I'm trying to launch from the command line:
$ /usr/bin/php -f "index.php?refresh_words=1"
Could not open input file: index.php?refresh_words=1
Off course, without ?refresh_words=1 it's running ok. Can I pass $_GET parameters from the command line?
You can't do this that way. Use argv and argc. See Command Line Usage section in manual
Related
I've got the following script:
#!/bin/sh
export DISPLAY=:0
phantomjs --version
It try to run it from the following PHP script:
<?php
$result = shell_exec('sh test.sh');
echo $result;
?>
This script return the following error:
[Thu Jun 19 10:31:31 2014] [error] [client] test.sh: line 3: phantomjs: command not found
I tried to run phantomjs -v by hand in a console, and it runs fine. I checked the PATH, and phantomjs is correctly defined and found.
The execution environment is a virtual Server with LiveConfig.
Can someone help me understand what I'm doing wrong ?
It could be an issue with shell_exec() and line breaks,
try adding "2>&1" to the string you are passing:
$result = shell_exec('sh test.sh 2>&1');
this worked for me, found it in the top comment here, naturally ;)
Your PATH probably lacks the location for the phantomjs executable. PhantomJS is probably installed in /usr/local/bin so you need to add this to your PATH variable:
#!/bin/sh
export DISPLAY=:0
PATH=$PATH:/usr/local/bin
phantomjs --version
To check what the current PATH is, you could begin the shell script with:
#!/bin/sh
echo $PATH
<?php
exec('/usr/local/bin/phantomjs path/somescript.js');
?>
Yes. Sometimes phantomjs don't need full path in some environment without generate any error. However, sometimes it does.
Always use the full path for all argument in the php command.
Did you use the fullpath for hello.js?
Do not use exec(). Never. It's a bad way.
Use the php-phantomjs and PhantomJS Runner instead.
I have the method stored in Z:\work\project\apps\controllers\_cron\tools\method
How can I call "method" using the command line?
You run the PHP executable with the location of the file as an argument (Windows example: php.exe path/to/method.php). The location of php.exe depends on where you installed it.
Read more.
Easy as
C:\path\to\php.exe -f "Z:\path\to\file.php"
Source:
#1 result for "run php from command line windows" in google
If I try to run this inside a script:
<?php exec("curl http://ww.google.com") ?>
I get:
-bash-3.2$ php test.php
sh: /curl: No such file or directory
using shell_exec:
PHP Warning: shell_exec(): Cannot execute using backquotes in Safe Mode...
How can I run curl as shell command line?
Those errors are happening on Linux, on my mac works.
The issue is that PHP safe mode is on and it is better to use the full path to run cURL (thanks ghostJago and amosrivera). Running the script with the following command fixed the issue:
php -dsafe_mode=Off test.php
I do not want to change the php.ini but it could be a solution too.
shell_exec tells the safe mode problem, but exec just tell you an wrong message, hopefully I tried both exec and shell_exec.
Disable safe mode in your php.ini file. Also check if you do have curl installed.
safe_mode = Off
To convert from an bash command (like you can copy from chrome-dev-tools) to php take a look at this: https://incarnate.github.io/curl-to-php/
at the commandline, do this:
which curl
This will give you the absolute path to the curl program.
Then double check that safe_mode = Off is in your php.ini.
When you've done this, change your code to:
<?php exec("path/you/got/from/which/curl http://www.google.com") ?>
How we run php script using Linux bash?
php file test.php
test.php contains:
<?php echo "hello\n" ?>
From the command line, enter this:
php -f filename.php
Make sure that filename.php both includes and executes the function you want to test. Anything you echo out will appear in the console, including errors.
Be wary that often the php.ini for Apache PHP is different from CLI PHP (command line interface).
Reference: https://secure.php.net/manual/en/features.commandline.usage.php
First of all check to see if your PHP installation supports CLI. Type: php -v. You can execute PHP from the command line in 2 ways:
php yourfile.php
php -r 'print("Hello world");'
There are two ways you can do this. One is the one already mentioned, i.e.:
php -f filename.php
The second option is making the script executable (chmod +x filename.php) and adding the following line to the top of your .php file:
#!/path/to/php
I'm not sure though if a webserver likes this, so if you also want to use the .php file in a website, that might not be the best idea. Still, if you're just writing some kind of script, it is easier to type ./path/to/phpfile.php than having to type php -f /path/to/phpfile.php every time.
Simply this should do:
php test.php
just run in linux terminal to get phpinfo .
php -r 'phpinfo();'
and to run file like index.php
php -f index.php
php -f test.php
See the manual for full details of running PHP from the command line
php test.php
should do it, or
php -f test.php
to be explicit.
I was in need to decode URL in a Bash script. So I decide to use PHP in this way:
$ cat url-decode.sh
#!/bin/bash
URL='url=https%3a%2f%2f1%2fecp%2f'
/usr/bin/php -r '$arg1 = $argv[1];echo rawurldecode($arg1);' "$URL"
Sample output:
$ ./url-decode.sh
url=https://1/ecp/
I have a script in which I am trying to load a custom php.ini file. The script is run on *nix systems via a #!/usr/bin/php -qc /path/to/php.ini header. When doing this, however, PHP reports that the loaded php.ini file does not exist, i.e. none is loaded.
If I execute php -qc /path/to/php.ini /path/to/script in the command line directly, it picks up the php.ini -- is it possible to override the php.ini file using the #! notation?
PHP does not like parsing arguments from the shebang. It only allows one to be present. You can however trick it by omitting the space for the first argument parameter:
#!/usr/bin/php -qc/etc/php5/my.ini
(Obviously this method only works for one such parameter with concatenated argument.)
You can workaround this shebang portability specification fail by wrapping your PHP script in a Shell script:
#!/bin/sh
SCRIPT_PATH="$(dirname $0)"
/usr/bin/env php -qc /path/to/php.ini -f $SCRIPT_PATH/my_original_script.php