Retrieve and upload image in php using mysql - php

Question

I have a problem in retrieving an image from a database. Here is the code that uploads the image to the database:
<form method="post" action="index2.php" enctype="multipart/form-data">
<input type="file" name="drimg2"/>
<input type="submit" name="submit2" value="Save"/>
</form>
<?php
if(isset($_POST['submit2'])) {
$con=mysql_connect("localhost","root","root");
mysql_select_db("test",$con);
$imgname1=$_FILES['drimg2']['name'];
echo $imgname1;
$imageextension1 = substr(strrchr($imgname1,'.'), 1);
if (($imageextension1!= "jpg") && ($imageextension1 != "jpeg") && ($imageextension1 != "gif")&& ($imageextension1 != "png")&& ($imageextension1 != "bmp")) {
die('Unknown extension. Only jpg, jpeg, and gif files are allowed. Please hit the back button on your browser and try again.');
}
if (($imageextension1= "jpg") && ($imageextension1= "jpeg") && ($imageextension1= "gif") && ($imageextension1 = "png") && ($imageextension1 = "bmp")) {
$query1=mysql_query("INSERT INTO store set image='$imgname1'");
$action = move_uploaded_file($_FILES['drimg2']['tmp_name'],"images/".$imgname1);
die('not Uploded');
}
}
?>
Now I want to retrieve all the images in the database; for this I am using the following code:
<?php
$query1="select * from store";
$fetch=mysql_query($query1);
while ($rows=mysql_fetch_array($fetch)) {
echo "<img src='images/".$rows['image']."' />";
}
?>

Answer 1

You should not be using the old mysql_* functions and use PDO or mysqli instead. Here is a much cleaner and securer way of doing what you want.
<?php
/**
* A Simple class to handle your database requests
* related to your image storage ect
*/
class image_model{
private $db;
function __construct($db){
$this->db = $db;
}
function add($img_name){
$sql = "INSERT INTO store (image) VALUES (:value)";
$stmt = $this->db->prepare($sql);
$stmt->bindParam(':value', $img_name, PDO::PARAM_STR);
$stmt->execute();
}
function get_all(){
$sql = "SELECT image FROM store";
return $this->db->query($sql)->fetchAll();
}
//Perhaps use in future
function get_image($id){
$sql = "SELECT image FROM store WHERE id=:id";
$stmt = $this->db->prepare($sql);
$stmt->bindParam(':id', $id, PDO::PARAM_INT);
$stmt->execute();
return $result->fetchAll();
}
}
//Connect safely to your database...
try{
$db = new PDO("mysql:host=localhost;dbname=test", 'root', 'password');
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$db->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$db->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE,PDO::FETCH_ASSOC);
}catch (Exception $e){
die('Cannot connect to mySQL server. Details:'.$e->getMessage());
}
//Create an instance of the image model above
$img_model = new image_model($db);
//Boom...Handle the upload
if($_SERVER['REQUEST_METHOD']=='POST'){
if ($_FILES["img"]["error"] > 0){
echo "Error: ".$_FILES["img"]["error"]."<br />";
}else{
$img = getimagesize($_FILES["img"]["tmp_name"]);
$allowed = array('image/jpeg','image/gif','image/png','image/bmp');
//Width and height must be more then 0 pixles and mime must be in allowed array
if($img[0] > 0 && $img[1] > 0 && in_array($img['mime'],$allowed)){
if(is_uploaded_file($_FILES["img"]["tmp_name"])){
//Clean image name
$img_name = preg_replace('/[^a-zA-Z0-9.-]/s', '_', basename($_FILES["img"]["name"]));
//move image to folder
move_uploaded_file($_FILES["img"]["tmp_name"],"images/".$img_name);
//Add image to db using a method from the image model
$img_model->add($img_name);
}
}else{
echo "Error: Unknown extension. Only jpg, bmp and gif files are allowed. Please hit the back button on your browser and try again.<br />";
}
}
}
//Your form
?>
<h1>Upload image</h1>
<form method="POST" action="" enctype="multipart/form-data">
<input type="file" name="img"/>
<input type="submit" name="submit" value="Save"/>
</form>
<?php
//Access your image model in a simple way and get all images
foreach($img_model->get_all() as $row){
echo '<img src="images/'.$row['image'].'" /><br />';
}
?>

Answer 2

Refer this link,
Hope this will help.
Change retrieval of image code to following,
$content = $row['image'];
header('Content-type: image/jpg');
echo $content;

Answer 3

try this I've tested this code and made some modifications.
<form method="post" action="index2.php" enctype="multipart/form-data">
<input type="file" name="drimg2"/>
<input type="submit" name="submit2" value="Save"/>
</form>
<?php
if(isset($_POST['submit2'])) {
$con=mysql_connect("localhost","root","root");
mysql_select_db("test",$con);
$imgname1=$_FILES['drimg2']['name'];
//echo $imgname1;
$imageextension1 = substr(strrchr($imgname1,'.'), 1);
//echo '<pre>';print_r($imageextension1);echo '</pre>';die('Call');
if (($imageextension1!= "jpg") && ($imageextension1 != "jpeg") && ($imageextension1 != "gif")&& ($imageextension1 != "png")&& ($imageextension1 != "bmp")) {
die('Unknown extension. Only jpg, jpeg, and gif files are allowed. Please hit the back button on your browser and try again.');
} else {
//if (($imageextension1 == "jpg") && ($imageextension1 == "jpeg") && ($imageextension1 == "gif") && ($imageextension1 == "png") && ($imageextension1 = "bmp")) {
if(move_uploaded_file($_FILES['drimg2']['tmp_name'],"images/".$imgname1)) {
$query1=mysql_query("INSERT INTO fileurl(filename) VALUES('".$imgname1."')"); //fileurl is table name and filename is field name
if($query1) {
echo "Data inserted";
} else {
echo "Data not inserted";
}
} else {
echo "Error occured while trying to upload image";
}
//$action = ;
//die('not Uploded');
}
}
?>
and for fetching images try this
$query = "SELECT * FROM fileurl";
$fetch = mysql_query($query);
while($rows = mysql_fetch_array($fetch)) {
echo "<img src='images/".$rows['filename']."' />";
}
if your image format not matched it will close the program automatically otherwise it'll jump to the else condition and upload the image and then insert the name of file into the database.