<p>You searched for: "" . $var . ""</p>";
// begin to show results set
echo "Results<br /><br />";
// now you can display the results returned
while ($row= mysql_fetch_array($result)) {
$title = $row["event_name"] . "<br />";
$title2 = $row["location"] . " - " . $row["style_name"] . "<br />";
echo "<b>$title</b>";
echo "$count $title2";
}
$currPage = (($s/$limit) + 1);
//break before paging
echo "<br />";
// next we need to do the links to other results
if ($s>=1) { // bypass PREV link if s is 0
$prevs=($s-$limit);
print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><<
Prev 10</a>&nbsp ";
}
// calculate number of pages needing links
$pages=intval($numrows/$limit);
// $pages now contains int of pages needed unless there is a remainder from division
if ($numrows%$limit) {
// has remainder so add one page
$pages++;
}
// check to see if last page
if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {
// not last page so give NEXT link
$news=$s+$limit;
echo " Next 10 >>";
}
$a = $s + ($limit) ;
if ($a > $numrows) { $a = $numrows ; }
$b = $s + 1 ;
echo "<p>Showing results $b to $a of $numrows</p>";
?>
Any thoughts would be greatly received.

Answer 1

simply use group_concat -> group_concat query performance
details -> http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html#function_group-concat
newbie including myself, please try google before posting the question

Answer 2

// now you can display the results returned
while ($row= mysql_fetch_array($result)) {
if($row["event_name"] != $lasteventname){
$title = $row["event_name"] . "<br />";
$lasteventname = $row["event_name"];
echo "<b>$title</b>";
}
$title2 = $row["location"] . " - " . $row["style_name"] . "<br />";
echo "$count $title2";
}