I am trying to fetch data and encode it to JSON. I have this very confusing trouble. The code I have put in getAnnotions() function, when I do not put it in function, the while loop (commented as //This loop) is reached. Whereas when I encapsulate the same code in getAnnotions() function, that while loop is not reached. What might be the problem?
Here is the code:
<?php
$city=$_GET["city"];
//$limit="1";
//$place=$_GET["place"];
getAnnotions("1");
function getAnnotions($limit)
{
$con = mysql_connect("localhost","hidden","*******");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("merrycod_tummy", $con);
$result = mysql_query("SELECT * FROM deal where city_names LIKE '%".$city."%'");
$rows = array();
while($row = mysql_fetch_array($result))
{
$rows[] = $row;
$result2 = mysql_query("SELECT locationLat,locationLong FROM place where city ='".$city."' AND name='".$row['place_name']."' LIMIT ".$limit);
while($row2 = mysql_fetch_array($result2))
{
$rows[] = $row2;
//This loop
}
}
echo json_encode($rows);
mysql_close($con);
}
?>
Because $city is defined in the global scope, and in PHP functions variables of another scope cannot be used directly. You can either pass it as a parameter (suggested), or use the global $city at the beginning of your function.
I suggest you to echo the sql in $result first,and then run the code you echo in phpmyadmin to look whether your sql is correct
Related
I have seen the opencart function which can be used outside with html like
<?php
foreach ($categories as $category){
echo $category['image'];
}
?>
i would like to make a function like that in php which i can grab data from database and use it outside. may be it's an array so foreach statement is working on it.
like i have name and age in my database i would like to use it like this
<?php
foreach($peoples as $people){
echo $people['name'];
echo $people['age'];
}
?>
Thanks in advance
As Aman Chhabra mentioned, you must first fetch the result from database and then you can use foreach loop to iterate over it.
One thing I would like to mention is DON'T use mysql_query() as use of it is discouraged as per the new guidelines of php development (Check: http://ca1.php.net/manual/en/function.mysql-query.php). To have a compatible code with advanced php use mysqli_query() instead.
Following is the code example utilizing mysqli class. This is procedural way but you can use it in OOP style as well.
//Connect to database
$host = "localhost"; //Change according to yours
$username = "root"; //Change according to yours
$password = ""; //Change according to yours
$database = "test"; //Change according to yours
$con = mysqli_connect($host,$username,$password,$database); //Create the connection
if(!$con)
{
echo "Not connected";
}
else
{
echo "Connected<br />";
}
//Prepare the query to fetch the database records
$query = "select * from TableName"; //Replace the table name with yours
$sql = mysqli_query($con,$query); //Execute the query
while($result = mysqli_fetch_assoc($sql)) //Loop through, till there are records corresponding to the query
{
$rows[] = $result; //Store all the records in an array
}
//Now iterate over each property using foreach loop
foreach($rows as $row)
{
echo "Name - ".$row['name']." Age - ".$row['age']."<br />";
}
Opencart modifies it to the array of results and the use it using foreach
You need to do it like this
$result = mysql_query($con,"SELECT * FROM Persons");
while($row = mysql_fetch_array($result))
{
$data[] = $result;
}
And then later you can use it like this
foreach($data as $row)
{
echo $row['FirstName'] . " " . $row['LastName'];
echo "<br>";
}
I know that this is an insanely basic question, but I'm new to PHP and am trying to write some simple 'getter' functions that are stored in a separate file.
I keep getting this error, and I can't figure out why.
Fatal error: Function name must be a string in
D:\Hosting\xxxxxxx\html\mysite\scripts\convert_ids.php on line 15
Here is the script from the calling function:
include 'scripts/convert_ids.php';
$group = getGroup(2);
echo $group;
And this is the getter function:
convert_ids.php
<?php
include('connection.php');
function getGroup($id) {
$sql = "SELECT group FROM Groups WHERE id=$id";
$result = mysql_query($sql);
if(!$result) {
return -1;
}
$row = $mysql_fetch_array($result); //<--this is line 15
return $row['group'];
}
?>
$row = $mysql_fetch_array($result);
Should be
$row = mysql_fetch_array($result);
You want to use mysql_fetch_assoc for $row['group']
mysql_fetch_array you will need to use $row[0]
Also don't put a $ in front of mysql_fetch_array
Is there a quick way to filter a mysql_query result to get a list containing only values of a specific column?
$query = mysql_query("SELECT * FROM users");
$list_of_user_names = get_values($query,"names");
What is the name of the function to be used in place of get_values?
Assuming your field name in databse is "names"
$query = mysql_query("SELECT names FROM users");
while($row = mysql_fetch_assoc($query)){
echo $row['names'];
echo "<br>";
}
NOTE : mysql_* functions are deprecated in new version of php, use mysqli_* or PDO
Use below function.
function get_values($q,$c)
{
$arr = array();
while($row = mysql_fetch_array($q))
{
$arr[] = $row[$c];
}
return $arr; // return all names value.
}
Try this:
$query = mysql_query("SELECT names FROM users");
if (!$query) {
echo "Could not successfully run query from DB: " . mysql_error();
exit;
}
if (mysql_num_rows($query) == 0) {
echo "No rows found, nothing to print so am exiting";
exit;
}
// While a row of data exists, put that row in $row as an associative array
// Note: If you're expecting just one row, no need to use a loop
// Note: If you put extract($row); inside the following loop, you'll
// then create $names
while ($row = mysql_fetch_assoc($query)) {
echo $row["names"];
}
I have a function that I can get all the correct values for with an echo, but when I cannot figure out how to get the whole array returned. Could someone help me figure out to get the all of the child users?
$useridarray[] = $userid;
getchildren($useridarray, $useridarray);
function getchildren($array, $totalarray)
{
foreach($array as $arr)
{
$db_name = "dbname";
$connection = #mysql_connect("localhost", "username", "password") or die(mysql_error());
$db = #mysql_select_db($db_name, $connection) or die(mysql_error());
$sql = "
select *
from users
where creator = '$arr'
";
$result = #mysql_query($sql, $connection) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$newchildren[] = $row['id'];
$totalarray[] = $row['id'];
//echo $row['id'] . ' ';
}
mysql_close();
getchildren($newchildren, $totalarray);
}
}
You need to pass by referenceDocs:
function getchildren($array, &$totalarray)
^
Usage:
$useridarray[] = $userid;
getchildren($useridarray, $useridarray);
var_dump($useridarray); # your result
You need add return before
mysql_close();
return getchildren($newchildren, $totalarray);
I am not familiar with PHP syntax but you likely want to implement a "Stopping Criteria" to return you results. So in your instance it would seem like you would want something where getChildren returns the localResults + recursive getChildren results that are totaled incrementally as you go through your foreach loop.
I have a strange question. I need to send some code to a client without having access to the server to test my code. In addition, it's using postgreSQL which I've never used, and I've not done PHP for a while!
In order to save some time, I'd really appreciate if someone could tell me if this code will do what I want?
example feed
<?
$sql = "SELECT * FROM V_SIDE_MENU_E";
include 'db.inc.php';
?>
db.inc.php
$connectString = 'host=localhost dbname=myDatabase user=foo password=bar';
$link = pg_connect($connectString);
if (!$link) {
echo "error";
} else {
$result = pg_query($link, $sql);
$rows = array();
while($r = pg_fetch_assoc($result)) {
$rows[] = $r;
}
print json_encode($rows);
}
I would change
$rows = array();
while($r = pg_fetch_assoc($result)) {
$rows[] = $r;
}
print json_encode($rows);
into
print json_encode(array_values(pg_fetch_all($result)));
But that's just a style thing -- your code should work.
Tested on your mysql ( it looks like it will work ). Your SELECT will work same in PostgreSQL like mySQL