dynamic xml using php - php

Question

i have an xml file. how to make dynamic xml?
<?xml version="1.0" encoding="ISO-8859-1"?>
<jukebox>
<song title="When the Levee Breaks" artist="Kansas Joe and Memphis Minnie" url="songs/levee.mp3" />
<song title="Better Leave that Stuff Alone" artist="Will Shade" url="songs/alone.mp3" />
<song title="Walk Right In" artist="Cannon's Jug Stompers" url="songs/walk.mp3" />
</jukebox>
here i have to fetch files from database. how it is possible?

Answer 1

I quite don't understand if you want to pull out those information from MySQL to XML or XML to HTML...
In the first case, we'll need more informations like :
Your MySQL schema
How do you extract info from there now
What did you try so far
In the second case, you can use that code :
<?php
$xml = '<?xml version="1.0" encoding="ISO-8859-1"?>
<jukebox>
<song title="When the Levee Breaks" artist="Kansas Joe and Memphis Minnie" url="songs/levee.mp3" />
<song title="Better Leave that Stuff Alone" artist="Will Shade" url="songs/alone.mp3" />
<song title="Walk Right In" artist="Cannon\'s Jug Stompers" url="songs/walk.mp3" />
</jukebox>';
$doc = new DOMDocument;
$doc->loadXML($xml);
$songs = $doc->getElementsByTagName('song');
foreach($songs as $song){
echo ''.$song->getAttribute('title').' by '.$song->getAttribute('artist').'';
}
DEMO HERE

Answer 2

It would depend on a number of other factors you haven't elaborated on, however given you intend on generating the file with PHP, and you've sorted out your database logic, something like this would work:
<?php foreach($songs as $song): ?>
<song title="<?php echo $song['title']; ?>"
artist="<?php echo $song['artist']; ?>"
url="<?php echo $song['url']; ?>" />
<?php endforeach; ?>
More details are really necessary to give you any more of answer though. For example, language?