Check stock tickers in string against array - php

Consider the following array which holds all US stock tickers, ordered by length:
$tickers = array('AAPL', 'AA', 'BRK.A', 'BRK.B', 'BAE', 'BA'); // etc...
I want to check a string for all possible matches. Tickers are written with or without a "$" concatenated to the front:
$string = "Check out $AAPL and BRK.A, BA and BAE.B - all going up!";
All tickers are to be labeled like: {TICKER:XX}. The expected output would be:
Check out {TICKER:AAPL} and {TICKER:BRK.A} and BAE.B - all going up!
So tickers should be checked against the $tickers array and matched both if they are followed by a space or a comma. Until now, I have been using the following:
preg_replace('/\$([a-zA-Z.]+)/', ' {TICKER:$1} ', $string);
so I didn't have to check against the $tickers array. It was assumed that all tickers started with "$", but this only appears to be the convention in about 80% of the cases. Hence, the need for an updated filter.
My question being: is there a simple way to adjust the regex to comply with the new requirement or do I need to write a new function, as I was planning first:
function match_tickers($string) {
foreach ($tickers as $ticker) {
// preg_replace with $
// preg_replace without $
}
}
Or can this be done in one go?

Just make the leading dollar sign optional, using ? (zero or 1 matches). Then you can check for legal trailing characters using the same technique. A better way to go about it would be to explode your input string and check/replace each substring against the ticker collection, then reconstruct the input string.
function match_tickers($string) {
$aray = explode( " ", $string );
foreach ($aray as $word) {
// extract any ticker symbol
$symbol = preg_replace( '/^\$?([A-Za-z]?\.?[A-Za-z])\W*$/', '$1', $word );
if (in_array($symbol,$tickers)) { // symbol, replace it
array_push( $replacements, preg_replace( '/^\$?([A-Za-z]?\.?[A-Za-z])(\W*)$/', '{TICKER:$1}$2', $word ) );
}
else { // not a symbol, just output it normally
array_push( $replacements, $word );
}
}
return implode( " ", $replacements );
}

I think just a slight change to your regex should do the trick:
\$?([a-zA-Z.]+)
i added "?" in front of the "$", which means that it can appear 0 or 1 times

You can use a single foreach loop on your array to replace the ticker items in your string.
$tickers = array('AAPL', 'AA', 'BRK.A', 'BRK.B', 'BAE', 'BA');
$string = 'Check out $AAPL and BRK.A, BA and BAE.B - all going up!';
foreach ($tickers as $ticker) {
$string = preg_replace('/(\$?)\b('.$ticker.')\b(?!\.[A-Z])/', '{TICKER:$2}', $string);
}
echo $string;
will output
Check out {TICKER:AAPL} and {TICKER:BRK.A}, {TICKER:BA} and BAE.B -
all going up!

Adding ? after the $ sign will also accept words, i.e. 'out'
preg_replace accepts array as a pattern, so if you change your $tickers array to:
$tickers = array('/AAPL/', '/AA/', '/BRK.A/', '/BRK.B/', '/BAE/', '/BA/');
then this should do the trick:
preg_replace($tickers, ' {TICKER:$1} ', $string);
This is according to http://php.net/manual/en/function.preg-replace.php

Related

How can I move chinese characters in a string to the end of string?

I have a string like this now: I want to do the following in PHP:
$string = 'Testing giving dancing 喝 喝 passing 制图 giving 跑步 吃';
I want to move all Chinese characters to the end of the string, and also reversing their current order. Accordingly, Removing the duplicate English words and Return the modified string
Here you go! Check the comments in the code:
<?php
$string = 'Testing giving dancing 喝 喝 passing 制图 giving 跑步 吃';
// split by a space into an array
$explosion = explode(' ', $string);
$normalWords = [];
$chineseWords = [];
// loop through the array
foreach ($explosion as $debris) {
// if not normal alphabet characters
if (!preg_match('#[a-zA-Z]+#', $debris) && !in_array($debris, $chineseWords)) {
// add to chinese words array if not already in the array
$chineseWords[] = $debris;
} elseif (preg_match('#[a-zA-Z]+#', $debris) && !in_array($debris, $normalWords)) {
// add to normal words array if not already in the array
$normalWords[] = $debris;
}
}
// reverse the chinese characters like you wanted
$chineseWords = array_reverse($chineseWords);
// Piece it all back together
$string = implode(' ', $normalWords) . ' ' . implode(' ', $chineseWords);
// and output
echo $string; // Testing giving dancing passing 吃 跑步 制图 喝
See it here! https://3v4l.org/FWQWG

Using PHP preg_replace match result in a math operation?

I want to find a number in a string, add one to it, and replace it. These don't work:
$new_version =
preg_replace("/str\/(\d+)str/", "str/".("$1"+1)."str", $original);
$new_version =
preg_replace("/str\/(\d+)str/", "str/".(intval("$1")+1)."str", $original);
Where 'str' is a very identifiable string, each side of the number (and does not contain numbers).
I realise I can do this in more than one line of code quite easily but it seems like this should be possible.
Using a callback function allows you to cast a match to number and increment, e.g.:
preg_replace_callback(
"/str\/(\d+)str/",
function($matches) { return "str/" . ((int)$matches[1] + 1) . "str"; },
$original
);
Solely using str_replace you can get the number from the string, add one to it, and the replace the old number with the new one :
$str = 'In My Cart : 11 items';
$nb = preg_replace('/\D/', '', $str);
$nb += 1;
$str = str_replace($nb-1, $nb, $str);
echo $str;

Search and replace all lines in a multiline string

I have a string with a large list with items named as follows:
str = "f05cmdi-test1-name1
f06dmdi-test2-name2";
So the first 4 characters are random characters. And I would like to have an output like this:
'mdi-test1-name1',
'mdi-test2-name2',
As you can see the first characters from the string needs to be replaced with a ' and every line needs to end with ',
How can I change the above string into the string below? I've tried for ours with 'strstr' and 'str_replace' but I can't get it working. It would save me a lot of time if I got it work.
Thanks for your help guys!
Here is a way to do the job:
$input = "f05cmdi-test1-name1
f05cmdi-test2-name2";
$result = preg_replace("/.{4}(\S+)/", "'$1',", $input);
echo $result;
Where \S stands for a NON space character.
EDIT : I deleted the above since the following method is better and more reliable and can be used for any possible combination of four characters.
So what do I do if there are a million different possibillites as starting characters ?
In your specific example I see that the only space is in between the full strings (full string = "f05cmdi-test1-name1" )
So:
str = "f05cmdi-test1-name1 f06dmdi-test2-name2";
$result_array = [];
// Split at the spaces
$result = explode(" ", $str);
foreach($result as $item) {
// If four random chars take string after the first four random chars
$item = substr($item, 5);
$result_array = array_push($result_arrray, $item);
}
Resulting in:
$result_array = [
"mdi-test1-name1",
"mdi-test2-name2",
"....."
];
IF you would like a single string in the style of :
"'mdi-test1-name1','mdi-test2-name2','...'"
Then you can simply do the following:
$result_final = "'" . implode("','" , $result_array) . "'";
This is doable in a rather simple regex pattern
<?php
$str = "f05cmdi-test1-name1
f05cmdi-test2-name2";
$str = preg_replace("~[a-z0-9]{1,4}mdi-test([0-9]+-[a-z0-9]+)~", "'mdi-test\\1',", $str);
echo $str;
Alter to your more specific needs

Check if input variables are numbers in an array

The problem is the following in PHP:
How to check if the input variables are numbers in an array if all of them was asked to separate with a " " (space) character within a form?
is_int and is_numeric don't work here, since it's a string not an array.
The answer might be easy, I'm just struggling with it in these late night hours.
The whole problem:
By using only one input field, read in numbers separated by " "(space), then print them out in ascending order. If there is any other variable besides numbers, print "error".
$str = "999 999 999 99";
$arr = explode(" ", $str);
foreach ($arr as $value) {
if(is_numeric($value)){
echo 'ok';
}
}
Might just replace the spaces:
if(is_numeric(str_replace(' ', '', $input)) {
// $input without spaces is numeric
}

Get the current + the next word in a string

this is what I try to get:
My longest text to test When I search for e.g. My I should get My longest
I tried it with this function to get first the complete length of the input and then I search for the ' ' to cut it.
$length = strripos($text, $input) + strlen($input)+2;
$stringpos = strripos($text, ' ', $length);
$newstring = substr($text, 0, strpos($text, ' ', $length));
But this only works first time and then it cuts after the current input, means
My lon is My longest and not My longest text.
How I must change this to get the right result, always getting the next word. Maybe I need a break, but I cannot find the right solution.
UPDATE
Here is my workaround till I find a better solution. As I said working with array functions does not work, since part words should work. So I extended my previous idea a bit. Basic idea is to differ between first time and the next. I improved the code a bit.
function get_title($input, $text) {
$length = strripos($text, $input) + strlen($input);
$stringpos = stripos($text, ' ', $length);
// Find next ' '
$stringpos2 = stripos($text, ' ', $stringpos+1);
if (!$stringpos) {
$newstring = $text;
} else if ($stringpos2) {
$newstring = substr($text, 0, $stringpos2);
} }
Not pretty, but hey it seems to work ^^. Anyway maybe someone of you have a better solution.
You can try using explode
$string = explode(" ", "My longest text to test");
$key = array_search("My", $string);
echo $string[$key] , " " , $string[$key + 1] ;
You can take i to the next level using case insensitive with preg_match_all
$string = "My longest text to test in my school that is very close to mY village" ;
var_dump(__search("My",$string));
Output
array
0 => string 'My longest' (length=10)
1 => string 'my school' (length=9)
2 => string 'mY village' (length=10)
Function used
function __search($search,$string)
{
$result = array();
preg_match_all('/' . preg_quote($search) . '\s+\w+/i', $string, $result);
return $result[0];
}
There are simpler ways to do that. String functions are useful if you don't want to look for something specific, but cut out a pre-defined length of something. Else use a regular expression:
preg_match('/My\s+\w+/', $string, $result);
print $result[0];
Here the My looks for the literal first word. And \s+ for some spaces. While \w+ matches word characters.
This adds some new syntax to learn. But less brittle than workarounds and lengthier string function code to accomplish the same.
An easy method would be to split it on whitespace and grab the current array index plus the next one:
// Word to search for:
$findme = "text";
// Using preg_split() to split on any amount of whitespace
// lowercasing the words, to make the search case-insensitive
$words = preg_split('/\s+/', "My longest text to test");
// Find the word in the array with array_search()
// calling strtolower() with array_map() to search case-insensitively
$idx = array_search(strtolower($findme), array_map('strtolower', $words));
if ($idx !== FALSE) {
// If found, print the word and the following word from the array
// as long as the following one exists.
echo $words[$idx];
if (isset($words[$idx + 1])) {
echo " " . $words[$idx + 1];
}
}
// Prints:
// "text to"

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