I have a query like this:
$query = "SELECT gyms.name FROM `fighters_team` INNER JOIN gyms ON gyms.id = fighters_team.gym_id WHERE fighter_id = $fighter_id";
if ($result = $mysqli->query($query)) {
while($row = $result->fetch_assoc()) {
echo $row['name'];
echo " / ";
}
}
What comes up is: "Team 1 / Team 2 /"
What I want to do is get rid of the trailing slash on the last item. So it should just say "Team 1 / Team 2" if there are two items.
Does anyone have any idea how I could approach that?
Thanks!
$query = "SELECT gyms.name FROM `fighters_team` INNER JOIN gyms ON gyms.id = fighters_team.gym_id WHERE fighter_id = $fighter_id";
$names = array();
if ($result = $mysqli->query($query)) {
while($row = $result->fetch_assoc()) {
array_push($names, $row['name']);
}
echo implode(' / ', $names);
}
I hope this would work.
Try:
$query = "SELECT gyms.name FROM `fighters_team` INNER JOIN gyms ON gyms.id = fighters_team.gym_id WHERE fighter_id = $fighter_id";
if ($result = $mysqli->query($query)) {
while($row = $result->fetch_assoc()) {
$teams .= $row['name'].' / '.'';
echo rtrim($teams,'/ ');
}
}
Is that what you are looking for?
Related
Good day!
I have a problem here that I can't solve (last 5hrs).
here's my codes:
include 'assets\function\retrieveFunction.php';
$loadGradProgram = array();
$x = count(getCourseInfo());
for($i=0;$i<=$x;$i++){
$loadGradProgram[$i] = getCourseInfo();
}
echo $loadGradProgram[0];
getCourseInfo function
Solution 1:
function getCourseInfo(){
$getInfo = array();
include 'assets\database\connect.php';
$i = 0;
$x = 0;
$sql = "SELECT c.courseID, c.courseCode, c.courseTitle, m.description";
$sql .=" FROM tblcourse as c INNER JOIN tblcoursemajor as m ON c.courseid=m.courseID ORDER BY c.courseID";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$getInfo[$i] = $row;
$i++;
}
return $getInfo;
}
}
Result: Array to string conversion
Solution 2:
function getCourseInfo(){
$getInfo = array();
$loadInfo = array();
include 'assets\database\connect.php';
$i = 0;
$x = 0;
$sql = "SELECT c.courseID, c.courseCode, c.courseTitle, m.description";
$sql .=" FROM tblcourse as c INNER JOIN tblcoursemajor as m ON c.courseid=m.courseID ORDER BY c.courseID";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$getInfo[$i] = $row;
$i++;
}
$conn->close();
for($x,$x<=$i;$x++;){
$loadInfo[] = implode(',', $getInfo[$x]);
}
return $loadInfo;
}
}
Result: Still the same
and this line causing error: echo $loadGradProgram[0];
I use echo just to see if the query is working.
if you want a multi-dimmentional array like in w3c documentation, you do it like this :
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$getInfo[$i][] = $row['courseID'];
$getInfo[$i][] = $row['courseCode'];
...
$i++;
}
return $getInfo;
then, if you want to diplay an information in the array you can do a foreach loop or a for loop like :
foreach($loadGradProgram as $key => $value) // here the key is useless
{
echo $value[0];
echo $value[1];
}
or directly like this :
echo $loadGradProgram[0][0];
echo $loadGradProgram[0][1];
echo $loadGradProgram[1][0];
I want to select two table values so I am using join query see below, from this code I stored one session variable like $_SESSION['emp_id'], I want select query like who are in te.emp_id='".$_SESSION['emp_id']."', From this code $count will return 0 but in my database I have one row.
$q = mysql_query("SELECT *
FROM task_employee te
JOIN task t
ON te.emp_id = t.t_assign_to
WHERE t.t_status = '0'
AND t.t_delete_on != '1'
AND te.emp_id = '" . $_SESSION['emp_id'] . "'");
$data = array();
while($r = mysql_fetch_assoc($q))
{
$data[] = $r;
}
$count = sizeof($data);
if($count > 0)
{
$return = array('status'=>'success', 'count'=>sizeof($data), 'data'=>$data);
echo json_encode($return);
}
else
{
$return=array('status'=>'not-found', 'count'=>sizeof($data), 'data'=>$data);
echo json_encode($return);
}
I am writing like this means I can get but using join query that time I can't get values
<?php
$sql = mysql_query("SELECT *
FROM task
WHERE t_delete_on !='1'
AND t_assign_to = '$emp_id'");
for ($i = 1; $row = mysql_fetch_assoc($sql); $i++)
{
$assign_to = $row['t_assign_to'];
$mysql = mysql_query("SELECT *
FROM task_employee
WHERE emp_id = '$assign_to'");
while ($r = mysql_fetch_assoc($mysql))
{
$emp_name = $r['emp_firstname']; // here i got value
}
}
?>
I want to make a Navigation with 2 levels.
My Code so far
<?php
$sql = ("SELECT name, id, pid FROM tl_table WHERE pid='' ORDER BY name");
$result = mysql_query($sql);
$list = array();
while ($row = mysql_fetch_assoc($result)) {
$list[] = $row;
}
foreach ($list as $kat) {
echo '<li>' . $kat['name'] . '</li>';
}
?>
Nested Sets are at the moment too tricky for me.
I want at the end this.
<li>$kat['name']
<li>$kat['name'] from PID</li>
</li>
MySQL:
http://i46.tinypic.com/35052m0.png - IMG
No I want to get the things our of the MySQL DB see the image Link.
MySQL:
id—–pid——name
1——0——–name1
2——0——–name2
3——0——–name3
4——3——–name3.1
5——3——–name3.2
<?php
$sql = ("SELECT name, id, pid FROM tl_table WHERE pid='' ORDER BY name");
$result = mysql_query($sql);
$list = array();
while ($row = mysql_fetch_assoc($result)) {
$list[$row['id']] = $row;
$sql = ("SELECT name, id, pid FROM tl_table WHERE pid='".$row['id']."' ORDER BY name");
$res = mysql_query($sql);
while($rw = mysql_fetch_assoc($res)){
$list[$row['id']]['sub'][] = $rw;
}
}
echo "<pre>";
print_r($list);
?>
I have been stuck with a problem and I am newbie in mysql and php, Here is the code first , so that I can explain in detail:
$metros = array(1,263);
foreach($metros as $metro_id) {
$sql = "SELECT cuisine_id, cuisine_name_en FROM poi_restaurant_cuisines";
$result = mysql_query($sql);
$cuisine_id = array();
$cusine_name = array();
while($row = mysql_fetch_assoc($result)) {
$cuisine_id[] = $row['cuisine_id'];
$cuisine_name[] = $row['cuisine_name_en'];
}
foreach ($cuisine_id as $cuisine) {
$sql = "
SELECT COUNT(*)
FROM poi AS p
LEFT JOIN poi_restaurant AS pr USING (poi_id)
WHERE p.poi_address_prefecture_id = '$metro_id'
AND pr.poi_restaurant_cuisine_id_array
AND find_in_set('$cuisine', poi_restaurant_cuisine_id_array)
AND p.poi_status = 1";
$result = mysql_query($sql);
$count_cuisine = array();
while($row = mysql_fetch_array($result)) {
$count_cuisine[$metro_id][$cuisine] = $row['COUNT(*)'];
}
echo "<table border = 1 cellpadding= 5 cellspacing= 5 width= 100>";
echo "<tr><th>CuisineID</th><th>Count</th></tr>";
echo "<tr><td>";
echo $cuisine;
echo "</td><td>";
echo $count_cuisine[$metro_id][$cuisine];
echo "</td><td>";
echo "</tr>";
echo "</table>";
}
}
The poi_restaurant_cuisine_id_array contains csv values. I am able to produce the count and the cuisine ID on the web page. I want to replace the cuisine ID with the name of the cuisine. I am not very good at sql or either PHP as I am a beginner. I hope I am being clear enough. Any help is highly appreciated ...Thank you.
Try this:
echo '<table border="1" cellpadding="5" cellspacing="5" width="100">';
echo "<tr><th>Cuisine</th><th>Count</th></tr>";
$metros = array(1,263);
foreach($metros as $metro_id) {
$sql = "SELECT cuisine_id, cuisine_name_en FROM poi_restaurant_cuisines";
$result = mysql_query($sql);
$cuisines = array();
while($row = mysql_fetch_assoc($result)) {
$cuisines[] = array(
'id' => $row['cuisine_id'],
'name' => $row['cuisine_name_en'],
);
}
foreach ($cuisines as $cuisine) {
$sql = "
SELECT COUNT(*)
FROM poi AS p
LEFT JOIN poi_restaurant AS pr USING (poi_id)
WHERE p.poi_address_prefecture_id = '$metro_id'
AND pr.poi_restaurant_cuisine_id_array
AND find_in_set('{$cuisine['id']}', poi_restaurant_cuisine_id_array)
AND p.poi_status = 1";
$result = mysql_query($sql);
$count_cuisine = array();
while($row = mysql_fetch_array($result)) {
$count_cuisine[$metro_id][$cuisine['id']] = $row['COUNT(*)'];
}
echo "<tr>
<td>{$cuisine['name']}</td>
<td>{$count_cuisine[$metro_id][$cuisine['id']]}</td>";
</tr>";
}
}
echo "</table>";
Assuming cuisine_id is a unique identifier, then just use it as the array index....
while($row = mysql_fetch_assoc($result)) {
$cuisines[$row['cuisine_id']] = $row['cuisine_name_en'];
}
....
foreach ($cuisines as $cuisine_id=>$cuisine_name_en) {
However storing multiple values in a single column is a very bad idea.
Generating and running queries in a loop is another very bad idea.
It is possible to reduce this to a single query, declared and invloked outside the inner loop but because your data is not mormalized, this is rather complex.
The query I have below will only show me one result even if there are multiple matching entries (completely or partially matching). How do I fix it so it will return all matching entries:
//$allowed is a variable from database.
$sql = "SELECT `users`.`full_name`, `taglines`.`name`, `users`.`user_id` FROM
`users` LEFT JOIN `taglines` ON `users`.`user_id` = `taglines`.`person_id`
WHERE ( `users`.`user_settings` = '$allowed' ) and ( `users`.`full_name`
LIKE '%$q%' ) LIMIT $startrow, 15";
$result = mysql_query($sql);
$query = mysql_query($sql) or die ("Error: ".mysql_error());
$num_rows1 = mysql_num_rows($result);
if ($result == "")
{
echo "";
}
echo "";
$rows = mysql_num_rows($result);
if($rows == 0)
{
}
elseif($rows > 0)
{
while($row = mysql_fetch_array($query))
{
$person = htmlspecialchars($row['full_name']);
}
}
}
print $person;
Because your overwriting $person on each iteration.
Hold it in a $person[] array if your expecting more then one. Then loop through it with a foreach loop when you intend to output.
Not related but your also querying twice, you only need 1 $result = mysql_query($sql);
Update (Simple Outputting Example):
<?php
$person=array();
while($row = mysql_fetch_array($query)){
$person[] = array('full_name'=>$row['full_name'],
'email'=>$row['email'],
'somthing_else1'=>$row['some_other_column']);
}
//Then when you want to output:
foreach($person as $value){
echo '<p>Name:'.htmlentities($value['full_name']).'</p>';
echo '<p>Eamil:'.htmlentities($value['email']).'</p>';
echo '<p>FooBar:'.htmlentities($value['somthing_else1']).'</p>';
}
?>
Or an alternative way to is to build your output within the loop using concatenation.
<?php
$person='';
while($row = mysql_fetch_array($query)){
$person .= '<p>Name:'.$row['full_name'].'</p>';
$person .= '<p>Email:'.$row['email'].'</p>';
}
echo $person;
?>
Or just echo it.
<?php
while($row = mysql_fetch_array($query)){
echo '<p>Name:'.$row['full_name'].'</p>';
echo '<p>Email:'.$row['email'].'</p>';
}
?>