Compare two strings (urls) for same domain - php

Question

I'm trying to compare two urls using PHP, ensuring that the domain name is the same. It cannot be the sub-domain. It has to literally be the same domain. Example:
http://www.google.co.uk would validate as true compared to http://www.google.co.uk/pages.html.
but
http://www.google.co.uk would validate as false compared to http://www.something.co.uk/pages.html.

Answer 1

Use parse_url(), and compare the "host" index in the array returned from the two calls to parse_url().

Answer 2

Use parse_url()
$url1 = parse_url("http://www.google.co.uk");
$url2 = parse_url("http://www.google.co.uk/pages.html");
if ($url1['host'] == $url2['host']){
//matches
}

Answer 3

simple, use parse_url()
$url1 = parse_url('http://www.google.co.uk');
$url2 = parse_url('http://www.google.co.uk/pages.html');
if($url1['host'] == $url2['host']){
// same domain
}

Answer 4

You could use parse_url for this
$url1 = parse_url('http://www.google.com/page1.html');
$domain1 = $url1['host'];
$url2 = parse_url('http://www.google.com/page2.html');
$domain2 = $url2['host'];
if($domain1 == $domain2){
// something
}

Answer 5

Expanding the answer given by Ariel, the code you could use is similar to the following one:
<?php
compare_host('http://www.google.co.uk', 'http://www.something.co.uk/pages.html');
function compare_host($url1, $url2)
{
// PHP prior of 5.3.3 emits a warning if the URL parsing failed.
$info = #parse_url($url1);
if (empty($info)) {
return FALSE;
}
$host1 = $info['host'];
$info = #parse_url($url2);
if (empty($info)) {
return FALSE;
}
return (strtolower($host1) === strtolower($info['host']));
}