PHP cannot override protected static - php

I can't seem to be able to override protected static variables. It's rather annoying, given that you cannot override any private variable as well. Howcan I fix that? (Have to support PHP 5.2)
<?
class Foo{
protected static $stuff = 'Foo';
public function showStuff(){
echo self::$stuff . PHP_EOL;
}
}
class Bar extends Foo{
protected static $stuff = 'Bar';
}
$f = new Foo();
$b = new Bar();
$f->showStuff(); // Output: Foo
$b->showStuff(); // Output: Foo
?>

You need to use late static bindings, a feature introduced in PHP 5.3. In your class Foo, self refers to the Foo class. You want to refer to the class where the call originated. You need to use the keyword static:
<?
class Foo{
protected static $stuff = 'Foo';
public function showStuff(){
echo static::$stuff . PHP_EOL; // <-- this line
}
}
class Bar extends Foo{
protected static $stuff = 'Bar';
}
$f = new Foo();
$b = new Bar();
$f->showStuff(); // Output: Foo
$b->showStuff(); // Output: Bar
?>

You can override them, but you cannot get the value from the parent class. Well, this is wat PHP calls overriding, while it actually reintroduces the variable and tries to hide the parent variable. That's why this won't work the way you want.
Since you're not on 5.3 yet, I think the best solution is to use (and override) a static function too. If you don't need to modify the value, you can just make the class override the function to let it return a different constant value per class. If you do need the variable, you can reintroduce both the variable and the function in each class.
class x
{
static $a = '1';
static function geta()
{
return self::$a;
}
}
class y extends x
{
static $a = '2';
static function geta()
{
return self::$a;
}
}
echo x::geta();
echo y::geta();
It is dirty, but it solves the problem until you can use the neater static:: way of PHP 5.3.

There is a better solution. You can use get_called_class() to find the current context and use that to access statics.
eg.
class Foo {
protected static $table = "foo";
static function getTable() {
$class = get_called_class();
return $class::$table;
}
}
class Bar extends Foo {
protected static $table = "bar";
}
echo Foo::getTable()."<br />\n";
echo Bar::getTable()."<br />\n";
You will get output as follows:
foo<br />
bar<br />
That will work in any PHP 5 version

Actually you can override them :)
You just can't use them in parent class, as they are static. Late static binding fixes it.

Related

public/protected class properties don't override private properties on parent classes?

Declare a private property on a Parent class, and then redeclare that property as public or protected on a Child class.
When you create an instance of the Child class, and invoke a method that is inherited from the Parent class. The property on the Parent class is used, and not the property on the Child class.
This is not the case if the initial declaration of the property on the Parent class is public or protected.
Could someone explain to me why this is?
<?php
class P {
private $foo = 'bar';
public function e()
{
echo get_class($this);
echo "\n";
echo $this->foo;
echo "\n";
}
}
class C extends P
{
protected $foo = 'baz';
}
$parent = new P();
$child = new C();
$parent->e();
$child->e();
Output:
P
bar
C
bar
Expected Output:
P
bar
C
baz
Private properties are, as the name implies, private. This means they only be accessed from within the class. As others have mentioned in the comments, this question offers a very good in depth explanation of variable scope in PHP, so by all means go check it out, it's an interesting read.
In your specific however, you seem to be concerned about renaming/overloading variables in a child class. More specifically, we're looking at what happens when a parent and child class happen to both have a property of the same name, and the parent class has a function which return that property.
class A {
private $foo = 'bar';
public function getFoo() {
return $this->foo;
}
}
class B extends A {
protected $foo = 'something something';
}
$b = new B;
echo $b->getFoo();
In the example above, the output would be bar, and that's actually the expected behavior. Since the function getFoo is not overwritten in the child class, PHP executes the function in the parent class. When it gets there, $this refers to A and therefore prints the value of $foo as it is defined in A. It's interesting to note that in this specific example, the scope of B::foo does not matter. In fact, it could omitted entirely and the code would still run perfectly fine.
We can experiment with different function scopes and see what happens:
class A {
private $foo = 'bar';
public function getFoo() {
return $this->foo;
}
private function getCapitalizedFoo() {
return strtoupper($this->foo);
}
protected function getDoubleFoo() {
return $this->foo . $this->foo;
}
}
class B extends A {
protected $foo = 'something something';
public function getParentDoubleFoo() {
return parent::getDoubleFoo();
}
}
$b = new B;
echo $b->getFoo().PHP_EOL; // Output: bar
echo $b->getParentDoubleFoo(); // Output: barbar
echo $b->getDoubleFoo(); // Output: Uncaught Error: Call to protected method ...
echo $b->getCapitalizedFoo(); // Output: Uncaught Error: Call to private method ...
Now, the question remains: How can you access private members from a parent class?
If you have read on the subject, you probably know that, unless completely necessary, your object's properties should be private so as to encapsulate its logic and data as much as possible. Knowing that, the best to allow a child class to access and modify its parent's class properties is by creating accessors and mutators for them.
class A {
private $foo = 'foo';
private $bar = 'bar';
public function setFoo($foo) {
$this->foo = $foo;
}
public function getFoo() {
return $this->foo;
}
protected function setBar($bar) {
$this->bar = $bar;
}
protected function getBar() {
return $this->bar;
}
}
class B extends A {
public function __construct() {
parent::setFoo('more foo');
parent::setBar('more bar');
}
public function getCapitalizedFoo() {
return strtoupper(parent::getFoo());
}
public function getCapitalizedBar() {
return strtoupper(parent::getBar());
}
}
$b = new B;
echo $b->getCapitalizedFoo(); // Output: MORE FOO
echo strtoupper($b->getFoo()); // Output: MORE FOO
echo $b->getCapitalizedBar(); // Output: MORE BAR
echo strtoupper($b->getBar()); // Output: Uncaught Error: Call to protected method ...
By creating public functions to access and modify the parent class' properties you allow the child class to overwrite them and perform logic of its own without having to duplicate the variable. However this also means that any instance of B can potentially alter the values defined in A. In order to mitigate this, you can create protected function that will allow B to internally access and consume the parent class attributes, but the code that consumes B will not be able to do the same.

PHP: how to access the data members of super class in subclass with the same name?

I searched everywhere but did not find any solution to this question.
Following is my code where I want to access the $myvar of the super class in the subclass but I don't know how? when I use $this keyword it accesses the variable in the same class but not the one in super class. please any help will be greatly appreciated.
<?php
class First{
protected $myvar = "First Class";
}
class Second extends First{
public $myvar = "Second Class";
function __construct(){
echo $this -> myvar;// here I want to access the $myvar of super class
}
}
$obj = new Second();
?>
Note: I can achieve the same functionality in java by using the super keyword.
You may create a custom function that returns the variables from the parent class BUT keep in mind that the variables should be "private":
class First{
private $myvar = "First Class";
protected function get_variable($var_name)
{
return $this->{$var_name};
}
}
class Second extends First{
public $myvar = "Second Class";
function __construct() {
echo parent::get_variable('myvar');
}
}
$obj = new Second();
The way you try to do this will not work, as Rizier mentioned. Maybe static properties can be useful to you (depending on your needs ofcourse)
<?php
class a {
protected static $var = 'a';
}
class b extends a {
protected static $var = 'b';
public function __construct() {
echo self::$var;
echo parent::$var;
}
}
$b = new b();
You could also reconstruct a in b. You'd be able to leverage the inheritance for methods and maybe other properties, while being able to use the default value in a-constructor.
<?php
class a {
protected $var = 'a';
}
class b extends a {
protected $var = 'b';
public function __construct() {
echo $this->var;
$a = new a();
echo $a->var;
}
}
$b = new b();
The main question I think you should answer is why you want a class to inherit from another but still want to be able to change/modify stuff in the parent. That's kinda counterproductive for the whole inheritance design.
You can't you are overwritten in when creating the sub class which inherits from the parent class. So you would have to change the name for it.
You override the parent parameter with:
public $myvar = "Second Class";
Remove this line to use the inherits from parent class or change the name of the child class parameter.

calling a class function from another class function

I'm new to programming. I have this going on:
I have Class A, which have many functions. One of those functions is functionX.
In functionX I need to make a call to functionY which belongs to another class: Class B.
So how do I acces to functionY from inside functionX?
I use Codeigniter.
Thanks in advance.
Try and experiment with this.
class ClassA {
public function functionX() {
$classB = new ClassB();
echo $classB->functionY();
}
}
class ClassB {
public function functionY() {
return "Stahp, no more OO, stahp!";
}
}
Class function? A static method?
If you have an instance (public) method, you just call $classB->functionY().
If you have a static method, you would call ClassB::functionY();
So:
class ClassA {
public function functionX(){
$classB = new ClassB();
// echo 'foo';
echo $classB->functionY();
// echo 'bar';
echo ClassB::functionYStatic();
}
}
class ClassB {
public $someVar;
public static $someVar2 = 'bar';
function __construct(){
$this->someVar = 'foo';
}
public function functionY(){
return $this->someVar;
}
public static function functionYStatic(){
return self::$someVar2;
}
}
Well that depends. If that function is a static function or not.
First off you must include the file with the class...
include_once('file_with_myclass.php');
If it is static you can call it like this:
ClassName::myFunction()
If it is not, then you create an instance of the class and then call the function on that instance.
$obj = new ClassName();
$obj->myFunction();
As you can guess the function being static means you can call it without the need of creating an instance. That is useful for example if you have a class Math and want to define a function that takes to arguments to calculate the sum of them. It wouldn't really be useful to create an instance of Math to do that, so you can declare as static and use it that way.
Here's a link to the docs with further info
http://www.php.net/manual/en/keyword.class.php
If functionY is static you can call ClassB::functionY(). Else you must create instance of Class B first. Like:
$instance = ClassB;
$instance->functionY();
But maybe you mean something else?
Looks like one of your class has a dependency to another one:
<?php
class A
{
public function x()
{
echo 'hello world';
}
}
class B
{
private $a;
public function __construct(A $a)
{
$this->a = $a;
}
public function y()
{
$this->a->x();
}
}
$a = new A();
$b = new B($a);
$b->y();
Depending how your code looks like, if it makes sense, you can inject class A into y()
public function y(A $a)
{
// your code with $a
}

Access to class variable from outside

How can I access to class variable from outside without creating new instance in PHP ? Something like this:
class foo
{
public $bar;
}
echo foo::$bar;
Is it possible or I must create method that will print or return this value and use it or create new instance ( $a = new foo; echo $a->$bar ) ?
EDIT: I don't want to create constant but classic variable that will be changed later.
make this variable static to access it with out class object.
If you wanted to change static variable value by method then you need to use static method
you can try like this:
class foo
{
public static $bar ="google";
public static function changeVal($val){
self::$bar=$val;
}
}
foo::changeVal("changed :)");
echo foo::$bar;
Output : changed :)
Demo : https://eval.in/107138
You also can changed it like this without static method:
foo::$bar = "changed";
demo : https://eval.in/107139
like this:
class foo
{
public static $bar ="google";
}
echo foo::$bar;
Output: google
demo: https://eval.in/107126
IF it makes sense to use a static variable:
class foo{
public static $bar = 'example';
}
Which could be accessed like so:
echo foo::$bar;
If the value will never change during runtime, then you probably want a class constant (http://www.php.net/oop5.constants)
class foo {
const bar = 'abc';
}
...otherwise you want a public static variable (http://www.php.net/manual/en/language.oop5.static.php)
class foo {
public static $bar = 'abc';
}
...either way, access it like this
echo foo::bar;
You can access the class variable without creating instances only when the variable is markesd as static:
class foo
{
public static $bar;
}
This is how you use a class variable:
// with instantiation
class foo {
// initialize on declare
public $bar = 1;
// or initialize in __construct()
public function __construct(){
$this->bar = 1;
}
}
$foo = new foo();
var_dump($foo->bar);
// static way
class static_foo {
public static $bar = 1;
}
var_dump(static_foo::$bar);
And this is how you instantiate a class from a random class name string variable.
$foo = new foo();
$random_class_name = $foo->bar;
try {
// following line throws if class is not found
$rc = new \ReflectionClass($random_class_name);
$obj = $rc->newInstance();
// can be used with dynamic arguments
// $obj = $rc->newInstance(...);
// $obj = $rc->newInstanceArgs(array(...));
} catch(\Exception $Ex){
$obj = null;
}
if($obj){
// you have a dynamic object
}
What's your actual question?

Accessing Static Variable from child->child class php

I have the following setup:
<?php
class core {
static $var1;
}
class parent extends core {
function getStatic() {
return parent::$var1;
}
}
class child extends parent {
function getStatic() {
// I want to access core static var, how can i do it?
//return parent::$var1;
}
}
?>
I need to be able to use parent::$var1 but from within class child.. is this possible? Am I missing something?
Just reference it as self... PHP will automatically go up the chain of inheritance until it finds a match
class core {
protected static $var1 = 'foo';
}
class foo extends core {
public static function getStatic() {
return self::$var1;
}
}
class bar extends foo {
public static function getStatic() {
return self::$var1;
}
}
Now, there will be an issue if you don't declare getStatic in bar. Let's take an example:
class foo1 extends core {
protected static $var1 = 'bar';
public static function getStatic() {
return self::$var1;
}
}
class bar1 extends foo1 {
protected static $var1 = 'baz';
}
Now, you'd expect foo1::getStatic() to return bar (and it will). But what will Bar1::getStatic() return? It'll return bar as well. This is called late static binding. If you want it to return baz, you need to use static::$var1 instead of self::$var1 (PHP 5.3+ only)...
core::$var1 seems best for your needs...
The biggest problem here is that you're using the keyword parent as a class name. This makes it completely ambiguous whether your calls to parent::$var1 are intended to point to that class, or to the parent of the calling class.
I believe, if you clean this up, you can achieve what you want. This code prints 'something', for example.
class core {
static $var1 = 'something';
}
class foo extends core {
function getStatic() {
return parent::$var1;
}
}
class bar extends foo {
function getStatic() {
// I want to access core static var, how can i do it?
return parent::$var1;
}
}
$b = new bar ();
echo $b->getStatic ();
It also works if you use core:: instead of parent::. Those two will behave differently, though, if you declare a static $var1 inside of the foo class as well. As is it's a single, inherited variable.

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