I have three classes. Class A, Class B, Class C. What I am trying to do, send a request to Class B form Class A, and Class B must redirect that request to Class c.
May be a simple example from below will give a certain idea.
class classa {
public function __construct() {
$obj_classb = new classb;
$obj_classb -> someRequest(); // This request must go to Class B and query the Class C
}
}
class classb {
//This class must do something, which is going to redirect any sorts of request it receives to the next classc
}
class classc {
public function someRequest() {
//do whatever
}
}
Any Idea?
You can create a "redirector" class by overriding the __call method like this:
class classb {
private $obj_classc;
public function __construct() {
$this->obj_classc = new classc;
}
public function __call($name, $arguments) {
return call_user_func_array(array($this->obj_classc, $name), $arguments);
}
}
Of course this will "forward" only method calls; if you are interested in forwarding property getters/setters etc you will have to override more magic methods.
Choosing the forwarding target can also be arranged (in this example it's just an automatically-created classc object; but you can pass it as a parameter in the constructor or provide it in any other way you choose).
Update: Magic functions you need to override to forward property accesses:
public function __set($name, $value) {
$this->obj_classc->$name = $value;
}
public function __get($name) {
return $this->obj_classc->$name;
}
public function __isset($name) {
return isset($this->obj_classc->$name);
}
public function __unset($name) {
unset($this->obj_classc->$name);
}
Related
I am not sure how to name this, but here it goes. Lets suppose i have the following
class A {
public function aa() {
$this->bb();
}
public function bb() {
}
}
class B extends a {
}
class C {
__construct(B $service) {
$this->service = $service;
}
public function aa() {
$this->service->aa();
}
}
My call in code will be
$C = new C(new B());
$C->aa();
So this will basically execute A:aa() which is what i want. As you can see, in A::aa() AA::bb() is called.
What I need. When AA::bb() is called i want to execute some code defined in class C, but I am not allowed to change the A class. I can only change the B class or the C class.
My idea was to add a listener in the B class and overwrite the bb() function like this
class B extends a {
public $listener;
bb() {
parent::bb();
$this->listener();
}
}
class C {
__construct(B $service) {
$this->service = $service;
}
public function aa() {
$this->service->listener = function() { }
$this->service->aa();
}
}
But I don't like this idea a lot, doesn't look like a good one. What are my options here?
Again, I CANNOT change the A class and i can only call the C class.
PHP version is 5.3
You have two options. Extend or decorate.
First one would be kinda what you have already written, though, I would not use public visibility for the listener:
class Foo extends A {
private $listener;
public function setListener(callable $func) {
$this->listener = $func;
}
public function bb() {
call_user_func($this->listener);
return parent:bb();
}
}
In the example I passed the listener via setter injection, but you can also use constructor injection and pass the $listened in the overloaded __construct() method. When you extend a class, the "interface restriction" does not aply to the constructor's signature.
The other approach is to use a decorator:
class Foo {
private $target;
public function __construct(A $target) {
$this->target = $target;
}
public function bb($callback) {
$callback();
return $this->target->bb();
}
public function __call($method, $arguments) {
return call_user_func_array(
array( $this->target, $method ),
$arguments
);
}
}
The second approach would let you alter the interface.
Which option you pick depend on the exact functionality you actually need to implement. The decorator is a solution for, when you need drastic change in the objects behavior - for example, it is really good for adding access control.
I understand that you want to execute code in C after code in A completes. You cannot change A.
As written, C::aa calls A::aa, which calls A::bb and the stack unwinds. Why not just do the work in C::aa after the service call finishes?
class C {
public function aa() {
$this->service->aa();
// whatever you want to do
}
}
If, on the other hand, you need to call code after A::aa is called but before A::bb is called then the example you posted would suffice with clarity:
class B extends a {
public $listener;
public function bb() {
call_user_func($this->listener);
parent::bb();
}
}
Note the use of call_user_func, which is necessary for PHP 5.3 to call an anonymous function stored in a member variable.
I am working on a PHP Object and I have a problem, I try to call an attribute (which is an object) from a mother class, and it's null. I'll show you my problem:
Class A {
protected $attribute;
public function __construct() {
$this->attribute = new C();
}
public function foo() {
new B();
}
}
Class B extends A {
public function __construct() {
var_dump($this->attribute) // show "NULL"
}
}
You are overriding A's constructor in B, which means that A's constructor never gets called, and consequently, $attribute never gets set. If you want to execute A's constructor in B, you need to do so explicitly:
class B extends A {
public function __construct() {
parent::__construct(); // This is required if you want to execute A's constructor
var_dump($this->attribute);
}
}
My Class is independant from another Class.
Inside my Class, a function is doing the same but refined job as a function in another Class. Can I use parent:: function_in_another_class() and get my function join that parent funciton's job flow?
No.
In PHP you can only extend from none or one class. As you write both classes are independent to each other, there is no information where to find the one or the other class.
But what you're looking for is probably this:
class A
{
function myFunction() {}
}
class B
{
private $a;
public function __construct(A $a)
{
$this->a = $a;
}
public function myFunction()
{
$this->a->myFunction();
}
}
If any class method already doing the same thing why would you bother call join it?
You can not do it. If you want the same job flow best way to do is to instantiate the other class and invoke that very same method. Thats why we use OOP.
See the example,
interface Fable()
{
public function f();
}
class OtherClass implements Fable
{
public function f()
{
// job flow
}
}
class MyClass
{
private $fable;
public function __construct(Fable $f)
{
$this->fable = $f;
}
public function method1($args){
return $this->fable->f($args);
}
}
If the current class is a child of another class, yes, you can. parent references to the parent class.
From php.net:
<?php
class A {
function example() {
echo "I am A::example() and provide basic functionality.<br />\n";
}
}
class B extends A {
function example() {
echo "I am B::example() and provide additional functionality.<br />\n";
parent::example();
}
}
$b = new B;
// This will call B::example(), which will in turn call A::example().
$b->example();
?>
The best you can do here is to extend Class B from Class A
Class B extends Class A
But, you can also:
class ClassA {
function do_something($args) {
// Do something
}
}
class ClassB {
function do_something_inclassA($args) {
classA::do_something($args);
}
}
Important: calling classa::do_something(); is a static call, in other words with error reporting E_STRICT you will get a static notice warning because function do_something() is not static function do_something()
Also, calling this function statically (i.e. classa::do_something()) means that class a's function cannot refer to $this within it
I have a class which initiates another class, i'm not concerned with having a reference to the object i only need the method and have to pass in new parameters.
class A {
__set .....
}
class B extends A {
$anotherA = new A;
$anotherA->myName = 'stackoverflow';
}
in short i'd like to have class B extend A, init a new instance of A but i don't want to have to type "new" everytime, i've seen the following syntax:
B::A // something like that
but not sure if how to use it or if that would do what i'm trying to do?
What you could do is define a static method on the class that returns the new instance. It's basically a 'shortcut', but it does exactly the same in the background.
class C {
public static function instance()
{
return new C();
}
public function instanceMethod()
{
echo 'Hello World!';
}
}
Now you can call it like:
C::instance()->instanceMethod();
Here are some examples of static functions - they can be called without using 'new A' or 'new B'.
class A {
static function message($msg = 'I am Alpha') {
echo "hi there, $msg\n";
}
}
class B {
static function message() {
A::message("I am Beta");
}
}
A::message();
B::message();
I would create the instance of A in B's constructor, then you can instantiate B using either its constructor or static B::create(), which just acts as a shortcut. You could make the constructor private if you wanted all instantiation go through create().
class A {
// __set .....
}
class B extends A {
public function __construct() {
parent::__construct();
$anotherA = new A;
$anotherA->myName = 'stackoverflow';
}
public static function create() {
return new self();
}
}
new B();
B::create();
Since you are extending A in B, you could call the method of class A:
class B extends A {
public function someMethod() {
parent::someMethodName();
}
}
Alternatively, you could create a static method in the class:
class A {
public static function someStaticMethod() { ... }
}
A::someStaticMethod();
If you really want a new instance of A, you have to use the new operator. That's what it is for.
sorry for that weird subject but I don't know how to express it in an other way.
I'm trying to access a method from a calling class. Like in this example:
class normalClass {
public function someMethod() {
[...]
//this method shall access the doSomething method from superClass
}
}
class superClass {
public function __construct() {
$inst = new normalClass;
$inst->someMethod();
}
public function doSomething() {
//this method shall be be accessed by domeMethod form normalClass
}
}
Both classes are not related by inheritance and I don't want to set the function to static.
Is there any way to achieve that?
Thanks for your help!
You can pass a reference to the first object like this:
class normalClass {
protected $superObject;
public function __construct(superClass $obj) {
$this->superObject = $obj;
}
public function someMethod() {
//this method shall access the doSomething method from superClass
$this->superObject->doSomething();
}
}
class superClass {
public function __construct() {
//provide normalClass with a reference to ourself
$inst = new normalClass($this);
$inst->someMethod();
}
public function doSomething() {
//this method shall be be accessed by domeMethod form normalClass
}
}
You could use debug_backtrace() for this. It is a bit iffy but for debugging purposes it is usefull.
class normalClass {
public function someMethod() {
$trace = debug_backtrace();
$trace[1]['object']->doSomething();
}
}
You have a few options. You can use aggregation like so
class normalClass
{
protected $superClass;
public function __construct( superClass $superClass )
{
$this->superClass = $superClass;
}
public function someMethod()
{
$this->superClass->doSomething();
}
}
class superClass
{
public function __construct()
{
$inst = new normalClass( $this );
$inst->someMethod();
}
public function doSomething()
{ //this method shall be be accessed by domeMethod form normalClass
}
}
Or just a straight-up setter
class normalClass
{
protected $superClass;
public function setSuperClass( superClass $superClass )
{
$this->superClass = $superClass;
}
public function someMethod()
{
if ( !isset( $this->superClass ) )
{
throw new Exception( 'you must set a superclass' );
}
$this->superClass->doSomething();
}
}
class superClass
{
public function __construct()
{
$inst = new normalClass();
$inst->setSuperClass( $this );
$inst->someMethod();
}
public function doSomething()
{ //this method shall be be accessed by domeMethod form normalClass
}
}
Depending on your use case, you might want to pass the instance to the function only:
class normalClass {
public function someMethod($object) {
$object->doSomething();
}
}
If normalClass::someMethod() can be called by multiple, distinct $objects, this might be the better choice (instead of providing the $object to the whole normalClass instance).
But regardless of that you might consider creating an Interface to use for type hinting:
interface ISomethingDoer {
public function doSomething();
}
class normalClass {
public function someMethod(ISomethingDoer $object) {
# Now PHP will generate an error if an $object is passed
# to this function which does not implement the above interface.
// ...
class superClass implements ISomethingDoer {
// ...
woah I had the same problem than you but instead of going with the so simple pass the reference to the object, I went with an event manager, Basically, when something would happen in the normal class, it would trigger an event which was listened by a class and that said class(the listener) would call the super class to execute that functionality and if necessary pass it new arguments.
Anyways, whether you pass it as a parameter to your object or you go with an event based approach, both solutions work. Choose the one you prefers.
For more information on events, sympony explains it quite good.
http://symfony.com/doc/current/components/event_dispatcher/introduction.html