<?php
mysql_connect("localhost","root","");
mysql_select_db('db2012');
$uid = 8;
$mid = 10;
$q = mysql_query("select friend from users_friends where user = $uid") or die(mysql_error());
if(mysql_num_rows($q) > 0)
{
while($r=mysql_fetch_array($q))
{
$qq = mysql_query("select friend from users_friends where user = $mid") or die(mysql_error());
while($rr = mysql_fetch_array($qq))
{
if($r[friend]==$rr[friend])
{
$friend_name_query = mysql_query("select name from users where uid = '$rr[friend]'") or die();
$friend_name = mysql_fetch_array($friend_name_query);
echo $friend_name[name];
}
}
}
}
?>
This query is working but any other way out to use less queries ? i m a beginner programmer please let me know if there is n e thng ...
You should use just one query:
$query = 'SELECT u.name
FROM users_friends f1
INNER JOIN users_friends f2 ON (f2.friend = f1.friend)
INNER JOIN user u ON (u.uid = f2.friend)
WHERE f1.user = "'. $uid. '"
AND f2.user = "'. $mid .'"';
run the query
$q = mysql_query($query) or die(mysql_error());
and do the while loop
while($r=mysql_fetch_array($q)){
echo $r['name'];
}
You only need the if(mysql_num_rows($q) > 0) statement if you do an else, otherwise you can just use the while
You could try below in order to get mutual friends of user 8 and 10.
select * from
user_friends a inner join user_friends b on
a.friend=b.friend and (a.user='8' and b.user='10')
U could then join the user table to get the name.
Related
I have two tables: users and threads. When a thread is created, it will store the user_id in the table as author_id. I want to display the thread name and the username of its author with the same query. I am currently using two querys as shown:
$query2 = mysql_query("SELECT author_id FROM threads WHERE id = $threadId") or die(mysql_error());
$result2 = mysql_fetch_array($query2);
$author_id = $result2['author_id'];
$query3 = mysql_query("SELECT username FROM users WHERE id = $author_id") or die(mysql_error());
$result3 = mysql_fetch_array($query3);
$author_name = $result3['username'];
<?php
$sql = '
SELECT t.name, u.username
FROM threads t
JOIN users u ON t.author_id = u.id
WHERE t.id = ' . (int)$threadId . '
';
list($thread_name, $author_name) = mysql_fetch_row(mysql_query($sql));
P.S. Mysql php extension is deprecated.
Try this query:
SELECT username
FROM users
WHERE id = (SELECT author_id
FROM threads
WHERE id = $threadId
LIMIT 1)
Note: Limit 1 is not mandatory as id is unique.
I'm trying to find the number of rows in a table in the database depending on certain conditions with a limit feature so that i can count the number of rows there are matching the condition after a certain row in the table.
Thus i created my php query:
$q = $db->query("SELECT u.*, f.* FROM updates U LEFT JOIN friends f ON f.fid = u.userid WHERE f.uid = '$userid' ORDER BY u.up_id DESC LIMIT $limitID, 9999999");
$nr = $q->num_rows;
However even if there are more rows in the database after the $limitID, it says there are no rows.
If I try this:
$q = $db->query("SELECT u.*, f.* FROM updates U LEFT JOIN friends f ON f.fid = u.userid WHERE f.uid = '$userid' ORDER BY u.up_id DESC LIMIT $limitID");
$nr = $q->num_rows;
then it works, but it doesnt count after the $limitID. Any udeas?
According yo your query, it should be like
$sql = "SELECT count(*) FROM updates U
LEFT JOIN friends f ON f.fid = u.userid WHERE f.uid = ?";
// getting stuff using prepared statements
$row = $res->fetch_row();
$num = $row[0] - $limitID;
but I doubt it's really what you need either.
Using what Your Common Sense told me I managed to find an answer to my problem, so here it is:
$limitID = $upid;
$sql = "SELECT count(*) FROM updates u
LEFT JOIN friends f ON f.fid = u.userid WHERE
(f.uid = '$userid' AND u.up_id > '$limitID')";
$res = $db->query($sql);
$row = $res->fetch_row();
$num = $row[0];
if($num == 0){
// do nothing
} else {
echo "<span class='newPosts'>" .$num. " New Post"
. (($num>1)?'s':' ') . "</span>";
}
works perfectly
I'm trying to display a list of status updates from artists that a logged in user is following.
So far I have this:
#Get the list of artists that the user has liked
$q = "SELECT * FROM artist_likes WHERE user_id = '1' ";
$r = mysqli_query($dbc,$q);
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {
#Now grab the statuses for each artist
$status_query = "SELECT * FROM status_updates WHERE artist_id = '".$row['artist_id']."' ";
$status_result = mysqli_query($dbc,$status_query)
}
But i'm not sure how to loop through and display the returned status updates?
This isn't a strong point of mine, so any pointers would be greatly appreciated!
What prevented you from doing similar to what you'd already done for the first query? Something like follows:
#Get the list of artists that the user has liked
$q = "SELECT * FROM artist_likes WHERE user_id = '1' ";
$r = mysqli_query($dbc,$q);
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {
#Now grab the statuses for each artist
$status_query = "SELECT * FROM status_updates WHERE artist_id = '".$row['artist_id']."' ";
$status_result = mysqli_query($dbc,$status_query)
while($status_result_row = mysqli_fetch_assoc($status_result)) {
echo $status_result_row['mycol']; // This is where you know better than us
}
}
Or if those two tables artist_likes and status_updates have artist_id in common then you could just use one query with a join. (But don't know if you are asking for that).
Just for avoiding multiple query, you can use one query like this:
SELECT l.*, s.*
from artist_likes l, status_updates s
WHERE
l.artist_id = s.artist_id and
l.user_id = '1'
or
SELECT l.*, s.*
from artist_likes l
JOIN status_updates s on (l.artist_id = s.artist_id)
WHERE
l.user_id = '1'
I need to create a friend system, but my loop always skips the first match and sometimes it prints copies of the same name
$result = mysql_query("SELECT * FROM tbusers INNER JOIN tbfriends ON tbusers.id = tbfriends.username_id");
while($row = mysql_fetch_array($result))
{
if ($row['username_id'] == 1)//the 1 will be a variable, username_id is in friends
$count = $row['friendname'];//friendname is in friends
if ($row['id'] == $count)//id is in users
echo $row['username'];//username is in users
}
Can someone see what my problem is ?
2 things:
if ($row['username_id'] == 1)
you should put that in your sql:
$result = mysql_query("SELECT username, friendname FROM tbusers INNER JOIN tbfriends ON tbusers.id = tbfriends.username_id where tbusers.id = ".$yourVariable);
In your query, user and friend are linked, and can only be equal.
Now, this:
$count = $row['friendname'];//friendname is in friends
if ($row['id'] == $count)//id is in users
is equal to
if ( $row['id'] == $row['friendname'] )
this sounds plain wrong. You compare a numerical id with a name. Moreover, your sql query already retrives all friends from users. In the version I showed here, it retrieves only friends of the user you are interested in.
finally, you print (echo) the name of the user, not of the friend. In my opinion the following code will do what you want:
$result = mysql_query("SELECT friendname FROM tbfriends WHERE username_id = ".$yourUserVariable);
while($row = mysql_fetch_array($result))
{
echo $row['friendname']; // or better: echo $row['friendname'], '<br>';
}
edit: after comment...
so if ( $row['id'] == $row['friendname'] ) means the user is his own friend. can that happen?
this code shall print what you want, friend names.
/*
$result = mysql_query("
SELECT username as friend_name,
friendname as friend_id,
username_id as user_id
FROM tbusers INNER JOIN tbfriends ON tbusers.id = tbfriends.username_id
WHERE tbusers.id = ".$yourVariable);
*/
$result = mysql_query("
SELECT username as friend_name,
friendname as friend_id,
username_id as user_id
FROM tbusers INNER JOIN tbfriends ON tbusers.id = tbfriends.friendname
WHERE tbfriends.username_id = ".$yourVariable);
while($row = mysql_fetch_array($result))
{
echo $row['friend_name']; // or better: echo $row['friend_name'], '<br>';
}
How can I grab the count value from the query MySQL query below using PHP.
Here is My MySQL code.
$dbc = mysqli_query($mysqli,"SELECT COUNT(*) FROM((SELECT users_friends.id
FROM users_friends
INNER JOIN users ON users_friends.user_id = users.user_id
WHERE users_friends.user_id = 1
AND users_friends.friendship_status = '1')
UNION
(SELECT users_friends.id
FROM users_friends
INNER JOIN users ON users_friends.friend_id = users.user_id
WHERE users_friends.friend_id = 1
AND users_friends.friendship_status = '1')) as friends");
using SQL_CALC_FOUND_ROWS should simplify things:
$dbc = mysqli_query($mysqli,"SELECT SQL_CALC_FOUND_ROWS users_friends.id
FROM users_friends
INNER JOIN users ON users_friends.user_id = users.user_id
WHERE users_friends.user_id = 1
AND users_friends.friendship_status = '1'
");
then afterwards do
$rs = mysqli_query($mysqli, "SELECT FOUND_ROWS()"));
$rec = $rs->fetch_array();
$count = $rec[0];
This method will return the number of records that match the query, ignoring any LIMIT statement, whereas using $rs->num_rows will only give you the number of records actually returned. Depends which one you want.
if ($result = mysqli_query($link, "SELECT Name FROM City LIMIT 10")) {
printf("Select returned %d rows.\n", mysqli_num_rows($result));
/* free result set */
mysqli_free_result($result);
http://us.php.net/manual/en/mysqli.query.php
Assuming that you are correctly connected to the MySQL server and your query are executed correctly, you can use the following code:
$values = mysql_fetch_row($dbc);
$count = $values[0];
Your query should look like SELECT COUNT(*) as numThings FROM xxx
The numThings is what you will reference in PHP:
$result = mysql_query("SELECT COUNT(*) as `numThings` FROM xxx");
$row = mysql_fetch_assoc($result);
$count = $row['numThings'];