PHP batch file renaming - php

Question

I have a bunch of files named like this...
full-file(1).jpg
full-file(10).jpg
full-file(11).jpg
full-file(12).jpg
full-file(2).jpg
etc...
I'm trying to figure out the most efficient way to rename all these files using PHP so that they get renamed like this...
full-file0001.jpg
full-file0010.jpg
full-file0011.jpg
full-file0012.jpg
full-file0002.jpg
I've got as far as reading all the files from a folder and looping through them but not sure about the best way to remove the brackets and make the number 4 digits with leading 0.
$image_files = get_files($thumbpath);
foreach($image_files as $index=>$file) {
echo $file;
}

Answer 1

Use a regular expression to get the digit, and then zero-pad it using sprintf():
$image_files = get_files($thumbpath);
foreach($image_files as $index=>$file) {
// Capture \d+ into $matches[1]
preg_match('/\((\d+)\)/', $file, $matches);
// Pad it with %04d in sprintf()
$newfile = sprintf("full-file%04d.jpg", $matches[1]);
}
Example:
php > $file = 'full-file(12).jpg';
php > preg_match('/\((\d+)\)/', $file, $matches);
php > $newfile = sprintf("full-file%04d.jpg", $matches[1]);
php > echo $newfile;
// full-file0012.jpg
Update (for more flexible filenames):
To please the downvoter I can only assume wanted more flexible filenames, expand the regular expression:
$image_files = get_files($thumbpath);
foreach($image_files as $index=>$file) {
preg_match('/([^(]+)\((\d+)\)(.+)/', $file, $matches);
$newfile = sprintf("%s%04d%s", $matches[1], $matches[2], $matches[3]);
// And rename the file
if (!rename($file, $newfile)) {
echo "Could not rename $file.\n";
}
else echo "Successfully renamed $file to $newfile\n";
}
The pattern matches first, everything up to the the first ( with ([^(]+), followed by the number via (\d+), and everything remaining via (.*).

Answer 2

You can use a mixture of REGEXP (remove brackets) and string padding (to force four digits).
Note I use a replacement callback to do both operations in one place.
$files = array(
'full-file(1).jpg',
'full-file(10).jpg',
'full-file(11).jpg',
'full-file(12).jpg',
'full-file(2).jpg'
);
function pr_callback($match) {
return str_pad($match[1], 4, '0', STR_PAD_LEFT);
}
foreach($files as $file)
echo preg_replace_callback('/\((\d+)\)/', pr_callback, $file).'<br />';
Outputs:
full-file0001.jpg
full-file0010.jpg
full-file0011.jpg
full-file0012.jpg
full-file0002.jpg

Answer 3

I haven't seen anyone recommend sscanf() yet.
<?php
$files = array(
"full-file(1).jpg",
"full-file(10).jpg",
"full-file(11).jpg",
"full-file(12).jpg",
"full-file(2).jpg",
);
foreach ($files as $file) {
$n = sscanf($file, "full-file(%d).jpg");
printf("full-file%04d.jpg\n", $n[0]);
}
returns:
full-file0001.jpg
full-file0010.jpg
full-file0011.jpg
full-file0012.jpg
full-file0002.jpg
This only works if "full-file" is the actual name of your file, of course. sscanf() is not a regex parser, it merely extracts data using printf()-style format strings ... though it does do some more advanced format recognition than is documented at http://php.net/sscanf . If you need to handle other filenames, you can extend the format string:
<?php
$files = array(
"this-file(1).jpg",
"full-file(10).jpg",
"foo(11).jpg",
"blarg(12).jpg",
"full-file(2).jpg",
);
foreach ($files as $file) {
$n = sscanf($file, "%[a-z-](%d).jpg");
printf("%s%04d.jpg\n", $n[0], $n[1]);
}
returns:
this-file0001.jpg
full-file0010.jpg
foo0011.jpg
blarg0012.jpg
full-file0002.jpg

Answer 4

Assuming your files aren't actually called full-file(0000).jpg:
<?php
$arr = array('full-file(1).jpg',
'full-file(10).jpg',
'full-file(11).png',
'full-file(12).jpg',
'full-file(2).gif',
'abc(12345).jpg',
'def(99).jpg',
'xzy-file(100).jpg');
function format_filename($matches){
return $matches[1].sprintf("%04d",$matches[3]).'.'.$matches[5];
}
function process_array(&$value){
$value = preg_replace_callback('/^(.*?)(\()(\d+)(\)).(jpg|png|gif)/','format_filename',$value);
}
array_walk($arr,'process_array');
print_r($arr);
/*
Array
(
[0] => full-file0001.jpg
[1] => full-file0010.jpg
[2] => full-file0011.png
[3] => full-file0012.jpg
[4] => full-file0002.gif
[5] => abc12345.jpg
[6] => def0099.jpg
[7] => xzy-file0100.jpg
)
*/
?>

Answer 5

Use code:
preg_match('/^(.*?)\((\d+)\)(.*)$/', $name, $m);
$name = sprintf("%s%04d%s", $m[1], $m[2], $m[3]);
See and test it here.

Answer 6

You will need str-pad(). A sample soon...
EDIT 1: solution using str_pad and preg_replace_callback.
OBS: Anonymous functions only in php5.3+.
foreach ($image_files as $file)
{
$o = preg_replace_callback(
"|\((\d+)\)|", function($matches)
{
$r = str_pad($matches[1], 4, '0', STR_PAD_LEFT);
return $r;
}
, $file);
echo $o . "\n";
}