Listing the tables content in the database - php

Question

written a script to print the contents of all the tables present in the database...
but unfortunately i am going wrong somewhere. could anyone please tell me where is the mistake?
$sql = "SHOW TABLES FROM $dbName";
$result = mysql_query($sql);
if (!$result) {
echo "DB Error, could not list tables\n";
echo 'MySQL Error: ' . mysql_error();
exit;
}
for ($i=1; $i<=5; $i++)
{
while ($row = mysql_fetch_row($result))
{
echo "Table: {$row[0]}\n";
$sql_1 = "SELECT * FROM {$row[0]}";
$result_1 = mysql_query($sql_1);
$row_1 = mysql_fetch_row($result);
echo "$row_1";
}
}
mysql_free_result($result);
?>
thanks..

Answer 1

first of all, u don't need
for ($i=1; $i<=5; $i++)
Also, $row_1 is an array, so to print it use something like
print_r($row_1);
And there might be not the only row in a table, so use construction like
while ($row = mysql_fetch_row($result))
{
echo "Table: {$row[0]}\n";
$sql_1 = "SELECT * FROM {$row[0]}";
$result_1 = mysql_query($sql_1);
while ($row_1 = mysql_fetch_row($result_1/*There was also an error*/))
print_r($row_1); /*Print_r or other function to print an array*/
}