I'm trying strip every third character (in the example a period) below is my best guess and is close as ive gotten but im missing something, probably minor. Also would this method (if i could get it working) be better than a regex match, remove?
$arr = 'Ha.pp.yB.ir.th.da.y';
$strip = '';
for ($i = 1; $i < strlen($arr); $i += 2) {
$arr[$i] = $strip;
}
One way you can do it is:
<?php
$oldString = 'Ha.pp.yB.ir.th.da.y';
$newString = "";
for ($i = 0; $i < strlen($oldString ); $i++) // loop the length of the string
{
if (($i+1) % 3 != 0) // skip every third letter
{
$newString .= $oldString[$i]; // build up the new string
}
}
// $newString is HappyBirthday
echo $newString;
?>
Alternatively the explode() function might work, if the letter you're trying to remove is always the same one.
This might work:
echo preg_replace('/(..)./', '$1', 'Ha.pp.yB.ir.th.da.y');
To make it general purpose:
echo preg_replace('/(.{2})./', '$1', $str);
where 2 in this context means you are keeping two characters, then discarding the next.
A way of doing it:
$old = 'Ha.pp.yB.ir.th.da.y';
$arr = str_split($old); #break string into an array
#iterate over the array, but only do it over the characters which are a
#multiple of three (remember that arrays start with 0)
for ($i = 2; $i < count($arr); $i+=2) {
#remove current array item
array_splice($arr, $i, 1);
}
$new = implode($arr); #join it back
Or, with a regular expression:
$old = 'Ha.pp.yB.ir.th.da.y';
$new = preg_replace('/(..)\./', '$1', $old);
#selects any two characters followed by a dot character
#alternatively, if you know that the two characters are letters,
#change the regular expression to:
/(\w{2})\./
I'd just use array_map and a callback function. It'd look roughly like this:
function remove_third_char( $text ) {
return substr( $text, 0, 2 );
}
$text = 'Ha.pp.yB.ir.th.da.y';
$new_text = str_split( $text, 3 );
$new_text = array_map( "remove_third_char", $new_text );
// do whatever you want with new array
Related
I have the following string...
$string = "True is True (5-7 years)";
what I want is to get - TiT(5-7 years)
I have tried the following code but no luck...
$string = "True is True (5-7 years)";
$explodedString = explode(" ",$string);
for($i = 0; $i < 4; $i++){
$tempString = substr($explodedString[$i], 0, 1);
$finalString .= $tempString;
}
In short, I need the first three words of its initials and the remaining in bracket is as it is like this.... TiT(5-7 years). how?
This a good case for using regular expressions:
$str = 'True is True (5-7 years)';
preg_match_all('~\([^()]*\)|\b\w~', $str, $matches);
echo implode("", $matches[0]); // TiT(5-7 years)
Regex breakdown:
\([^()]*\) Match anything inside parentheses including themselves
| Or
\b\w Match first word character from a word
Your loop is going one element too far. If you want the first letter of the first 3 words, it should be $i < 3.
Then you should use array_slice() and implode() to concatenate the rest of the array.
for ($i = 0; $i < 3; $i++) {
$finalString .= $explodedString[$i][0];
}
$finalString .= implode(' ', array_slice($explodedString, 3));
DEMO
$string = "True is True (5-7 years)";
$new_string = preg_replace('/^([a-z])[a-z]+ ([a-z])[a-z]+ ([a-z])[a-z]+ (\(.+\))$/i', '$1$2$3$4', $string);
First of all.
Create an empty variable. That will be your final result
$result="";
Then youse foreach to loop your explode string.
At every part chech the first character.
If it's not ( add the first char onto the result variable.
else add the whole array element onto the result variable
foreach(explodedString as $t){
If($t[0] !="("){$result.=$t[0];} else{$result.=$t;}
}
At the end of the loop you will get what you wanted
echo $result;
I have a url. I want to parse url. I don't want to get last two value. How can I do?
$str="first-second-11.1268955-15.542383564";
As I wanted
$str="first-second";
I used this code. But I don't want to get - from last value
$arr = explode("-", $str);
for ($a = 0; $a < count($arr) - 2; $a++) {
$reqPage .= $arr[$a] . "-";
}
You can use regular expressions too.Those are patterns used to match character combinations in strings.:
W*((?i)first-second(?-i))\W*
Use the 3rd param of explode() called limit:
$str="first-second-11.1268955-15.542383564";
$arr = explode("-", $str, -2);
$reqPage = implode($arr, "-"); // contains "first-second"
Regex is the fastest way for the string manipulations. Try this.
$str="first-second-11.1268955-15.542383564";
preg_match('/^[a-z]*-{1}[a-z]*/i', $str, $matches);
$match = count($matches) > 0 ? $matches[0] : '';
echo $match;
How can I format an arbitrary string according to a flexible pattern? The only solution I came up with is using regular expressions, but then I need 2 "patterns" (one for the search and one for the output).
Example:
$str = '123ABC5678";
Desired output: 12.3AB-C5-67.8
I would like to use a pattern in a variable (one that a user can easily define without knowledge of regular expressions) It could look like this:
$pattern = '%%.%%%-%%-%%.%';
So the user would just have to use 2 different characters (% and .)
A solution with regex would look like this:
$str = '123ABC5678';
$pattern_src = '#(.{2})(.{3})(.{2})(.{2})(.{1})#';
$pattern_rpl = "$1.$2-$3-$4.$5";
$res = preg_replace($pattern_src, $pattern_rpl, $str);
//$res eq 12.3AB-C5-67.8
Way too complicated since the user would need to define $pattern_src and $pattern_rpl. If the string could vary in length, it would be even more complex to explain.
Yes, I could write a function/parser that builds the required regular expressions based on a simple user pattern like %%.%%%-%%-%%.%. But I wonder if there is any "built in" way to achieve this with php? I was thinking about sprintf etc., but that doesn't seem to do the trick. Any ideas?
I was thinking about sprintf etc., but that doesn't seem to do the trick.
You're on the right track. You can accomplish this with vsprintf as follows:
$str = '123ABC5678';
$pattern = '%%.%%%-%%-%%.%';
echo vsprintf(str_replace('%', '%s', $pattern), str_split($str));
Output:
12.3AB-C5-67.8
This is assuming the number of % characters in $pattern match the length of $str.
Why not write a simple parser that works as follows:
For each character of pattern:
if you match percent character, output next character from input
if you match any other character, output it
$str = '123ABC5678';
$pattern = '%%.%%%-%%-%%.%';
if (strlen($str) < substr_count($pattern, '%'))
Die('The length of input string is lower than number number of placeholders');
$len = strlen($pattern);
$stringIndex = 0;
$output = '';
for ($i = 0; $i < $len; $i++) {
if ($pattern[$i] === '%') {
$output .= $str[$stringIndex];
$stringIndex++;
} else {
$output .= $pattern[$i];
}
}
echo $output;
I have a similar solution that looks like this.
<?php
$format = '%%.%%%-%%-%%.%';
$string = '123ABC5678';
$new_string = '';
$c = 0;
for( $i = 0; $i < strlen( $format ); $i++ )
{
if( $format[ $i ] == '%' )
{
$new_string .= $string[ $c ];
$c++;
}
else
{
$new_string .= $format[ $i ];
}
}
echo $new_string;
Output:
12.3AB-C5-67.8
How about this pattern from the user?
2.3-2-2.1
Where the pattern is a number means n chars, a dot or dash means add a dot or dash.
Now you make a regex to parse the user input:
preg_match_all("/(.)/", $User_input, $pattern);
Now you will have an array with either numbers or dots and dashes.
So loop through the array and build the string:
$string = '123ABC5678';
$User_input = "2.3-2-2.1";
preg_match_all("/(.)/", $User_input, $pattern);
$i=0;
$str="";
foreach($pattern[1] as $val){
if(is_numeric($val)){
$str .= substr($string,$i,$val);
$i=$i+$val;
}else{
$str .= $val;
}
}
echo $str;
https://3v4l.org/5eg5G
I'm searching for the most elegant way in PHP to hide a string (for example an username).
For example, usernames should be shown as:
tim will be shown as: t*m
So the username itself is not completely "cryptically", but no one can guess their login name or at least not for sure.
You can use preg_replace:
$string = 'usernameTest';
echo preg_replace("/(?!^).(?!$)/", "*", $string); // u**********t
(?!^) Checks if the character is not the first character in the string.
. matches any character
(?!$) Checks if the character is not the last character in the string.
Hope this helps.
You can use the following regex along with preg_replace function like as
(^.|.$)(*SKIP)(*F)|(.)
Example
$your_string = "Narendra";
echo preg_replace("/(^.|.$)(*SKIP)(*F)|(.)/","*",$your_string);
Output :
N******a
Explanation of Regex:
(^.|.$) This'll capture the first and last alphabet of the word
(*SKIP)(*F) This'll skip the above captured words
|(.) Over here rest of the alphabets'll be captured and can be replaced further with your character i.e. * over here
Demo
Try:
function get_starred($str) {
$len = strlen($str);
return substr($str, 0, 1).str_repeat('*', $len - 2).substr($str, $len - 1, 1);
}
$myStr = 'YourName';
echo get_starred($myStr); //should show Y******e
You can do something like this for example:
<?php
function HideUN($username = "") {
$replaced = "";
# Count the characters in username and remove an extra asterik (*)
# Substring, remove all characters and leave the first one and add the last one
for($i = 0; $i < strlen($username) -1; $i++) $replaced .= "*";
return substr($username, 0, 1)."".$replaced."".substr($username, -1, 1);
}
# Call this function
$string = "John";
echo HideUN($string);
?>
The substr() removes all characters after the first one, then the for() loop, counts the characters from $string and then we gonna add the asterik (*) to an other variable called $replaced.
Then at the end we put them together in an echo. Output: J***n
function Split_Hide_Name($name) {
$name = trim($name);
$split_name = explode(' ',$name);
foreach($split_name as $v) {
$string []= strlen($v);
}
$number_of_letters_to_show = 3;
$first_name_length = $string[0];
$last_name_length = $string[count($string)-1];
$first_name1 = $split_name[0];
$last_name1 = $split_name[count($string)-1];
$fname_cover = '';
for ($i = 0; $i < $first_name_length - $number_of_letters_to_show; $i++){
$fname_cover .="*";
}
$lname_cover = '';
for ($i = 0; $i < $last_name_length - $number_of_letters_to_show; $i++){
$lname_cover .="*";
}
$first_name = substr_replace($first_name1,$fname_cover,$number_of_letters_to_show);
$last_name = substr_replace($last_name1,$lname_cover,$number_of_letters_to_show);
return $first_name.' '.$last_name;}
I'm looking for a way that I can extract the first letter of each word from an input field and place it into a variable.
Example: if the input field is "Stack-Overflow Questions Tags Users" then the output for the variable should be something like "SOQTU"
$s = 'Stack-Overflow Questions Tags Users';
echo preg_replace('/\b(\w)|./', '$1', $s);
the same as codaddict's but shorter
For unicode support, add the u modifier to regex: preg_replace('...../u',
Something like:
$s = 'Stack-Overflow Questions Tags Users';
if(preg_match_all('/\b(\w)/',strtoupper($s),$m)) {
$v = implode('',$m[1]); // $v is now SOQTU
}
I'm using the regex \b(\w) to match the word-char immediately following the word boundary.
EDIT:
To ensure all your Acronym char are uppercase, you can use strtoupper as shown.
Just to be completely different:
$input = 'Stack-Overflow Questions Tags Users';
$acronym = implode('',array_diff_assoc(str_split(ucwords($input)),str_split(strtolower($input))));
echo $acronym;
$initialism = preg_replace('/\b(\w)\w*\W*/', '\1', $string);
If they are separated by only space and not other things. This is how you can do it:
function acronym($longname)
{
$letters=array();
$words=explode(' ', $longname);
foreach($words as $word)
{
$word = (substr($word, 0, 1));
array_push($letters, $word);
}
$shortname = strtoupper(implode($letters));
return $shortname;
}
Regular expression matching as codaddict says above, or str_word_count() with 1 as the second parameter, which returns an array of found words. See the examples in the manual. Then you can get the first letter of each word any way you like, including substr($word, 0, 1)
The str_word_count() function might do what you are looking for:
$words = str_word_count ('Stack-Overflow Questions Tags Users', 1);
$result = "";
for ($i = 0; $i < count($words); ++$i)
$result .= $words[$i][0];
function initialism($str, $as_space = array('-'))
{
$str = str_replace($as_space, ' ', trim($str));
$ret = '';
foreach (explode(' ', $str) as $word) {
$ret .= strtoupper($word[0]);
}
return $ret;
}
$phrase = 'Stack-Overflow Questions IT Tags Users Meta Example';
echo initialism($phrase);
// SOQITTUME
$s = "Stack-Overflow Questions IT Tags Users Meta Example";
$sArr = explode(' ', ucwords(strtolower($s)));
$sAcr = "";
foreach ($sArr as $key) {
$firstAlphabet = substr($key, 0,1);
$sAcr = $sAcr.$firstAlphabet ;
}
using answer from #codaddict.
i also thought in a case where you have an abbreviated word as the word to be abbreviated e.g DPR and not Development Petroleum Resources, so such word will be on D as the abbreviated version which doesn't make much sense.
function AbbrWords($str,$amt){
$pst = substr($str,0,$amt);
$length = strlen($str);
if($length > $amt){
return $pst;
}else{
return $pst;
}
}
function AbbrSent($str,$amt){
if(preg_match_all('/\b(\w)/',strtoupper($str),$m)) {
$v = implode('',$m[1]); // $v is now SOQTU
if(strlen($v) < 2){
if(strlen($str) < 5){
return $str;
}else{
return AbbrWords($str,$amt);
}
}else{
return AbbrWords($v,$amt);
}
}
}
As an alternative to #user187291's preg_replace() pattern, here is the same functionality without needing a reference in the replacement string.
It works by matching the first occurring word characters, then forgetting it with \K, then it will match zero or more word characters, then it will match zero or more non-word characters. This will consume all of the unwanted characters and only leave the first occurring word characters. This is ideal because there is no need to implode an array of matches. The u modifier ensures that accented/multibyte characters are treated as whole characters by the regex engine.
Code: (Demo)
$tests = [
'Stack-Overflow Questions Tags Users',
'Stack Overflow Close Vote Reviewers',
'Jean-Claude Vandàmme'
];
var_export(
preg_replace('/\w\K\w*\W*/u', '', $tests)
);
Output:
array (
0 => 'SOQTU',
1 => 'SOCVR',
2 => 'JCV',
)