How can I get a range of dates in php? - php

Question

$start_date = '2012-01-01';
$end_date = '2012-12-31';
$total_days = round(abs(strtotime($end_date) - strtotime($start_date)) / 86400, 0) + 1;
if ($end_date >= $start_date)
{
for ($day = 0; $day < $total_days; $day++)
{
echo "<br />" . date("Y-m-d", strtotime("{$start_date} + {day} days"));
}
}
Right now that's printing '1969-12-31' over and over. The expected output should be:
2012-01-01
2012-01-02
2012-01-03
...
2012-12-30
2012-12-31

Answer 1

I would use the DatePeriod class (along with DateTime and DateInterval) for this:
$start_date = '2012-01-01';
$end_date = '2012-12-31';
$start = new DateTime($start_date);
$end = new DateTime($end_date);
$interval = new DateInterval('P1D'); // 1 day interval
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $day) {
// Do stuff with each $day...
echo $day->format('Y-m-d'), "\n";
}

Answer 2

You above code will work with one extra character - you missed a $ on this line:
echo "<br />" . date("Y-m-d", strtotime("{$start_date} + {$day} days"));
// ^ This was missing

Answer 3

<?php
$start_date = '2012-01-01';
$end_date = '2012-12-31';
$total_days = round(abs(strtotime($end_date) - strtotime($start_date)) / 86400, 0) + 1;
if ($end_date >= $start_date)
{
for ($day = 0; $day < $total_days; $day++)
{
echo "<br />" . date("Y-m-d", strtotime("{$start_date} + {$day} days"));
// You missed the $ here ^
}
}