problem with calculating all elements in array - php

$query = $db->query("SELECT * FROM orders");
while ($row = mysql_fetch_array($query)) {
$cost= array_sum($row['cost']);
}
This is not working, I want to to calculate the sum of all elements but I get this error:
Warning: array_sum() expects parameter
1 to be array, string given in
C:\xampp\htdocs\falco\classes\controller.php
on line 303
Any idea how to calculate all the elements coming from mysql?
Thank you for your time and help.

Why not let MYSQL handle it?
$query = $db->query("SELECT orders.*,SUM(cost) as sum_cost FROM orders");

If its just a sum you want you can let the database do it for you:
Select sum(cost) from orders

Try this:
$query = $db->query("SELECT * FROM orders");
$cost = 0;
while ($row = mysql_fetch_array($query)) {
$cost += $row['cost'];
}
Or from mysql:
$query = $db->query("SELECT sum(`cost`) as `cost` FROM orders");
while ($row = mysql_fetch_array($query)) {
$cost = $row['cost'];
}

this should work:
$query = $db->query("SELECT * FROM orders");
$cost = 0;
while ($row = mysql_fetch_array($query)) {
$cost += $row['cost'];
}
or even better
$query = $db->query("SELECT SUM(cost) FROM orders");
list($cost) = mysql_fetch_row($query);

Really, it sounds like you just want the sum.
'SELECT SUM(cost) as sum_cost FROM ORDERS'

Related

Display the total of the SUM (price * quantity) from SELECT query [duplicate]

I have a column in a table that I would like to add up and return the sum. I have a loop, but it's not working.
while ($row = mysql_fetch_assoc($result)){
$sum += $row['Value'];
}
echo $sum;
You can completely handle it in the MySQL query:
SELECT SUM(column_name) FROM table_name;
Using PDO (mysql_query is deprecated)
$stmt = $handler->prepare('SELECT SUM(value) AS value_sum FROM codes');
$stmt->execute();
$row = $stmt->fetch(PDO::FETCH_ASSOC);
$sum = $row['value_sum'];
Or using mysqli:
$result = mysqli_query($conn, 'SELECT SUM(value) AS value_sum FROM codes');
$row = mysqli_fetch_assoc($result);
$sum = $row['value_sum'];
$query = "SELECT * FROM tableName";
$query_run = mysql_query($query);
$qty= 0;
while ($num = mysql_fetch_assoc ($query_run)) {
$qty += $num['ColumnName'];
}
echo $qty;
Try this:
$sql = mysql_query("SELECT SUM(Value) as total FROM Codes");
$row = mysql_fetch_array($sql);
$sum = $row['total'];
Let us use the following image as an example for the data in our MySQL Database:
Now, as the question mentions, we need to find the sum of a particular column in a table. For example, let us add all the values of column "duration_sec" for the date '09-10-2018' and only status 'off'
For this condition, the following would be the sql query and code:
$sql_qry = "SELECT SUM(duration_sec) AS count
FROM tbl_npt
WHERE date='09-10-2018' AND status='off'";
$duration = $connection->query($sql_qry);
$record = $duration->fetch_array();
$total = $record['count'];
echo $total;
MySQL 5.6 (LAMP) . column_value is the column you want to add up. table_name is the table.
Method #1
$qry = "SELECT column_value AS count
FROM table_name ";
$res = $db->query($qry);
$total = 0;
while ($rec = $db->fetchAssoc($res)) {
$total += $rec['count'];
}
echo "Total: " . $total . "\n";
Method #2
$qry = "SELECT SUM(column_value) AS count
FROM table_name ";
$res = $db->query($qry);
$total = 0;
$rec = $db->fetchAssoc($res);
$total = $rec['count'];
echo "Total: " . $total . "\n";
Method #3 -SQLi
$qry = "SELECT SUM(column_value) AS count
FROM table_name ";
$res = $conn->query($sql);
$total = 0;
$rec = row = $res->fetch_assoc();
$total = $rec['count'];
echo "Total: " . $total . "\n";
Method #4: Depreciated (don't use)
$res = mysql_query('SELECT SUM(column_value) AS count FROM table_name');
$row = mysql_fetch_assoc($res);
$sum = $row['count'];
$row['Value'] is probably a string. Try using intval($row['Value']).
Also, make sure you set $sum = 0 before the loop.
Or, better yet, add SUM(Value) AS Val_Sum to your SQL query.
$result=mysql_query("SELECT SUM(column) AS total_value FROM table name WHERE column='value'");
$result=mysql_result($result,0,0);
Get Sum Of particular row value using PHP MYSQL
"SELECT SUM(filed_name) from table_name"
$sql = "SELECT SUM(Value) FROM Codes";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)){
sum = $row['SUM(price)'];
}
echo sum;

Creating an array of IDs from a while loop

Im trying to generate an array but not sure how to go about it.
I'm currently getting my data like so:
$query = mysql_query("SELECT * FROM users WHERE userEmail LIKE 'test#test.com'");
$row = mysql_fetch_array($query);
$query1 = mysql_query("SELECT * FROM categories");
while($row1 = mysql_fetch_array($query1)){
$query2 = mysql_query("SELECT * FROM usersettings WHERE userId = ".$row['userId']." AND usersettingCategory".$row1['categoryId']." LIKE 'y'");
$isyes = mysql_num_rows($query2);
if($isyes > 0){
$cat1 = mysql_query("SELECT * FROM shops WHERE shopstateId = 1 AND (categoryId1 = ".$row1['categoryId']." OR categoryId2 = ".$row1['categoryId']." OR categoryId3 = ".$row1['categoryId'].")");
$cat1match = mysql_num_rows($cat1);
if($cat1match > 0){
while($cat1shop = mysql_fetch_array($cat1)){
$cat1msg = mysql_query("SELECT * FROM messages WHERE shopId = ".$cat1shop['shopId']." and messagestateId = 1");
while($cat1msgrow = mysql_fetch_array($cat1msg)){
echo $cat1msgrow['messageContent']." - ".$cat1msgrow['messageCode'];
$cat1img = mysql_query("SELECT shopimagePath FROM shopimages WHERE shopimageId = ".$cat1shop['shopimageId']);
$imgpath = mysql_fetch_array($cat1img);
echo " - ".$imgpath['shopimagePath']."<br/>";
}
}
}
}
}
But this can cause duplicates when a user has all 3 of a shops categories picked in their preferences. I am trying to find a way to just pull the message ID out instead of the whole thing and put it into an array giving me, for example:
1,3,5,7,1,3,5,2,4,7,8
Then I can just run a separate query to say get me all messages where the ID is in the array, but i am unsure of the most constructive way to build such an array and examples of array from a while loop I have seen do not seem to be what I am looking for.
Is there anyone out there that can push me in the right direction?
Can't help with this code. But if you want an array from a query without duplicate result, you can use " select DISTINCT (id) " in your query or for more simple solution :
$id_arr = array();
$sql = mysql_query("select id from id_table");
while ($id_result = mysql_fetch_array($sql) {
$id = $id_result['id'];
if (!in_array($id, $id_arr)) {
$id_arr[] = $id;
}
}
I have found a much easier way to create the required result. I think at 6am after a hard night coding my brain was fried and I was making things a lot more complicated than I needed to. A simple solution to my issue is as follows:
$query = mysql_query("SELECT * FROM users WHERE userEmail LIKE 'test2#test2.com'");
$row = mysql_fetch_array($query);
$categories = "(";
$query1 = mysql_query("SELECT * FROM categories");
while($row1 = mysql_fetch_array($query1)){
$query2 = mysql_query("SELECT usersettingCategory".$row1['categoryId']." FROM usersettings WHERE userId = ".$row['userId']);
$row2 = mysql_fetch_array($query2);
if($row2['usersettingCategory'.$row1['categoryId']] == y){
$categories .= $row1['categoryId'].",";
}
}
$categories = substr_replace($categories ,")",-1);
echo $categories."<br />";
$query3 = mysql_query("SELECT * FROM shops,messages WHERE shops.shopId = messages.shopId AND messages.messagestateId = 1 AND (shops.categoryId1 IN $categories OR shops.categoryId2 IN $categories OR shops.categoryId3 IN $categories)");
while($row3 = mysql_fetch_array($query3)){
$query4 = mysql_query("SELECT shopimagePath FROM shopimages WHERE shopimageId = ".$row3['shopimageId']);
$row4 = mysql_fetch_array($query4);
echo $row3['messageContent']." - ".$row3['messageCode']." - ".$row4['shopimagePath']."<br />";
}

php math question

I have a db table which have a row of a product amount. I want to create a loop that will calculate for me the sum for all the amounts.
$results = mysql_query("SELECT *
FROM prod");
while($info = mysql_fetch_array($results)) {
$amount = $info['amount'];
}
amount is the var for each product cost. I want to get a sum for all the vars together - how can I do it?
Use the SUM() function in a SQL query.
$result = mysql_query("SELECT SUM(amount) AS sum_amount FROM prod");
if ( $result )
$sum = mysql_result($result, 0, 0);
Easier to do in MySQL:
SELECT SUM(amount) FROM prod
Then fetch the result.
First:
You can do this with mysql
SELECT SUM(amount) FROM ....
Second:
while ($info = mysql_fetch_array($results)) {
$amount[] = $info['amount'];
}
$sum = array_sum($amount);
You can add the amounts to a variable:
$results = mysql_query("select * from prod");
$sum = 0
while($info = mysql_fetch_array($results)) {
$amount = $info['amount'];
$sum += $amount
}
Or you can do it in SQL:
SELECT SUM(column) FROM table

Get sum of MySQL column in PHP

I have a column in a table that I would like to add up and return the sum. I have a loop, but it's not working.
while ($row = mysql_fetch_assoc($result)){
$sum += $row['Value'];
}
echo $sum;
You can completely handle it in the MySQL query:
SELECT SUM(column_name) FROM table_name;
Using PDO (mysql_query is deprecated)
$stmt = $handler->prepare('SELECT SUM(value) AS value_sum FROM codes');
$stmt->execute();
$row = $stmt->fetch(PDO::FETCH_ASSOC);
$sum = $row['value_sum'];
Or using mysqli:
$result = mysqli_query($conn, 'SELECT SUM(value) AS value_sum FROM codes');
$row = mysqli_fetch_assoc($result);
$sum = $row['value_sum'];
$query = "SELECT * FROM tableName";
$query_run = mysql_query($query);
$qty= 0;
while ($num = mysql_fetch_assoc ($query_run)) {
$qty += $num['ColumnName'];
}
echo $qty;
Try this:
$sql = mysql_query("SELECT SUM(Value) as total FROM Codes");
$row = mysql_fetch_array($sql);
$sum = $row['total'];
Let us use the following image as an example for the data in our MySQL Database:
Now, as the question mentions, we need to find the sum of a particular column in a table. For example, let us add all the values of column "duration_sec" for the date '09-10-2018' and only status 'off'
For this condition, the following would be the sql query and code:
$sql_qry = "SELECT SUM(duration_sec) AS count
FROM tbl_npt
WHERE date='09-10-2018' AND status='off'";
$duration = $connection->query($sql_qry);
$record = $duration->fetch_array();
$total = $record['count'];
echo $total;
MySQL 5.6 (LAMP) . column_value is the column you want to add up. table_name is the table.
Method #1
$qry = "SELECT column_value AS count
FROM table_name ";
$res = $db->query($qry);
$total = 0;
while ($rec = $db->fetchAssoc($res)) {
$total += $rec['count'];
}
echo "Total: " . $total . "\n";
Method #2
$qry = "SELECT SUM(column_value) AS count
FROM table_name ";
$res = $db->query($qry);
$total = 0;
$rec = $db->fetchAssoc($res);
$total = $rec['count'];
echo "Total: " . $total . "\n";
Method #3 -SQLi
$qry = "SELECT SUM(column_value) AS count
FROM table_name ";
$res = $conn->query($sql);
$total = 0;
$rec = row = $res->fetch_assoc();
$total = $rec['count'];
echo "Total: " . $total . "\n";
Method #4: Depreciated (don't use)
$res = mysql_query('SELECT SUM(column_value) AS count FROM table_name');
$row = mysql_fetch_assoc($res);
$sum = $row['count'];
$row['Value'] is probably a string. Try using intval($row['Value']).
Also, make sure you set $sum = 0 before the loop.
Or, better yet, add SUM(Value) AS Val_Sum to your SQL query.
$result=mysql_query("SELECT SUM(column) AS total_value FROM table name WHERE column='value'");
$result=mysql_result($result,0,0);
Get Sum Of particular row value using PHP MYSQL
"SELECT SUM(filed_name) from table_name"
$sql = "SELECT SUM(Value) FROM Codes";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)){
sum = $row['SUM(price)'];
}
echo sum;

trying to show a total from mysql in php

I am trying to get the qunt with are int and add them all up and show a total
$qunt = 0;
$result = mysql_query("SELECT *
FROM properties_items
WHERE user_propid='$view'
ORDER BY id DESC") or die (mysql_error());
while ($row = mysql_fetch_array($result)) {
$itemid = $row['itemid'];
$qunt = $row['qunt'];
$qunt++;
}
echo $qunt;
$qunt = 0;
$result = mysql_query("SELECT *
FROM properties_items
WHERE user_propid='$view'
ORDER BY id DESC") or die (mysql_error());
while ($row = mysql_fetch_array($result)) {
$itemid = $row['itemid'];
$qunt += $row['qunt'];
}
echo $qunt;
Dare I say that you probably aren't using the itemid, in which case there's no point in looping through a result set in code. Instead, try something like this:
$qunt = mysql_query "SELECT SUM(qunt) FROM properties_items WHERE user_propid='$view'";
$qunt += $row['qunt'];
And get rid of the ++ line.

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