Load/Modify/Save XML with javascript - php

Before this question gets stamped as a duplicate, I am sorry! I've read ALL the duplicate questions and if anything, it has confused me even more. So maybe this question is slightly different.
I've written a little Javascript library that makes ajax calls and fetches and parses information from the graph facebook API.
This enables me to pretty much show all my page status' on my web page. However I'm just about to launch, and I have done as much testing as I can.
However. I'm sure errors will occur, and I've written many error catches blah blah blah.
What I want to do, is save all my errors in a xml file.
So when an error occurs, I want the javascript to load the xml file from the server, add the errors, then save the changes.
I know how to load the xml doc using XmlHttpRequests, And I'm sure I can figure out how to modify the xml just by using dom manipulation.
All i really want to know is. How do i save these changes? does it save automatically?
Or do i have to "somehow" pass the updated xml version to php and get that to save it?
Im not quite sure how to go about it.
I would use mySQL and php but that means "somehow" passing the error information to php, then saving it.
However id much prefer XML seeing as I'm the only person that will be reading the xml file.
Thanks very much.
Alex

Or do i have to "somehow" pass the updated xml version to php and get that to save it?
Yes, you'll want to use an XML HTTP request to send the XML DOM to the server where PHP can save it:
function postXML(xmlDOM, postURL, fileName, folderPath){
try{
// Create XML HTTP Request Object
oXMLReq = new ActiveXObject("MSXML2.XMLHTTP.3.0");
// Issue Synchronous HTTP POST
oXMLReq.open("POST",postURL,false);
// Set HTTP Request Headers
if(fileName != null){ oXMLReq.setRequestHeader("uploadFileName", fileName); } // What should file be named when saved on server?
if(folderPath != null){ oXMLReq.setRequestHeader("uploadDir", folderPath); } // What folder should file be saved in on server?
// SEND XML
///WScript.Echo(xmlDOM.xml);
oXMLReq.send(xmlDOM.xml);
return oXMLReq.responseText;
}catch(e){
return "postXML failed - check network connection to server";
}
}

Related

Save binary request body as file

I wrote a program that reads a binary file into the RAM and then sends it using an HTTP request to my server. It uses the PUT method and the binary file is (in) the body.
Now how can I tell my server to receive and safe the file in a folder?
If possible without any additional libraries that I would need to download (unless it's more efficient).
I know, there are some similar threads to this one, but they either they where about receiving text or they were about doing it with libraries or there simply was no sufficient answer.
I'd also like to know, if it would be more efficient or smarter to use the POST method or any other instead of PUT.
You can get at the data by opening a stream to php://input, like so:
$datastr = fopen('php://input',rb);
if ($fp = fopen('outputfile.bin', "wb")){
while(!feof($datastr)){
fwrite($fp,fread($datastr,4096)) ;
}
}
As to whether to use POST or anything else depends on what is happening with the data, and whether you care about being RESTful or such. See other questions/answers, indempotency.
The advantage I would see with using POST is that it's more commonly used (on most submission forms where you upload a file), and therefore has more support from within PHP and html.

Agile Toolkit: Any way to upload files and fetch directly from $_FILES['uploadedfile']['tmp_name']?

I wrote a simple script in plain PHP that uses $_FILES['uploadedfile']['tmp_name'] to fetch a freshly uploaded file and process its contents directly without permanently storing it. The idea is to allow the user to upload a file containing several rows of data that will be automatically parsed and added to a database by the PHP script. There is no need to store the file itself or a reference to it in the database as only the file contents are important. I know of Import CSV to MySQL, but I am trying to keep things clean and easy for the user (and for the time being I am developing with phpDesktop + sqlite so that my application will be portable).
I am now trying to recreate this process within Agile Toolkit but I cannot seem to figure out how. I know that the filestore model must access ['tmp_name'] before it moves/renames the file but I cannot figure out how to poach just this functionality. I tried looking in /lib/Form/Field/Upload.php to see if any of the methods there might be of use, but I am quite new to PHP so these docs are baffling to me. getFilePath() looked promising, but it seems that $_FILES remains empty when I do something like:
$form = $page->add('Form');
$upl = $form->addField('Upload', 'file');
$form->addSubmit();
if ($form->isSubmitted()){
$form->js()->univ()->alert($upl->isUploaded())->execute(); //sends js alert('false')
}
I realize that AJAX cannot be used to post files and I have a feeling this is part of the problem but I am not really sure where to go from here. Any help would sincerely be appreciated.
Thanks.
Agile Toolkit uploads file as soon as it is selected - moves it immediately into filestore and creates database record, so not really what you need.
Anything you write in a plain PHP can also work with Agile Toolkit. You can disable JavaScript in the form by doing this:
$this->add('Form',array('js_widget'=>false));
Such a form would send you a normal POST request.
Ok, I managed to achieve what I wanted by creating a custom extension of Form_Field_Upload and redefining the loadPOST() method within it.
function loadPOST(){
Form_Field::loadPOST();
if($_GET[$this->name.'_upload_action']){
// This is JavaScript upload. We do not want to trigger form submission event
$_POST=array();
}
if($_GET[$this->name.'_upload_action'] || $this->isUploaded()){
if($this->model){
try{
$model=$this->model;
/*Function is identical to parent above this line*/
//process file here and do $model->set('custom_field',$value);
//I am using $this->getFilePath() to analyze the uploaded file
/*Function is identical to parent below this line*/
$model->save();
}catch(Exception $e){
$this->api->logger->logCaughtException($e);
$this->uploadFailed($e->getMessage()); //more user friendly
}
$this->uploadComplete($model->get());
}
}
if($_POST[$this->name.'_token']){
$a=explode(',',$_POST[$this->name.'_token']);$b=array();
foreach($a as $val)if($val)$b[]=$val;
$this->set(join(',',filter_var_array($b,FILTER_VALIDATE_INT)));
}
else $this->set($this->default_value);
}
I sure this is not the most elegant solution but it worked for my purpose anyway.

Status report during form process

I created a little script that imports wordpress posts from an xml file:
if(isset($_POST['wiki_import_posted'])) {
// Get uploaded file
$file = file_get_contents($_FILES['xml']['tmp_name']);
$file = str_replace('&', '&', $file);
// Get and parse XML
$data = new SimpleXMLElement( $file , LIBXML_NOCDATA);
foreach($data->RECORD as $key => $item) {
// Build post array
$post = array(
'post_title' => $item->title,
........
);
// Insert new post
$id = wp_insert_post( $post );
}
}
The problem is that my xml file is really big, and when i submit the form, the browser just hangs for a couple of minutes.
Is it possible to display some messages during the import, like displaying a dot after every item is imported?
Unfortunately, no, not easily. Especially if you're building this on top of the WP framework you'll find it not worth your while at all. When you're interacting with a PHP script you are sending a request and awaiting a response. However long it takes that PHP script to finish processing and start sending output is how long it usually takes the client to start seeing a response.
There are a few things to consider if what you want is for output to start showing as soon as possible (i.e. as soon as the first echo or output statement is reached).
Turn off output buffering so that output begins sending immediately.
Output whatever you want inside the loop that would indicate to you the progress you wish to be know about.
Note that if you're doing this with an AJAX request content may not be ready immediately to transport to the DOM via your XMLHttpRequest object. Also note that some browsers do their own buffering before content can be ready for the user to display (like IE for example).
Some suggestions you may want to look into to speed up your script, however:
Why are you doing str_replace('&','&',$file) on a large file? You realize that has cost with no benefit, right? You've acomplished nothing and if you meant you want to replace the HTML entity & then you probably have some of your logic very wrong. Encoding is something you want to let the XML parser handle.
You can use curl_multi instead of file_get_contents to do multiple HTTP requests concurrently to save time if you are transferring a lot of files. It will be much faster since it's none-blocking I/O.
You should use DOMDocument instead of SimpleXML and a DOMXPath query can get you your array much faster than what you're currently doing. It's a much nicer interface than SimpleXML and I always recommend it above SimpleXML since in most cases SimpleXML makes things incredibly difficult to do and for no good reason. Don't let the name fool you.

Can't send content-type: text/xml header from PHP at the same time getting the data from MYSQL

i hope you can cast some light on my problem. I need to do an AJAX / PHP / MYSQL application to display posts and stuff on the page i'm writing.
I only discovered how to do some simple stuff in PHP after taking some mushrooms but that was years ago and now i don't have mushrooms and i'm just stuck!
So here's the problem:
i think i need to send a proper "xml" file through php so the ajax part can take it but: when i try to put the header on top of the php it displays this error:
" Extra content at the end of the document "
When i looked at some tutorials people were using the "header" fearlesly to do such stuff as i want to do and no comments suggested that it didn't work. so why it doesn't work on my local server?
I'm running:
WAMP
Apache 2.2.11
PHP 5.3.0
It also doesn't work on a remote server (PHP 5.3.0) :/
I read all the stuff i could find till 5am and decided to ask you for help for the first time :)
Thank you!
header('content-type: application/xhtml+xml; charset=utf-8');
require_once("allyouneed.php");
require_once("bazingablob.php");
$category=$_GET["category"];
$post_tags=$_GET["post_tags"];
$language=$_GET["language"];
$author=$_GET["author"];
$posts_per_page=$_GET["posts_per_page"];
$current_page=$_GET["current_page"];
$order=$_GET["order"];
$hard_limit=$_GET["hard_limit"];
$show_hidden=$_GET["show_hidden"];*/
$wypluj="";
$wypluj="<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\"?>";
$bazinga_blob = new bazingablob;
if (!$bazinga_blob->connect_to_database())
{
$wypluj.="<IsOK>0</IsOK>";
echo $wypluj;
exit;
}
else
{
$wypluj.="<IsOK>jedziem</IsOK>";
}
$bb_result=$bazinga_blob->get_all_posts($category,$post_tags,$language,$author,$posts_per_page,$current_page,$order,$hard_limit,$show_hidden);
if ($bb_result) //udalo sie cos znalezc w bazie wedlug kryteriow
{
$wypluj.="<Pagination>";
$wypluj.="<CurrentPage>";
$wypluj.=$bazinga_blob->posts_pagination["current_page"];
$wypluj.="</CurrentPage>";
$wypluj.="<LastPage>";
$wypluj.=$bazinga_blob->posts_pagination["last_page"];
$wypluj.="</LastPage>";
$wypluj.="<PostsCount>";
$wypluj.=$bazinga_blob->posts_pagination["posts_count"];
$wypluj.="</PostsCount>";
$wypluj.="</Pagination>";
$wypluj.="<Posts>";
foreach ($bb_result as $item)
{
$wypluj.="<Post>";
$wypluj.="<PostId>".$item->post_id."</PostId>";
$wypluj.="<PostAuthor>".$item->post_author."</PostAuthor>";
$wypluj.="<PostLangId>".$item->post_langid."</PostLangId>";
$wypluj.="<PostSlug>".$item->post_slug."</PostSlug>";
$wypluj.="<PostTitle>".$item->post_title."</PostTitle>";
$wypluj.="<PostGreetingPicture>".$item->post_greeting_picture."</PostGreetingPicture>";
$wypluj.="<PostGreetingVideo>".$item->post_greeting_video."</PostGreetingVideo>";
$wypluj.="<PostGreetingSound>".$item->post_greeting_sound."</PostGreetingSound>";
$wypluj.="<PostShort>".$item->post_short."</PostShort>";
$wypluj.="<PostBody>".$item->post_body."</PostBody>";
$wypluj.="<PostDate>".$item->post_date."</PostDate>";
$wypluj.="<PostPublished>".$item->post_published."</PostPublished>";
$wypluj.="<PostSticky>".$item->post_sticky."</PostSticky>";
$wypluj.="<PostComments>".$item->post_comments."</PostComments>";
$wypluj.="<PostProtected>".$item->post_protected."</PostProtected>";
$wypluj.="</Post>";
}
$wypluj.="</Posts>";
}
echo $wypluj;
The error comes from your browser and indicates that your XML is malformed.
Setting the application/xhtml+xml header tells the browser to process the document as serious XML. XML needs to be "well-formed", i.e. it must not contain any syntax errors. Apparently you do have a syntax error on line 1 at column 73, which makes the browser abort the attempt to process the document.
For this reason it's a pain to hand-code XML, you should really look into a library that takes care of the well-formedness for you, like PHP's own XMLWriter.
Have you validated your XML?
http://friendsofed.infopop.net/4/OpenTopic?a=tpc&s=989094322&f=5283032876&m=4521066061
I'm honestly not sure what you're trying to do with the header, it's not any Ajax method I've ever been taught. The header method you're doing looks just a few lines short of outputting the XML to a download prompt.
Here's my favorite way to do AJAX. Simple, understandable, and quick.
Include Jquery.
Setup your data--whether by form with a Serialize (gets form data into a Javascript Variable) or by just setting some variables as it seems you're doing above.
Send via Jquery Ajax to a separate processing page. The page will receive the data you setup as a $_REQUEST variable, with the method depending on whether you defined it as a POST or not (defaults to a GET)
The processing page --does-- stuff with the REQUEST data and may or may not respond back to the page. This is where you can do stuff like update divs, alert that it worked, etc.
Here's a great tutorial. Focus on the code under "Hello Ajax, Meet Jquery"
If you get yourself any more of those mushrooms, a PHP familiar way to do AJAX is with XAJAX. It allows you to do asynchronous calls to PHP functions. Be aware, though, that the forums are not the most english-friendly and documentation is a bit cryptic.

how to hide a json object from source code of a page?

iam using json object in my php file but i dont want my json object to be displayed in source code as it increases my page size a lot.
this is what im doing in php
$json = new Services_JSON();
$arr = array();
$qs=mysql_query("my own query");
while($obj = mysql_fetch_object($qs))
{
$arr[] = $obj;
}
$total=sizeof($arr);
$jsn_obj='{"abc":'.$json->encode($arr).',"totalrow":"'.$total.'"}';
and this is javascript
echo '<script language=\'javascript\'>
var dataref = new Object();
dataref = eval('.$jsn_obj.');
</script>';
but i want to hide this $jsn_obj objects value from my source,how can i do that??? plz help !!
I'm not sure there's a way around your problem, other than to change your mind about whether it's a problem at all (it's not, really).
You can't use the JSON object in your page if you don't output it. The only other way to get the object would be to make a separate AJAX request for it. If you did it that way, you're still transferring the exact same number of bytes that you would have originally, but now you've added the overhead of an extra HTTP request (which will be larger than it would have been originally, since there are now HTTP headers on the transfer). This way would also be slower on your page load, since you'd have to load the page, then send the AJAX request and run the result.
There's much better ways to manage the size of your pages. JSON is just text, so you should look into a server-side solution to zip your content, like mod_deflate. mod_deflate works beautifully on dynamic PHP output as well as static pages. If you don't have control over your web server, you could use PHP's built in zlib compression.
Instead of writing the JSON date directly to the document instead you can use an XMLHttpRequest in or use a library like JQuery to load the JSON data during script runtime.
It depends largely on your json data. If the data you're printing inline in the html is huge you might wanna consider using ajax to load the json data. That is assuming you wanted your page to be loaded faster, even without data.
If the data isn't that big, try to keep the data inline, without making extra http requests. To speed up your page, try using YSlow! to see what other areas you could optimize.

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