I have some XML to which I need to add a child.
Using SimpleXML, I'm not having any issue adding a simple node.
The beginning XML looks a bit like this:
<root>
<item>
<title>This is the title</title>
<sort>2</sort>
</item>
<item>
<title>This is another title</title>
<sort>3</sort>
</item>
</root>
I need to add a node that looks like this:
<label id=1>
<title type=normal>This is a label</title>
<sort>1</sort>
</label>
The result would be:
<root>
<item>
<title>This is the title</title>
<sort>2</sort>
</item>
<item>
<title>This is another title</title>
<sort>3</sort>
</item>
<label id=1>
<title type=normal>This is a label</title>
<sort>1</sort>
</label>
</root>
I'm able to add a simple child using:
$xml->root->addChild('label', 'This is a label');
I am having trouble getting the attributes and children added to this newly added node though.
I am not worried about appending versus prepending as the sorting happens in XSLT.
addChild returns the added child, so you just have to do :
$label = $xml->root->addChild('label');
$label->addAttribute('id', 1);
$title = $label->addChild('title', 'This is a label');
$title->addAttribute('type', 'normal');
$label->addChild('sort', 1);
$xml->root->addChild('label', 'This is a label');
This opereration returns a reference to the child that was just added. So you could do this:
$child = $xml->root->addChild('label', 'This is a label');
From this, you can not add your additional children and attributes to that child.
$child->addAttributes('id', '1');
Since it returns a reference, that node and attributes that were just added are part of the $xml object as well.
Related
I load the following XML data into SimpleXML like this:
<?php
$xmlString = <<<'XML'
<?xml version="1.0"?>
<response>
<item key="0">
<title>AH 2308</title>
<field_a>3.00</field_a>
<field_b>7.00</field_b>
<field_d1>35.00</field_d1>
<field_d2>40.00</field_d2>
<field_e></field_e>
<field_g2></field_g2>
<field_g>M 45x1,5</field_g>
<field_gewicht>0.13</field_gewicht>
<field_gtin>4055953012781</field_gtin>
<field_l>40.00</field_l>
<field_t></field_t>
<field_abdrueckmutter>KM 9</field_abdrueckmutter>
<field_sicherung>MB 7</field_sicherung>
<field_wellenmutter>KM 7</field_wellenmutter>
</item>
<item key="1">
<title></title>
<field_a></field_a>
<field_b></field_b>
<field_d1></field_d1>
<field_d2></field_d2>
<field_e></field_e>
<field_g2></field_g2>
<field_g></field_g>
<field_gewicht></field_gewicht>
<field_gtin></field_gtin>
<field_l></field_l>
<field_t></field_t>
<field_abdrueckmutter></field_abdrueckmutter>
<field_sicherung></field_sicherung>
<field_wellenmutter></field_wellenmutter>
</item>
</response>
XML;
$xml = simplexml_load_string($xml);
How can I achieve the following result:
<?xml version="1.0"?>
<response>
<item key="0">
<title>AH 2308</title>
<field_a>3.00</field_a>
<field_b>7.00</field_b>
<field_d1>35.00</field_d1>
<field_d2>40.00</field_d2>
<field_e></field_e>
<field_g2></field_g2>
<field_g>M 45x1,5</field_g>
<field_gewicht>0.13</field_gewicht>
<field_gtin>4055953012781</field_gtin>
<field_l>40.00</field_l>
<field_t></field_t>
<field_abdrueckmutter>KM 9</field_abdrueckmutter>
<field_sicherung>MB 7</field_sicherung>
<field_wellenmutter>KM 7</field_wellenmutter>
</item>
<item key="1"></item>
</response>
To delete all empty elements, I could use the following working code:
foreach ($xml->xpath('/child::*//*[not(*) and not(text()[normalize-space()])]') as $emptyElement) {
unset($emptyElement[0]);
}
But that's not exactly what I want.
Basically, when the <title> element is empty, I want to remove it with all its siblings and keep the parent <item> element.
What's important: I also want to keep empty element, if the <title> is not empty. See <item key="0"> for example. The elements <field_e>, <field_g2> and <field_t>will be left untouched.
Is there an easy xpath query which can achieve that? Hope anyone can help. Thanks in advance!
This xpath query is working:
foreach ($xml->xpath('//title[not(text()[normalize-space()])]/following-sibling::*') as $emptyElement) {
unset($emptyElement[0]);
}
It keeps the <title> element but I can live with that.
DOM is more flexible manipulating nodes:
$document = new DOMDocument();
$document->loadXML($xmlString);
$xpath = new DOMXpath($document);
$expression = '/response/item[not(title[normalize-space()])]';
foreach ($xpath->evaluate($expression) as $emptyItem) {
// replace children with an empty text node
$emptyItem->textContent = '';
}
echo $document->saveXML();
I've been trying to merge two XML files I use to build my menubar in my web application for hours, but I can't get it to work.
I have my main XML file which looks like this:
<?xml version="1.0" encoding="ISO-8859-1" ?>
<root>
<version>1.0.0</version>
<menu>
<Category1>
<item>
<id>Cake</id>
<nr>1</nr>
<hint>I like these</hint>
<userlevel>5</userlevel>
</item>
<item>
<id>Cake 2</id>
<nr>2</nr>
<hint>I like these too, but only for me</hint>
<userlevel>10</userlevel>
</item>
<Category1>
<Category2WithApples>
<item>
<id>Apple Cake</id>
<nr>1</nr>
<hint>Sweet</hint>
<userlevel>5</userlevel>
</item>
<item>
<id>Rainbow Cake</id>
<nr>2</nr>
<hint>Mine!!</hint>
<userlevel>10</userlevel>
</item>
<Category2WithApples>
</menu>
</root>
Now, I want each user to be able to load in his custom XML which is in the same folder as the main.xml which looks like this:
<CategoryMyOwn>
<item>
<id>Item in my Category</id>
<nr>0</nr>
<hint>Some text</hint>
<userlevel>0</userlevel>
</item>
</CategoryMyOwn>
<Category1>
<item>
<id>Item in existing category</id>
<nr>0</nr>
<hint>Some text</hint>
<userlevel>0</userlevel>
</item>
</Category1>
I've tried solutions from
http://php.net/manual/de/ref.simplexml.php
php recursion, function doesn't return any value
http://durgagupta.com.np/php-how-to-merge-two-simplexml-objects/
but they all do not work at all for me or just append the second file to the end of my main.xml. So, my question is, how do I properly merge the user.xml into my main.xml so it looks like this:
<?xml version="1.0" encoding="ISO-8859-1" ?>
<root>
<version>1.0.0</version>
<menu>
<Category1>
<item>
<id>Cake</id>
<nr>1</nr>
<hint>I like these</hint>
<userlevel>5</userlevel>
</item>
<item>
<id>Cake 2</id>
<nr>2</nr>
<hint>I like these too, but only for me</hint>
<userlevel>10</userlevel>
</item>
<item>
<id>Item in existing category</id>
<nr>0</nr>
<hint>Some text</hint>
<userlevel>0</userlevel>
</item>
<Category1>
<Category2WithApples>
<item>
<id>Apple Cake</id>
<nr>1</nr>
<hint>Sweet</hint>
<userlevel>5</userlevel>
</item>
<item>
<id>Rainbow Cake</id>
<nr>2</nr>
<hint>Mine!!</hint>
<userlevel>10</userlevel>
</item>
<Category2WithApples>
<CategoryMyOwn>
<item>
<id>Item in my Category</id>
<nr>0</nr>
<hint>Some text</hint>
<userlevel>0</userlevel>
</item>
</CategoryMyOwn>
</menu>
</root>
Your second XML is not a document, XML documents need to have a document element node. In other words here at the top level only a single element node is allowed. All other element nodes have to be descendants of that node.
You can treat this as an XML fragment however. A fragment is the inner XML of an element node.
In both cases it easier to use DOM for that.
Append a fragment to a parent element node
Let's keep it simple for the first step and append the fragment to the menu node.
$document = new DOMDocument();
$document->loadXml($targetXml);
$xpath = new DOMXpath($document);
$fragment = $document->createDocumentFragment();
$fragment->appendXml($fragmentXml);
foreach ($xpath->evaluate('/root/menu[1]') as $menu) {
$menu->appendChild($fragment);
}
echo $document->saveXml();
The Xpath expression can /root/menu[1] selects the first menu element node inside the root. This can be only one node or none.
A document fragment in DOM is a node object and can be appended like any other node (element, text, ...).
Merging nodes
Merging the category nodes is a little more difficult. But Xpath will help.
$document = new DOMDocument();
$document->loadXml($targetXml);
$xpath = new DOMXpath($document);
$fragment = $document->createDocumentFragment();
$fragment->appendXml($fragmentXml);
$menu = $xpath->evaluate("/root/menu[1]")->item(0);
foreach ($xpath->evaluate('*', $fragment) as $category) {
$targets = $xpath->evaluate("{$category->nodeName}[1]", $menu);
if ($targets->length > 0) {
$targetCategory = $targets->item(0);
foreach ($category->childNodes as $item) {
$targetCategory->appendChild($item);
}
} else {
$menu->appendChild($category);
}
}
echo $document->saveXml();
Fetching the menu node
$menu = $xpath->evaluate("/root/menu[1]")->item(0);
This is about the same like in the first simple example. It fetch the menu nodes in root and returns the first found node. You should check if the list contained a node. But for this example just take it for guaranteed.
Iterating the fragment
foreach ($xpath->evaluate('*', $fragment) as $category) {
...
}
* is a simple Xpath expression that returns any element child node. The fragment can contain other nodes (whitespace, text, comment, ...). The second argument for DOMXpath::evaluate() is the context for the Xpath expression.
Fetching the target category
Next you need to fetch the category node with the same name from the target document. This will return a list with one node or an empty list.
$targets = $xpath->evaluate("{$category->nodeName}[1]", $menu);
if ($targets->length > 0) {
...
} else {
...
}
Append to the found target category
If the category exists append all child nodes from the category in the fragment to the target.
$targetCategory = $targets->item(0);
foreach ($category->childNodes as $item) {
$targetCategory->appendChild($item);
}
Append a category
$menu->appendChild($category);
If the category doesn't exists, just append it to the menu.
I've made a simple news script that saves articles to rss which then gets used on the Character Generator Newsticker on TV, the problem is that the CG plays the nodes starting from the top of the rss file.
now the xml looks like this:
<?xml version="1.0" ?>
<rss version="2.0">
<channel>
<title>News</title>
<link>website.com</link>
<description>News</description>
<language>ar-sa</language>
<item>
<title>Headline 1</title>
<description>Headline one the news this hour</description>
</item>
<item>
<title>Headline 2</title>
<description>Fire here flooding over there</description>
</item>
<item>
<title>Headline 3</title>
<description>Fire here flooding over there</description>
</item>
</channel>
</rss>
What i would like todo is have an option to move articles up and down the xml file, so instead of having "Headline 3" third in the list i would like to move it up to be first.
I know with C# you can do this using:
XElement node = ...get the element...
//Move up
if (node.PreviousNode != null) {
node.PreviousNode.AddBeforeSelf(node);
node.Remove();
}
//Move down
if (node.NextNode != null) {
node.NextNode.AddAfterSelf(node);
node.Remove();
Anyone have an idea how i can do this in PHP?
Thanks!
You can have a look at this answer XML reforming with DOM where they use the DOM-parser to rearrange the XML
I have two XML files (that have a number of common nodes) that look a bit like these:
DESTINATION FILE: ('destination.xml')
<items>
<item>
<title>Item A</title>
<description>This is the description for Item A</description>
<id>1001</id>
</item>
<item>
<title>Item B</title>
<description>This is the description for Item B</description>
<id>1002</id>
</item>
<item>
<title>Item D</title>
<description>This is the description for Item D</description>
<id>1004</id>
</item>
and
SOURCE FILE: ('source.xml')
<items>
<item>
<title>Item A</title>
<description>This is the description for Item A</description>
<id>1001</id>
</item>
<item>
<title>Item C</title>
<description>This is the description for Item C</description>
<id>1003</id>
</item>
<item>
<title>Item B</title>
<description>This is the description for Item B</description>
<id>1002</id>
</item>
I need to grab the node from SOURCE with the 'id' matching '1003' (in this example) and import it into the DESTINATION. I'm looking for insight in using importNode (or a simpleXML option) and also the xpath in only getting only the node I need.
Just do that and it should work :
<?php
header('Content-type: application/xml'); //Just to test in the browser directly and have a good format
$docSource = new DOMDocument();
$docSource->loadXML(file_get_contents('source.xml'));
$docDest = new DOMDocument();
$docDest->loadXML(file_get_contents('destination.xml'));
$xpath = new DOMXPath($docSource);
$result = $xpath->query('//item[id=1003]')->item(0); //Get directly the node you want
$result = $docDest->importNode($result, true); //Copy the node to the other document
$items = $docDest->getElementsByTagName('items')->item(0);
$items->appendChild($result); //Add the copied node to the destination document
echo $docDest->saveXML();
To get the correct node, I think your XPath should look like this:
$xpath->query('/items/item/id[.="1003"]/..')
To import it to the other document, you'll need to create the document and call importNode with the second parameter set to true:
$newDom = new DOMDocument;
$newDom->load('destination.xml');
$newNode = $newDom->importNode($el, true);
$newDom->firstChild->appendChild($newNode);
file_put_contents('destination.xml', $newDom->saveXML());
I am completely new to DOM Documents, basically what I am trying to do, is to load a RSS feed in and select only one node, and then save it to a XML file.
Here is the XML I am loading from a web feed:
<?xml version="1.0" encoding="UTF-8"?>
<rss version="2.0">
<channel>
<title>Markets</title>
<description/>
<link>http://www.website.com</link>
<language>en-us</language>
<copyright>XML Output Copyright</copyright>
<ttl>15</ttl>
<pubDate>Tue, 16 Nov 2010 09:38:00 +0000</pubDate>
<webMaster>admin#website.com</webMaster>
<image>
<title>title</title>
<url>http://www.website.com/images/xmllogo.gif</url>
<link>http://www.website.com</link>
<width>144</width>
<height>16</height>
</image>
<item>
<title>title</title>
<description>the description goes here
</description>
<enclosure url="http://www.website.com/images/image.png" type="image/png"/>
</item>
</channel>
</rss>
Here is my lame attempt at getting the <description> node and saving it to feed.xml:
<?php
$feed = new DOMDocument();
$feed->load('http://www.website.com/directory/directory/cz.c');
$nodeValue = $feed->getElementsByTagName('description')->item(0)->nodeValue;
$feed->save("feed.xml");
?>
So basically I need to get the description tag, and save it as a XML file.
Any help would be appreciated, thanx in advance!
Almost correct. To get the "outerXml" of a node, you can pass the node to saveXml()
$feed = new DOMDocument();
$feed->load('http://www.website.com/directory/directory/cz.c');
$xml = $feed->saveXml($feed->getElementsByTagName('description')->item(0));
file_put_contents("feed.xml", $xml);
Saving with file_put_contents will not include an XML prolog. Note that in your example, the first description element is empty, so the file will contain <description/>.
If you want to extract the node as standalone XML Document, you have to instantiate a new DOMDocument and import the DOMNode and then use save().
$dom = new DOMDocument($feed->xmlVersion, $feed->xmlEncoding);
$dom->appendChild(
$dom->importNode(
$feed->getElementsByTagName('description')->item(0),
TRUE
)
);
echo $dom->save('new.xml');
$feed = simplexml_load_file('feed.xml');
$descr=$feed->channel->description;
Try this