I'm starting with this small PHP and mysql script. How would i make it show the tasks by the taskupdated column?
$query = "SELECT * FROM tasks2 where owner=72";
$result = mysql_query($query);
while ($row = mysql_fetch_assoc($result)) {
echo $row['ownername'];
echo ' - ';
echo $row['tasktitle'];
echo '<br/>';
echo $row['taskdetails'];
echo '<hr/>';
}
<?php
$query = "SELECT * FROM tasks2 WHERE owner=72 ORDER BY taskupdated";
$result = mysql_query($query);
while ($row = mysql_fetch_assoc($result)) {
echo $row['ownername'];
echo ' - ';
echo $row['tasktitle'];
echo '<br />';
echo $row['taskdetails'];
echo '<hr />';
}
?>
If you want to sort them the other way, use ORDER BY taskupdated DESC instead.
SELECT * FROM tasks2 where owner=72 ORDER BY taskupdated
Related
This is the small minor project from college. It ranks the students as per the no of votes. It does rank the student in the pagination but when the student profile is clicked the rank is not shown.
Ok so the below code works but the last part of the code does not display the rank in the output. how can I $num in both codes?
HOME
<br><br>
<form>
<input type="text" name="id" autocomplete="off" placeholder="enter student id">
</form>
<br><br>
<?php include 'conn.php'; ?>
<?php
$sql = "SELECT * FROM table";
$result = mysqli_query($conn, $sql);
$result_per_page = 5;
$no_of_result = mysqli_num_rows($result);
$no_of_page = ceil($no_of_result/$result_per_page);
if(!isset($_GET['page'])){
$page = 1;
}else{
$page = $_GET['page'];
}
$page_first = ($page-1)*$result_per_page;
$sql = 'SELECT * FROM table ORDER BY votes DESC LIMIT ' . $page_first . ',' . $result_per_page;
$result = mysqli_query($conn, $sql);
$num = $page * $result_per_page -4;
while($row = mysqli_fetch_assoc($result)) {
echo '<div class="x">';
echo '#';
echo $num++;
echo ' ';
echo '<a href="?id='.$row['id'].'">';
echo $row['name'];
echo '</a>';
echo '</div>';
}
echo '<br>';
for($page=1;$page<=$no_of_page;$page++){
echo ''.$page.'';
echo ' ';
}
echo '<br>';
?>
<?php
$name = $_GET['id'];
$sql = "SELECT * FROM table WHERE id=$name";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
echo '<br>';
echo 'RANK = ';
echo '?';//display rank here?
echo '<br>';
echo 'NAME = ';
echo $row['name'];
echo '<br>';
echo 'VOTES = ';
echo $row['votes'];
echo '<br>';
}
} else {
//echo "0 results";
}
?>
The output of the above code.. I want to output the rank in the place of question mark.
current output
i want something like this
desired output
I'm pretty new at PHP/MySQL, so please be patient with me.
I am trying to get a list of members in a table to show up on a page. Right now it's showing the first member about 10 times and not displaying anyone else's name. I DID have it working, but I don't know what happened. I just want it to display everyone's name once. Here is my code:
<?php $select = mysql_query("SELECT * FROM `member_staff` WHERE `username`='$_SESSION[USR_LOGIN]' AND `status`='Active'");
$row = mysql_fetch_array($select);
$rows = mysql_num_rows($select);
$teaching = $row[teaching];
if ($rows==0){echo "Sorry, you don't appear to be a professor.";}
else { ?>
<?php }
$select2 = mysql_query("SELECT * FROM `classes_enrolled` WHERE `course`='" . $teaching . "' ORDER BY `student_name`") or die(mysql_error());
$count = mysql_num_rows($select2);
$row2 = mysql_fetch_array($select2);
$student=$row2[student_name];
if($count==NULL) {
echo "<table width=\"80%\">\n";
echo "<tr><td><center>Nobody has registered for your class yet!</center></td></tr>\n";
echo "</table>\n";
echo "<br /><br />\n\n";
}
else {
echo "<center><font size=\"3\"><b>YEAR 1, TERM 2</b></font></center>";
echo "<table width=\"80%\" class=\"table-stripes\">\n";
echo "<tr><td width=\"50%\"><b>STUDENT</b></td></tr>\n";
$select3 = mysql_query("SELECT * FROM `members` WHERE `username`='" . $student . "'") or die(mysql_error());
$row3 = mysql_fetch_array($select3);
while($row2 = mysql_fetch_array($select2)) {
$house=$row3[house];
echo "<tr><td><strong class=\"$house\">$student</strong></td></tr>";
}
echo "</table>"; }
?>
I miss look on your code, since it is mess, but disregard the mysqli and mysql thing, you want to show how many student in the teacher's classes.
<?php $select = mysql_query("SELECT * FROM `member_staff` WHERE `username`='$_SESSION[USR_LOGIN]' AND `status`='Active'");
$row = mysql_fetch_array($select);
$rows = mysql_num_rows($select);
$teaching = $row[teaching]; <--- This only get first row of the course, if you want multiple course under same username, you need to loop it.
if ($rows==0){echo "Sorry, you don't appear to be a professor.";}
else { ?>
<?php }
$select2 = mysql_query("SELECT * FROM `classes_enrolled` WHERE `course`='" . $teaching . "' ORDER BY `student_name`") or die(mysql_error());
$count = mysql_num_rows($select2);
$row2 = mysql_fetch_array($select2);
$student=$row2[student_name]; <----- This only get the first row of the student name, if you want multiple student under a course, you need to loop it.
if($count==NULL) {
echo "<table width=\"80%\">\n";
echo "<tr><td><center>Nobody has registered for your class yet!</center></td></tr>\n";
echo "</table>\n";
echo "<br /><br />\n\n";
}
else {
echo "<center><font size=\"3\"><b>YEAR 1, TERM 2</b></font></center>";
echo "<table width=\"80%\" class=\"table-stripes\">\n";
echo "<tr><td width=\"50%\"><b>STUDENT</b></td></tr>\n";
$select3 = mysql_query("SELECT * FROM `members` WHERE `username`='" . $student . "'") or die(mysql_error());
$row3 = mysql_fetch_array($select3);
while($row2 = mysql_fetch_array($select2)) {
$house=$row3[house]; <----This only show the first row of $house under same student, so you need to loop it too.
echo "<tr><td><strong class=\"$house\">$student</strong></td></tr>";
}
echo "</table>"; }
?>
So what you really want to do is
<?php
$select = mysql_query("SELECT * FROM `member_staff` WHERE `username`='$_SESSION[USR_LOGIN]' AND `status`='Active'");
$rows = mysql_num_rows($select);
if ($rows==0){echo "Sorry, you don't appear to be a professor.";}
else { ?>
<?php }
while( $row = mysqli_fetch_array( $select ) ) {
$teaching = $row[teaching];
$select2 = mysql_query("SELECT * FROM `classes_enrolled` WHERE `course`='" . $teaching . "' ORDER BY `student_name`") or die(mysql_error());
$count = mysql_num_rows($select2);
if($count==NULL) {
echo "<table width=\"80%\">\n";
echo "<tr><td><center>Nobody has registered for your class yet!</center></td></tr>\n";
echo "</table>\n";
echo "<br /><br />\n\n";
} else {
while( $row2 = mysql_fetch_array($select2) ) {
$student=$row2[student_name];
echo "<center><font size=\"3\"><b>YEAR 1, TERM 2</b></font></center>";
echo "<table width=\"80%\" class=\"table-stripes\">\n";
echo "<tr><td width=\"50%\"><b>STUDENT</b></td></tr>\n";
$select3 = mysql_query("SELECT * FROM `members` WHERE `username`='" . $student . "'") or die(mysql_error());
while($row3 = mysql_fetch_array($select3)) {
$house=$row3[house];
echo "<tr><td><strong class=\"$house\">$student</strong></td></tr>";
}
echo "</table>";
}
} // END ELSE
}
} // END ELSE
?>
Using php, I am trying to link results from 3 tables that are connected by a same value. I would then like each dynamic set of related results to repeat as a while loop on the page. This is the result I would like:
artist->
series1->piece1, piece2
series2->piece3, piece4
Artists and series tables share a matched column named 'artist'. Series and piece table have a matched column name 'series'. I know these tables are linked through this same matched value in the database as on another page cascade delete is working.
Currently it only shows the series as an echo repeat loop but with no artist or piece related on either side. Like so: http://www.exhibitjewellery.com/artistindex.php
Whether a mysql_fetch_assoc is the right way, I am not sure. I am confused as to whether the tables are linking correctly at all or if the problem is how I have divided the body section for formatting. I have a feeling a multidimensional array may help or even nesting the tables but I haven't quite grasped how all the details combine throughout each section of the code. Please help!
PHP above the head:
<?php
mysql_select_db($database_connectmysql, $connectmysql);
$query_artistrecordset = "SELECT * FROM artists ORDER BY artist ASC";
$artistrecordset = mysql_query($query_artistrecordset, $connectmysql) or die(mysql_error());
$row_artistrecordset = mysql_fetch_assoc($artistrecordset);
$totalRows_artistrecordset = mysql_num_rows($artistrecordset);
mysql_select_db($database_connectmysql, $connectmysql);
$query_seriesrecordset = "SELECT * FROM series, artists WHERE series.artist=artists.artist ORDER BY exhibition ASC";
$seriesrecordset = mysql_query($query_seriesrecordset, $connectmysql) or die(mysql_error());
$resultseries = mysql_query($query_seriesrecordset);
$row_seriesrecordset = mysql_fetch_assoc($resultseries);
$totalRows_seriesrecordset = mysql_num_rows($seriesrecordset);
mysql_select_db($database_connectmysql, $connectmysql);
$query_piecerecordset = "SELECT * FROM pieces,series WHERE pieces.piece=series.series ORDER BY piece ASC";
$piecerecordset = mysql_query($query_piecerecordset, $connectmysql) or die(mysql_error());
$resultpiece = mysql_query($query_piecerecordset);
$row_piecerecordset = mysql_fetch_assoc($resultpiece);
$totalRows_piecerecordset = mysql_num_rows($piecerecordset);
?>
This is how I have tried to echo it in the body:
<div id="serieslist" align="right">
<?php echo $row_artistrecordset['artist']; ?><br />
<?php echo $row_artistrecordset['website']; ?><br />
<?php echo $row_artistrecordset['artist_statement']; ?><br />
<?php do { ?>
<?php echo $row_seriesrecordset['series']; ?><br />
<?php echo $row_seriesrecordset['exhibition']; ?><br />
<?php echo $row_seriesrecordset['series_statement']; ?><br />
<?php do { ?>
<?php echo $row_piecerecordset['piece']; ?><br />
<?php echo $row_piecerecordset['description']; ?><br />
<?php echo $row_piecerecordset['category']; ?><br />
<?php echo $row_piecerecordset['dimensions']; ?><br />
<?php echo $row_piecerecordset['price']; ?><br />
add to collection button<br />
<?php } while ($row_piecerecordset = mysql_fetch_assoc($resultpiece)); ?>
<?php } while ($row_seriesrecordset = mysql_fetch_assoc($resultseries)); ?>
</div>
</body>
</html>
<?php
mysql_free_result($artistrecordset);
mysql_free_result($seriesrecordset);
mysql_free_result($piecerecordset);
?>
Any help would be greatly appreciated as I have been working on this for days!
Working from your code, here's a version converted to mysqli, with some of the redundant lines removed. I haven't been able to test this, so a little debugging might be required.
<?php
$connectmysql = mysqli_connect("dbhost","dbuser","dbname","dbname") or die("Database error:".mysqli_connect_error);
$query_artistrecordset = "SELECT * FROM artists ORDER BY artist ASC";
$artistrecordset = mysqli_query($connectmysql, $query_artistrecordset) or die(mysqli_error);
$query_seriesrecordset = "SELECT * FROM series, artists WHERE series.artist=artists.artist ORDER BY exhibition ASC";
$seriesrecordset = mysqli_query($connectmysql, $query_seriesrecordset ) or die(mysqli_error);
$query_piecerecordset = "SELECT * FROM pieces,series WHERE pieces.piece=series.series ORDER BY piece ASC";
$piecerecordset = mysqli_query($connectmysql, $query_piecerecordset) or die(mysqli_error);
echo "<div id="serieslist" align="right">"
while ($row_artistrecordset = mysqli_fetch_assoc($artistrecordset)) {
echo $row_artistrecordset['artist'],"<br>";
echo $row_artistrecordset['website'],"<br>";
echo $row_artistrecordset['artist_statement'],"<br>";
while ($row_seriesrecordset = mysqli_fetch_assoc($seriesrecordset)) {
echo $row_seriesrecordset['series'],"<br>";
echo $row_seriesrecordset['exhibition'],"<br>";
echo $row_seriesrecordset['series_statement'],"<br>";
while ($row_piecerecordset = mysqli_fetch_assoc($piecerecordset)) {
echo $row_piecerecordset['piece'],"<br>";
echo $row_piecerecordset['description'],"<br>";
echo $row_piecerecordset['category'],"<br>";
echo $row_piecerecordset['dimensions'],"<br>";
echo $row_piecerecordset['price'],"<br>";
echo "add to collection button<br />";
} // end of pieces
} // end of series
} //end of artists
mysqli_free_result($artistrecordset);
mysqli_free_result($seriesrecordset);
mysqli_free_result($piecerecordset);
echo "</div>";
?>
</body>
</html>
Firs I recommend you use object oriented PHP. Keep this on a separate, secure page called db.php, or something:
//db.php
<?php
function db(){
return new mysqli('replaceWithHostName', 'relaceWithUserName', 'replaceWithPassWord', 'replaceWithDatebaseName');
}
?>
Now for your other page:
//other.php
<?php
include('db.php'); $db = db(); $nr = 'No Results Were Found'; $od = '<div>'; $cd = '</div>'; $br = '<br />'; $ar = $sr = $pr = '';
$artistrecordset = $db->query('SELECT * FROM artists ORDER BY artist ASC');
if(!$artistrecordset)die($db->error);
if($artistrecordset->num_rows > 0){
while($row_ar = $artistrecordset->fetch_assoc()){
$ar .= $od.$row_ar['artist'].$br.$row_ar['website'].$br.$row_ar['artist_statement'].$cd;
}
$artistrecordset->free();
}
else){
die($nr);
}
$seriesrecordset = $db->query('SELECT * FROM series, artists WHERE series.artist=artists.artist ORDER BY exhibition ASC');
if(!$seriesrecordset)die($db->error);
if($seriesrecordset->num_rows > 0){
while($row_sr = $seriesrecordset->fetch_assoc()){
$sr .= $od.$row_sr['series'].$br.$row_sr['exhibition'].$br.$row_sr['series_statement'].$cd;
}
$seriesrecordset->free();
}
else){
die($nr);
}
$piecerecordset = $db->query('SELECT * FROM pieces,series WHERE pieces.piece=series.series ORDER BY piece ASC');
if(!$piecerecordset)die($db->error);
if($piecerecordset->num_rows > 0){
while($row_pr = $piecerecordset->fetch_assoc()){
$pr .= $od.$row_pr['piece'].$br.$row_pr['description'].$br.$row_pr['category'].$br.$row_pr['dimensions'].$br.$row_pr['price'].$cd;
}
$piecerecordset->free();
}
else){
die($nr);
}
$db->close();
$head = '<html><head></head><body>'; //this could be your other info
echo "$head<div id='serieslist' align='right'>$ar$sr$pr$cd".
"<script type='text/javascript'>/*you should put your JavaScript here*/</script>".
'</body></html>';
?>
Really, you should use an external src for your JavaScript so it's cached. Sorry, if the format is hard to read. Use the scrollbars.
You missed to write while loop for $row_artistrecordset as you did also for others, see your code there are only two loops.
First try this query in something like phpMyAdmin to see if it gets the result you want.
SELECT *
FROM artists a
JOIN series s ON s.artist = a.artist
JOIN pieces p ON p.series = s.series
ORDER BY a.artist;
Then process the single result like this.
mysql_select_db($database_connectmysql, $connectmysql);
$q = "SELECT * FROM artists a
JOIN series s ON s.artist = a.artist
JOIN pieces p ON p.series = s.series
ORDER BY a.artist";
$result = mysql_query($q, $connectmysql) or die(mysql_error());
foreach ( $row = mysql_fetch_assoc($result) ) {
echo $row['artist'] . '<br />';
echo $row['website'] . '<br />';
echo $row['artist_statement'] . '<br />';
echo $row['series'] . '<br />';
echo $row['exhibition'] . '<br />';
echo $row['series_statement'] . '<br />';
echo $row['piece'] . '<br />';
echo $row['description'] . '<br />';
echo $row['category'] . '<br />';
echo $row['dimensions'] . '<br />';
echo $row['price'] . '<br />';
echo ' add to collection button<br />';
}
Ok you should also use mysqli or PDO as the mysql extension is now deprecated, but without changing everything and its not a like for like just add a i conversion, you could try this as an interim solution.
We have a basic PHP script to extract the title and description for each job from a MySQL database as simply display this information. This is what it looks like:
$sql = "SELECT `title`, `desc` FROM jobs WHERE active = 'y'";
$query = mysql_query($sql) or die('<em><strong>SQL Error:</strong> ' . mysql_error() . '</em>');
$results = mysql_fetch_assoc($query);
<?php while($result = mysql_fetch_assoc($query)) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$results['title']}</h2>";
echo "<p>{$results['desc']}</p>";
echo '</div>';
} ?>
Now, this only extracts one row from the database, but it should extract two. So, I tried the following to replace the while statement:
<?php foreach($results as $result) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$result['title']}</h2>";
echo "<p>{$result['desc']}</p>";
echo '</div>';
} ?>
This statement doesn't work either. This just displays (weirdly) the first character of each column in the first row in the table.
Does anyone have any idea as to why this isn't working as it should?
In your while use same variable $result as you started:
while($result = mysql_fetch_assoc($query)) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$result['title']}</h2>";
echo "<p>{$result['desc']}</p>";
echo '</div>';
}
and remove the first $results = mysql_fetch_assoc($query);
Result variable you have used is result not results
Replace
$sql = "SELECT `title`, `desc` FROM jobs WHERE active = 'y'";
$query = mysql_query($sql) or die('<em><strong>SQL Error:</strong> ' . mysql_error() . '</em>');
**$results = mysql_fetch_assoc($query);** // remove this line
<?php while($result = mysql_fetch_assoc($query)) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$results['title']}</h2>";
echo "<p>{$results['desc']}</p>";
echo '</div>';
} ?>
to
$sql = "SELECT `title`, `desc` FROM jobs WHERE active = 'y'";
$query = mysql_query($sql) or die('<em><strong>SQL Error:</strong> ' . mysql_error() . '</em>');
<?php while($result = mysql_fetch_assoc($query)) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$result['title']}</h2>";
echo "<p>{$result['desc']}</p>";
echo '</div>';
} ?>
You already fetched the first row before your loop started, which is why it only prints the second row. Simply comment out that line:
#$results = mysql_fetch_assoc($query); # here is your first row,
# simply comment this line
<?php while($result = mysql_fetch_assoc($query)) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$result['title']}</h2>";
echo "<p>{$result['desc']}</p>";
echo '</div>';
} ?>
You are also looping over $result but using $results in your while loop body.
Check this:
$sql = "SELECT `title`, `desc` FROM jobs WHERE active = 'y'";
$query = mysql_query($sql) or die('<em><strong>SQL Error:</strong> ' . mysql_error() . '</em>');
<?php
while($result = mysql_fetch_assoc($query)) {
echo '<div class="left_content" style="margin-top: 15px;">';
echo "<h2>{$result['title']}</h2>";
echo "<p>{$result['desc']}</p>";
echo '</div>';
}
?>
Change this line
<?php while($result = mysql_fetch_assoc($query)) {
to
<?php while($results = mysql_fetch_assoc($query)) {
I just can't figure out why i get the error message, I have tried removing the'' and the()
I have run the script in phpmyadmin and it says the problem with my syntax is at $result = ("SELECT * FROM 'test_prefixCatagory' ORDER by 'Cat'");
$result = ("SELECT * FROM 'test_prefixCatagory' ORDER by 'Cat'");
while($row = mysql_fetch_array($result))
$sCat = ($row['Cat']);
$sCatID = ($row['CatID']);
{
echo "<table>";
echo "<tr valign='top'><td><b><a href='#".$sCat."'>".$sCat."</a></b><br>";
// column 1 categories
$result2 = ("SELECT * FROM `test_prefixSubCat` WHERE `CatID`=$sCatID");
// sub-cats
while($row2 = mysql_fetch_array($result2))
{
$sSub = ($row2['CatID']);
$sSubID = ($row2['SubID']);
echo "<dd><a href='#'>".$sSub."</a><br>";
}
echo "<br></td></tr>";
echo "</table>";
}
Do anyone have an idea?
Try this :
<?php
$result = mysql_query("SELECT * FROM `test_prefixCatagory ORDER by `Cat`");
while ($row = mysql_fetch_array($result)) {
$sCat = $row['Cat'];
$sCatID = $row['CatID'];
echo "<table>";
echo "<tr valign='top'><td><b><a href='#" . $sCat . "'>" . $sCat . "</a></b><br>";
// column 1 categories
$result2 = mysql_query("SELECT * FROM `test_prefixSubCat` WHERE `CatID`='".$sCatID. "'");
// sub-cats
while ($row2 = mysql_fetch_array($result2)) {
$sSub = $row2['CatID'];
$sSubID = $row2['SubID'];
echo "<dd><a href='#'>" . $sSub . "</a><br>";
}
echo "<br></td></tr>";
echo "</table>";
}
?>
$result = ("SELECT * FROM `test_prefixCatagory` ORDER by `Cat`");
Not only do you need to add mysql_query but you also need to remove the single quotes from the table name and field name. You can use backticks if you wish but not single quotes around table names.
$result = mysql_query("SELECT * FROM `test_prefixCatagory` ORDER by `Cat`");
// other query:
$result2 = mysql_query("SELECT * FROM `test_prefixSubCat` WHERE `CatID`=$sCatID");
When debugging MySQL problems, use mysql_error() to see a description of the problem.