I need to get textbox value to another php page. By clicking 'Box' icon i want to submit perticular row only. I already got row ID to 'Box' icon. How can i do that with the while loop.
thanks in advance
Tharindu
You should arrange the HTML code for this in the following fashion:
<table>
<form method="post">
<tr>
<td>Z0678<input type="hidden" name="id" value="Z0678"></td><td><input type="text" value="0" name="qty"></td><td><input type="image" src="box.gif"></td>
</tr>
</form>
<form method="post">
<tr>
<td>Z0678<input type="hidden" name="id" value="Z0678"></td><td><input type="text" value="0" name="qty"></td><td><input type="image" src="box.gif"></td>
</tr>
</form>
<form method="post">
<tr>
<td>Z0678<input type="hidden" name="id" value="Z0678"></td><td><input type="text" value="0" name="qty"></td><td><input type="image" src="box.gif"></td>
</tr>
</form>
<form method="post">
<tr>
<td>Z0678<input type="hidden" name="id" value="Z0678"></td><td><input type="text" value="0" name="qty"></td><td><input type="image" src="box.gif"></td>
</tr>
</form>
</table>
Then once you hit the image, it will submit the form. Add this code to the top of your PHP script "<?php print_r($_POST); ?> and you will see that you can now process the posted contents based on the data that was posted without the need for any while loop.
let the you have posted be list.php
in the text box like
<input type=text name="rid" value= " <?php echo $rid ?>" onclick="location.href='view.php'"/>
get the row id in next page that is view.php
$id = $_GET['rid'];
pass it as hidden in view.php
<input type="hidden" name="id" value="<?php echo $id; ?> "/>
Make sure all your db connection goes perfect and echo all data whatever you want from row.
In the original php file generate a different html form for each box.
<form action="page2.php" method="post">
<input name="Z067DA" />
</form>
In the page2.php file use code similar to this. $value contains the user
submitted information.
foreach($_POST as $key=>$value)
{
// Use submitted value.
}
If you know the input tag names in advance you can just access them directly in your php code.
$value = $_POST['Z067DA'];
Related
I am trying to get a input textbox value in a PHP variable and then update a table based on this variable value in my custom WordPress page. I have written following code.
It is working but not updating the text input value. What is wrong with my code?
<form method="post" enctype="multipart/form-data">
<td>
<table> <tr><td> </td><input type="text" name="offeramt" style="height:15px"/> <td>
<input type="hidden" name="pid" value= "<?php echo $retrieved_data->id; ?>">
<input type="hidden" name="textamount" value="<?php echo htmlspecialchars($_POST['offeramt']);?>">
<input type="submit" name="update" value="update" /></td> </table></td>
</form>
<?php
if (isset($_POST['update'])) {
$sellamt=$_POST['textamount'];
if (empty($sellamt)){
echo "pls input a value in text box";
}
else{
$myid = $_POST['pid'];
?> <?php
$wpdb->update('wp_share', array('status'=>'onsell','offervalue'=>$sellamt),array('id'=>$myid));
}}
}?>
I was updating the text input value to a hidden field ["textamount"]then trying to get that hidden field ["textamount"] value to $sellamt. However I have removed the hidden field and took the value directly from textbox like this
$sellamt=$_POST['offeramt'];
where ['offeramt'] is the textbox itself
and its working.Thanks
$sql="SELECT vName,id FROM employee WHERE vName LIKE '%$my_data%' ORDER BY vName";
$result = mysql_query($sql);
if($result)
{
while($row=mysqli_fetch_array($result))
$hid='<input type="hidden" name="xyz" id="abc" value="'.$row['id'].'" />';
echo($hid);
echo $row['vName']."\n";
}
How to pass the value of a hidden input field to another PHP script? I am using auto complete. how to pass the value auto complete page to index page
You have two options:
Sessions
PHP Sessions
Session support in PHP consists of a way to preserve certain data across subsequent accesses.
eg:
<?php
// Page1.php
session_start();
$_SESSION["key"] = "random value";
Then:
<?php
// Page2.php
session_start();
echo $_SESSION["key"];
// Output would then be ... random value
POST
Using the PHP $_POST
Taking what you currently have, you'd do:
<form method="post" action="somescript.php">
<input type="hidden" name="xyz" id="abc" value="<?=$row['id'] ?>" />
<button type="submit" name="submit" value="submitForm" />
</form>
Then on somescript.php if you do:
<?php
print_r($_POST);
You'll see an array with the data from your form, hidden value included
Create a form
<form action="action_page.php" method="get">
<input type="hidden" name="xyz" id="abc" value="'.$row['id'].'" />
<input type="submit" value="Submit">
</form>
And Get value on action_page.php
$_GET['xyz']
You enter your html code inside php code like this
<?php
while($row=mysqli_fetch_array($result))
{
?>
<form action="action_page.php" method="get">
<input type="hidden" name="xyz" id="abc" value="'.$row['id'].'" />
<input type="submit" value="Submit">
</form>
<?php
echo $row['vName']."\n";
}
?>
I have a table with radio buttons to get the row values and 2 buttons
1 button.)For printing data , which moves to "notice.php"
2 button.)For row details,which stays on the same page.
<form action="" method="POST">
<table border="1" >
<tr>
<th>sourceID</th>
....
<th>Status</th>
</tr>
<tr>
<td><input type="radio" name="ID[]" value="<?php echo $tot; ?>" /></td>
<td>1</td>
....
<td>open</td>
</tr>
<input type="button" name="issue" value="Issue Notice" onClick="location.href='notice.php'" />
<input type="submit" name="details" value="details" />
<?php
if(isset($_POST['details']))
{
$n=$_POST['ID'];
$a=implode("</br>",$n);
echo$a;
}
Notice.php:
<?php
if ($_SERVER["REQUEST_METHOD"] == "POST") {
$n=$_POST['ID'];
}?>
The problem here is: My code is working perfectly fine with the button details.
But it doesnt work with issue, i.e after selecting radio button and clicking on the issue notice button :it gives Undefined index: ID in D:\XAMPP\notice.php.
kindly help
Your details button is a submit button, so it submits the form. However your other button is just a regular button and you use javascript to send the browser to notice.php. As such, it does not post any data to notice.php.
You could include the data on the query string and send it that way, e.g.:
location.href="notice.php?id=<?=$tot?>"
Or you could also have the issue button post the page, and then have your receiving page check which submit button was used. If the issue button was used you could then have the php code post to notice.php.
Using the following code is the exact same as having a link:
<input type="button" name="issue" value="Issue Notice" onClick="location.href='notice.php'" />
As in, this will not change the form action and submit the POST data to your new page.
You would need something like:
<form method="post" action="" name="unique-form-name">
<input type="radio" name="ID[]" value="<?php echo $tot; ?>">
<input type="button" id="unique-btn-name" value="Issue Notice">
</form>
<script type="text/javascript">
document.getElementById('unique-btn-name').onclick = function(){
document['unique-form-name'].action='notice.php';
document['unique-form-name'].submit();
}
</script>
Then, once you get the data to notice.php, you'll have to use the data as an array (you won't be able to echo the data):
$IDs = $_POST['ID'];
echo '<pre>',print_r($IDs),'</pre>';
<input type="radio" name="ID" value="<?php echo $tot; ?>" />
Your error is the name attribute.
Also the other button is not related to the form at all. You may want to use ajax here.
My question is how do I call input value of user selected which has show by php code from another php.
Normal simple way we get the input this way
$calendar_id_val = $_GET['calendar_id'];
and now it is not working:
For example Show.php, I have one form which show the values from Database and show the result with php variable with While Loop.
<input name="calendar_id" value="<?php echo $calendar_id;?>">
and when user is submit that form I will carry these user selected value and perform insert.php
While you are doing echo in the input use echo $calendar_id_val
You should use form like,
<form action="insert.php" method="get">
<input type="text" name="calendar_id" value="<?php echo $calendar_id;?>"/>
<input type="submit" name="submit_id" value="Insert"/>
</form>
Insert.php
echo $calendar_id_val = $_GET['calendar_id'];
Does this answer your question?
<form action="insert.php" method="GET">
<input name="calendar_id" value="<?php echo $calendar_id;?>">
</form>
If you want to redirect the user back to show.php, add this to the end of your insert.php script
header('Location: show.php');
exit();
I suggest $_POST var like this:
<form action="insert.php" method="POST">
<input type="text" name="calendar_id" value="<?php echo $calendar_id;?>" />
<input type="submit" name="submit" value="Submit" />
</form>
insert.php file:
echo $calendar_id = $_POST['calendar_id'];
I have a form with multiple items and an id attributed to each of these items, on Submit I want to be able to grab the id of the item that was clicked - I have tried using js, something like:
<form method="post" action="add_item_cart.php">
<input type="hidden" id="item_id" name="item_id">
<input name="submit_item" id="btn_sub" onclick="document.getElementById('item_id').value = <?php echo '3'; ?>" type="submit" value="Add">
</form>
I want to be able to grab this value: $item_id = $_POST["item_id"]; on add_item_cart.php, but this doesn't seem to be working.
Is this a problem with my js syntax or is my logic not plausible to solve this problem? Is it submitting before changing the value?
EDIT:
Let's see if I can explain myself better, I want to assign that hidden value dynamically, imagine that my form has 3 submit buttons (one for each item displayed). Depending on the one that is clicked, I want to pass the item's id to my hidden field, so if I click button1 - $_POST["item_id"]=1, button2 - $_POST["item_id"]=2... etc
Here is my actual form (non simplified example)
<form method="post" action="add_item_cart.php">
<table style="width:600px">
<tr>
<?php foreach ($items as $item): ?>
<td>
<center>
<span style="font-size:20px"><?php echo $item["item_name"] ?></span><br/>
€<?php echo $item["price"] ?><br/>
Quantidade: <input type="text" value="1" style="width:30px"><br/>
<input type="hidden" id="item_id" name="item_id">
<input name="submit_item" id="btn_sub" onclick="document.getElementById('item_id').value = <?php echo $item["id"]; ?>" type="submit" value="Adicionar">
</center>
</td>
<?php endforeach; ?>
</tr>
</table>
</form>
When your form is posted and you want to collect the item_id value on add_item_cart.php first you need to actually assign a value to id as in (Assuming item_id is a php variable). The id is just used for setting the css editing not a value...
<input type="hidden" id="item_id" value="<?php echo $item_id; ?>" name="item_id">
you cannot have id='' for the value because 'value' is value.
Then you can get that value on your other page with:
<?php
if(isset($_POST['item_id'])){
$item_id = $_POST['item_id'];
}
?>
If you want to edit the variable after post depending on which button you hit you can try.
<input name="submit_item1" id="btn_sub" name="button1" type="submit" value="Add">
<input name="submit_item2" id="btn_sub" name="button1" type="submit" value="Add">
<input name="submit_item3" id="btn_sub" name="button1" type="submit" value="Add">
Then on the top of your page you can do.
<?php
if(isset($_POST['submit_item1'])){
$item_id = 1;
}
if(isset($_POST['submit_item2'])){
$item_id = 2;
}
if(isset($_POST['submit_item3'])){
$item_id = 3;
}
?>
If you are creating forms from an array of items you could do something like, (assuming you somehow have an id associated with those items; I would need to know more information about how you are making your item list. But it would generally do like this.
<?php
foreach($item_array as $item){
?>
<form method="post" action="add_item_cart.php">
<input type="hidden" id="item_id" name="item_id" value="<?php echo $item['id']; ?>">
<input name="submit_item" id="btn_sub" type="submit" value="Add">
</form>
<?php
}
?>
Then on the top of your page you can just get $_POST['item_id'] and since that value is dynamically set you do not need any conditionals you can just get that value and run any query.
UPDATE
Use normal button instead of submit button and use javascript for submitting the form.
<form method="post" name="f1" action="add_item_cart.php">
<input type="hidden" id="item_id" name="item_id">
<input name="submit_item" id="btn_sub" onclick="document.getElementById('item_id').value = <?php echo '3'; ?>; document.f1.submit();" type="button" value="Add">