Need Help With Implementing Simple Stuff with PHP and MYSQL - php

Question

Here is my code -
<?php
$u = $_SESSION['username'];
while($fetchy = mysqli_fetch_array($allusers))
{
mysqli_select_db($connect,"button");
$select = "select * from button where sessionusername='$u' AND response = 'approve'";
$query = mysqli_query($connect,$select) or die('Oops, Could not connect');
$result= mysqli_fetch_array($query);
$email = mysqli_real_escape_string($connect,trim($result['onuser']));
echo $email;
if($email){
mysqli_select_db($connect,"users");
$select_name = "select name, icon from profile where email = '$email'";
$query_2 = mysqli_query($connect,$select_name) or die('Oops, Could not connect. Sorry.');
$results= mysqli_fetch_array($query_2);
$name = mysqli_real_escape_string($connect,trim($results['name']));
$icon = mysqli_real_escape_string($connect,trim($results['icon']));
echo $name;
}
}
NOw, there are two reponses in db. So, two names are getting echoed, but they both are SAME. Why so? Eg
DB - NAMEs - Apple and Orange.
Displayed - Apple Apple.
Database example -
SESSIONUSERNAME OnUSer
s#s.com apple
s#s.com orange
EDITED
Using #endophage's method -
AppleOrange and AppleOrange.

Answer 1

As your loop stands now, $u will always be the same, so $select will always have the same value, and so will $email, and so will $select_name, so it is no surprise that the same record keeps coming back.
Edit
If the $select_name query returns multiple results, then you need to loop through the results with a while loop like the other queries.

Answer 2

Try this, you had your while loop in the wrong place:
<?php
$u = $_SESSION['username'];
mysqli_select_db($connect,"button");
$select = "select * from button where sessionusername='$u' AND response = 'approve'";
$query = mysqli_query($connect,$select) or die('Oops, Could not connect');
while($result = mysqli_fetch_array($query))
{
$email = mysqli_real_escape_string($connect,trim($result['onuser']));
echo $email;
if($email){
mysqli_select_db($connect,"users");
$select_name = "select name, icon from profile where email = '$email'";
$query_2 = mysqli_query($connect,$select_name) or die('Oops, Could not connect. Sorry.');
$results= mysqli_fetch_array($query_2);
$name = mysqli_real_escape_string($connect,trim($results['name']));
$icon = mysqli_real_escape_string($connect,trim($results['icon']));
echo $name;
}
}