Mysql Query is not working in edited jTable code, why? - php

I'm using this example: www.jtable.org
I've downloaded the jTable PHP version. I then edited the script. The jTable simple version is working, but my edited version isn't.
I can create a list, but I can't add a row; this code is causing problems. However, PHP doesn't display any error messages.
else if($_GET["action"] == "create")
{
//Insert record into database
$result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web) VALUES('" . $_POST["bolge"] . "', '" . $_POST["sehir"] . "', '" . $_POST["firma"] . "', '" . $_POST["adres"] . "', '" . $_POST["tel"] . "', '" . $_POST["web"] . "'");
//Get last inserted record (to return to jTable)
$result = mysql_query("SELECT * FROM veriler WHERE id = LAST_INSERT_ID();");
$row = mysql_fetch_array($result);
//Return result to jTable
$jTableResult = array();
$jTableResult['Result'] = "OK";
$jTableResult['Record'] = $row;
print json_encode($jTableResult);
}
What is the problem?

In this line, there is a problem:
$result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web) VALUES('" . $_POST["bolge"] . "', '" . $_POST["sehir"] . "', '" . $_POST["firma"] . "', '" . $_POST["adres"] . "', '" . $_POST["tel"] . "', '" . $_POST["web"] . "'");
The format for the INSERT query is:
INSERT INTO table (column1, column2, etc) VALUES (value1, value2, etc);
You missed a closing parenthesis for the VALUES part.
To improve your code, you can do something like this:
$result = mysql_query("YOUR QUERY") or die('ERROR: '.mysql_error());
And please read on SQL Injection.

here is the problem you forget the )
$result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web)
VALUES('" . $_POST["bolge"] . "', '" . $_POST["sehir"] . "', '" . $_POST["firma"] . "', '" . $_POST["adres"] . "', '" . $_POST["tel"] . "', '" . $_POST["web"] . "'");
use
$result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web) VALUES
('{$_POST["bolge"]}', '{$_POST["sehir"] }' , '{$_POST["firma"]}' , '{$_POST["adres"] }', '{$_POST["tel"]}', '{$_POST["web"]}' )" ) ;

first of all you can reduce one query of last_inset_id()
else if($_GET["action"] == "create")
{
//Insert record into database
$result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web) VALUES('" . $_POST["bolge"] . "', '" . $_POST["sehir"] . "', '" . $_POST["firma"] . "', '" . $_POST["adres"] . "', '" . $_POST["tel"] . "', '" . $_POST["web"] . "'"));
//Get last inserted record (to return to jTable)
//check youe result query you are missing something here
$id=mysql_insert_id();
//this will automatically give you last id
//Return result to jTable
$jTableResult = array();
$jTableResult['Result'] = "OK";
$jTableResult['id'] = $id;
$jTableResult['Record'] = $row;
$jTableResult['aderes'] = $_POST['adres'];
//and so on
print json_encode($jTableResult);
}

Related

SQL Can't Delete from Table

I have a PHP and I want to do 2 inserts and 1 delete, but I can only make an insert. If the array containt the last parameter == "historico" should delete from instant_table all register with same serial_num and inserte the array intro the instant_table and insert in historical_table("SensorData"). Ifnot (the array don't hace the parameter "historico"), should de delete from instant_table all register with same serial_num and only inserte the array intro the instant_table.
My code:
if ($_SERVER["REQUEST_METHOD"] == "POST") {
$serial_numb = test_input($_POST["serial_numb"]);
$DHTtempC = test_input($_POST["DHTtempC"]);
$DHThumid = test_input($_POST["DHThumid"]);
$CCS811_CO2 = test_input($_POST["CCS811_CO2"]);
$CCS811_tVOC = test_input($_POST["CCS811_tVOC"]);
$PM25 = test_input($_POST["PM25"]);
$PM10 = test_input($_POST["PM10"]);
$reading_date = date("Y-m-d");
$update_status = test_input($_POST["update_status"]);
$tipo_tabla = test_input($_POST["tipo_tabla"]);
// Create connection
// Check connection
if ($mysqli->connect_error) {
die("Connection failed: " . $mysqli->connect_error);
}
if ($tipo_tabla == "historico"){
$sql = "INSERT INTO SensorData (serial_numb, DHTtempC, DHThumid, CCS811_CO2, CCS811_tVOC, PM25, PM10, reading_date, update_status)
VALUES ('" . $serial_numb . "', '" . $DHTtempC . "', '" . $DHThumid . "', '" . $CCS811_CO2 . "', '" . $CCS811_tVOC . "', '" . $PM25 . "', '" . $PM10 . "', '" . $reading_date . "', '" . $update_status . "')";
}
$sql = "DELETE FROM instant_data WHERE (serial_numb = '" . $serial_numb . "')";
$sql = "INSERT INTO instant_data (serial_numb, DHTtempC, DHThumid, CCS811_CO2, CCS811_tVOC, PM25, PM10, reading_date, update_status)
VALUES ('" . $serial_numb . "', '" . $DHTtempC . "', '" . $DHThumid . "', '" . $CCS811_CO2 . "', '" . $CCS811_tVOC . "', '" . $PM25 . "', '" . $PM10 . "', '" . $reading_date . "', '" . $update_status . "')";
if ($mysqli->query($sql) === TRUE) {
echo "New record created successfully";
}
else {
echo "Error: " . $sql . "<br>" . $mysqli->error;
}
if ($mysqli->connect_error) {
die("Connection failed: " . $mysqli->connect_error);
}
$mysqli->close();
}
else {
echo "No data posted with HTTP POST.";
}
function test_input($data) {
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
return $data;
}
Tu sum up, If the array contains the parameter, INSERTE(TABLE1) + DELETE with same serial_num(TABLE2) + INSERTE(TABLE2). If not DELETE with same serial_num(TABLE2) + INSERTE(TABLE2).
EDIT: Now this code only make the second INSERT
It seems like you are overwriting the content of $sql without executing the queries in between. You have to either:
execute each query before redefining $sql
use $sql .= (instead of $sql =) to concatenate the next query. If you do this, you have to terminate your sql query with an ; before concatenating the next query.
Are you using this code just for an small personal project or are you going to publish this in any way? In case of the later one:
please read into PHP SQL best practices. With your current approach you are vulnerable to SQL injections and your code is kinda difficult to read.

how to check duplicate records in mysql database

$queryb = "SELECT product, imei, country, warranty, config from PRODUCT WHERE product_slno = '$mnserialno' ";
$resultb = mysql_query($queryb, $gndbconn) ;
if(mysql_num_rows($resultb) > 0)
{
$queryc = "UPDATE PRODUCT SET product='$desc', product_slno='$mnserialno',imei='$imei',country='$country',warranty='$warranty',config='$config' WHERE product_slno = '.$mnserialno.' ";
$resutc = mysql_query($queryc, $gndbconn) ;
}
else{
$querya = "INSERT INTO PRODUCT SET product='$desc', product_slno='$mnserialno',imei='$imei',country='$country',warranty='$warranty',config='$config'";
$resulta = mysql_query($querya, $gndbconn) ;
}
I want to check the serial number if that serial number already exist in database so records get update, otherwise it get insert into the database.
but the code inserting the records only, no updation, what is the fault i am not getting,
how to prevent the duplicate entry?
INSERT INTO PRODUCT SET
(`product`, `product_slno`, `imei`, `country`, `warranty`, `config`)
VALUES
('" . $desc . "', '" . $mnserialno . "', '" . $imei . "', '" . $country . "', '" . $warranty . "', '" . $config . "')
ON DUPLICATE KEY UPDATE
product='" . $desc . "',
product_slno='" . $mnserialno . "',
imei='" . $imei . "',
country='" . $country . "',
warranty='" . $warranty . "',
config='" . $config . "'";

MySQL not inserting NULL Value

This is going to be an easy one for you but I'm a noob so I need help.
Here is my code, for whatever reason the else statement isn't executing. If I change the NULL value for a $variable = NULL it works, but enters an empty string into my database rather than the NULL value. Can anyone help with why?
if (isset($_POST['agreeto']))
{
$enter_feedback = "INSERT INTO feedback" . //(initial, surname, country_id, date, friend_score, return_score, service_score, comments)
" VALUES('" . $initial. "', '" . $lastname . "', '" . $country_id . "', NOW(), '" . $friend . "', '" . $return . "', '" . $service . "', '" . $_POST['comments'] . "')";
}else
{
$enter_feedback = "INSERT INTO feedback" . //(initial, surname, country_id, date, friend_score, return_score, service_score, comments)
" VALUES('" . $initial. "', '" . $lastname . "', '" . $country_id . "', NOW(), '" . $friend . "', '" . $return . "', '" . $service . "', " . NULL . ")" or die("couldn't execute my query");
}
MySQL requires the string=NULL and you are passing it the value of the php NULL constant.
if (isset($_POST['agreeto']))
{
$enter_feedback = "INSERT INTO feedback" . //(initial, surname, country_id, date, friend_score, return_score, service_score, comments)
" VALUES('" . $initial. "', '" . $lastname . "', '" . $country_id . "', NOW(), '" . $friend . "', '" . $return . "', '" . $service . "', '" . $_POST['comments'] . "')";
}else
{
$enter_feedback = "INSERT INTO feedback" . //(initial, surname, country_id, date, friend_score, return_score, service_score, comments)
" VALUES('" . $initial. "', '" . $lastname . "', '" . $country_id . "', NOW(), '" . $friend . "', '" . $return . "', '" . $service . "',NULL)" or die("couldn't execute my query");
}
This should work as expected.
Try set the column to int, if this does not work.
INSERT INTO table (val1, val2) VALUES('String Value', NULL);
or set default column value to NULL.
A NULL value can not be enclosed in 'apostrophes'
Think about how you will get the SQL:
INSERT INTO table_name VALUES ('null','');?
The database may understand as a string
Just replace the 'NULL' value with NULL without the quotes.
$enter_feedback = "INSERT INTO feedback" . //(initial, surname, country_id, date, friend_score, return_score, service_score, comments)
" VALUES('" . $initial. "', '" . $lastname . "', '" . $country_id . "', NOW(), '" . $friend . "', '" . $return . "', '" . $service . "', NULL) " or die("couldn't execute my query");
Once you do that and save the record you will see NULL in the database column for that field when you browse via PHPMYADMIN. Please make sure that the field in question "comments" allows NULL.

MySQL Syntax error when inserting

I've got a syntax error in the following code, but I can't find it:
$tableSelect = $_POST["tableSelect"];
$companyName = $_POST["companyName"];
$telephone = $_POST["telephone"];
$fax = $_POST["fax"];
$email = $_POST["email"];
$address = $_POST["address"];
$postcode = $_POST["postcode"];
$category = $_POST["category"];
$contact = $_POST["contact"];
$contactTel = $_POST["contactTel"];
$contactEmail = $_POST["contactEmail"];
$sql = "INSERT INTO '" . $tableSelect . "' ('" . $companyName . "', '" . $telephone . "', '"
. $fax . "', '" . $email . "', '" . $address . "','" . $postcode . "', '" . $category . "',
'" . $contact . "', '" . $contactTel . "', '" . $contactEmail . "')";
mysqli_query($con,$sql);
if (!mysqli_query($con,$sql)) {
die('Error: ' . mysqli_error($con));
}
Cheers!
EDIT: I have modified the code to this:
$sql = "INSERT INTO `" . $tableSelect . "` (name, telephone, fax, email, address, postcode, category,
contact, contactTel, contactEmail) VALUES (`" . $companyName . "`, `" . $telephone . "`, `"
. $fax . "`, `" . $email . "`, `" . $address . "`,`" . $postcode . "`, `" . $category . "`,
`" . $contact . "`, `" . $contactTel . "`, `" . $contactEmail . "`)";
and now have the error "Error: Unknown column [companyName] in 'field list'", where [companyName] is the value submitted through the form. But surely I've defined the column as "name"?
Edit 2: Thanks, I'm now aware of the injection issue. I'd like to get it working, then I'll change it to using prepared statements.
You need either a values statement or a select statement:
"INSERT INTO '" . $tableSelect . "' VALUES ('" . $companyName . "', '" . $telephone . "', '"
. $fax . "', '" . $email . "', '" . $address . "','" . $postcode . "', '" . $category . "',
'" . $contact . "', '" . $contactTel . "', '" . $contactEmail . "')";
However, I would also recommend that you include the column names in the insert statement:
"INSERT INTO '" . $tableSelect ."(companyname, telephone, fax, email, address, postcode, category, contact, contactTel, contactEmail) ".
"' VALUES ('" . $companyName . "', '" . $telephone . "', '"
. $fax . "', '" . $email . "', '" . $address . "','" . $postcode . "', '" . $category . "',
'" . $contact . "', '" . $contactTel . "', '" . $contactEmail . "')";
I'm not sure if those are the correct names.
Ignoring injection issues...
$sql = "
INSERT INTO $tableSelect
(name
,telephone
,fax
,email
,address
,postcode
,category
,contact
,contactTel
,contactEmail
) VALUES
('$companyName'
,'$telephone'
,'$fax'
,'$email'
,'$address'
,'$postcode'
,'$category'
,'$contact'
,'$contactTel'
,'$contactEmail'
);
";
Incidentally, in my (limited) experience, the practice of calling the variable (e.g. '$companyName') and the column (e.g. name) two (slightly) different things can get very confusing.
Use backquotes: ` instead of straight quotes when quoting table names:
instead of:
'" . $companyName . "'
this:
`" . $companyName . "`
Use prepared statements instead of putting the variables into the query directly. And check, that the tables names are correct, cause now you are open to SQL injection.
How can I prevent SQL injection in PHP?
please check insert query syntax
you are missing values in your program:
Follow the below Syntax:
INSERT INTO table_name (column1, column2, column3,...)
VALUES (value1, value2, value3,...)
try query like this
$query="insert into abc (a,b,c) values ('a','b','c')
and first check your all variables using isset()
Please try below query:
$sql = "INSERT INTO $tableSelect ('" . $companyName."', '".$telephone."',
'".$fax."', '".$email."', '".$address."', '".$postcode."', '".$category."',
'".$contact."', '".$contactTel."', '".$contactEmail."')";
If still getting error, then you should use mysql_real_escape_string() function.
Data may contain special characters.

escape null values(Nestoria UK)

I am able to retrieve data from a website(Nestoria) and store into my PostGIS database. However not every individual result that is returned have latitude and longitude values and as such they are not stored into the database. I tried using (pg_escape_string) so that it can return null values as double quotes(") but it didn't work. The field type of my lat and long columns in the database is "double precision".
This is a sample output of the error: ("Warning: pg_query() [function.pg-query]: Query failed: ERROR: invalid input syntax for type double precision: "" LINE 1: ...droom garden flat set in a period building with...', '', '') ^ in C:\XAMMP...\database.php on line 12")
Please see the code below for retrieving the data:
<?php
$url = ("http://api.nestoria.co.uk/api?action=search_listings&centre_point=51.5424,-0.1734,2km&listing_type=rent&property_type=all&price_min=min&price_max=max&bedroom_min=0&bedroom_max=0&number_of_results=50&has_photo=1&page=4");
$xml = simplexml_load_file($url);
foreach ($xml->response->listings as $entry) {
echo $entry->attributes()->title;
echo $entry->attributes()->bathroom_number;
echo $entry->attributes()->bedroom_number;
echo $entry->attributes()->datasource_name;
echo $entry->attributes()->guid;
echo $entry->attributes()->img_url;
echo $entry->attributes()->keywords;
echo $entry->attributes()->lister_name;
echo $entry->attributes()->listing_type;
echo $entry->attributes()->price;
echo $entry->attributes()->price_type;
echo $entry->attributes()->property_type;
echo $entry->attributes()->summary;
echo $entry->attributes()->latitude;
echo $entry->attributes()->longitude;
// Process XML file
}
?>
Find below the code to store values into database:
<?php
require 'nestoriauk.php';
// Opens a connection to a PostgresSQL server
$connection = pg_connect("dbname=postgis user=postgres password=xxxx");
// Execute query
foreach ($xml->response->listings as $entry) {
$query = "INSERT INTO nestoriaphp(title, bathroom, bedroom, datasource, guid, image, keywords, lister, listype, price, pricetype, property_type, summary, latitude, longitude) VALUES ('" . pg_escape_string($entry->attributes()->title) . "', '" . pg_escape_string($entry->attributes()->bathroom_number) . "', '" . pg_escape_string($entry->attributes()->bedroom_number) . "', '" . pg_escape_string($entry->attributes()->datasource_name) . "', '" . pg_escape_string($entry->attributes()->guid) ."', '" . pg_escape_string($entry->attributes()->img_url) . "', '" . pg_escape_string($entry->attributes()->keywords) . "', '" . pg_escape_string($entry->attributes()->lister_name) . "', '" . pg_escape_string($entry->attributes()->listing_type) . "', '" . pg_escape_string($entry->attributes()->price) . "', '" . pg_escape_string($entry->attributes()->price_type) . "', '" . pg_escape_string($entry->attributes()->property_type) ."', '" . pg_escape_string($entry->attributes()->summary) . "', '" . pg_escape_string($entry->attributes()->latitude) . "', '" . pg_escape_string($entry->attributes()->longitude) . "')";
$result = pg_query($query);
printf ("These values are inserted into the database - %s %s %s", $entry->attributes()->title, $entry->attributes()->bathroom_number, $entry->attributes()->bedroom_number, $entry->attributes()->datasource_name, $entry->attributes()->guid, $entry->attributes()->img_url, $entry->attributes()->keywords, $entry->attributes()->lister_name, $entry->attributes()->listing_type, $entry->attributes()->price, $entry->attributes()->price_type, $entry->attributes()->property_type, $entry->attributes()->summary, $entry->attributes()->latitude, $entry->attributes()->longitude);
}
pg_close();
?>
Yemi
If a POI has no lat-lon, which value it has? empty string?
assuming that an empty string is returned when there is no lat-lon.
$lon = "NULL";
if($entry->attributes()->longitude != "")
$lon = "'".$entry->attributes()->longitude."'";
$lat = "NULL";
if($entry->attributes()->latitude != "")
$lat = "'".$entry->attributes()->latitude."'";
so query looks like this:
$query = "INSERT INTO nestoriaphp(title, bathroom, bedroom, datasource, guid, image, keywords, lister, listype, price, pricetype, property_type, summary, latitude, longitude) VALUES ('" . pg_escape_string($entry->attributes()->title) . "', '" . pg_escape_string($entry->attributes()->bathroom_number) . "', '" . pg_escape_string($entry->attributes()->bedroom_number) . "', '" . pg_escape_string($entry->attributes()->datasource_name) . "', '" . pg_escape_string($entry->attributes()->guid) ."', '" . pg_escape_string($entry->attributes()->img_url) . "', '" . pg_escape_string($entry->attributes()->keywords) . "', '" . pg_escape_string($entry->attributes()->lister_name) . "', '" . pg_escape_string($entry->attributes()->listing_type) . "', '" . pg_escape_string($entry->attributes()->price) . "', '" . pg_escape_string($entry->attributes()->price_type) . "', '" . pg_escape_string($entry->attributes()->property_type) ."', '" . pg_escape_string($entry->attributes()->summary) . "', " . $lat . ", " . $lon . ")";
Note that the NULL value has no '' in sql.

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