php multidimensional array if loop - php

Question

I have a multidimensional array like this
$array['value'][1][1]
Now i would like to implement if loop like this
if ($value = $array['value'][1][1]) {
echo "It works";
}
Now it works if i assign the values like [1][1],[2][1].
Is it possible to compare the whole array.
I mean if the array looks like
array[value][1][1],array[value][2][1],..........,array[value][n][1]
It works should be echoed.
I tried like this.
if ($value = $array['value'][][]) {
echo "It works";
}
But its not working. Can anyone give me the correct syntax?

Answer 1

I'm not sure if this is what you're looking for but you could try this function
$value is 1 in your case
function($array,$value)
foreach($array['amazon'] as $val){
if($value != $val[1])return FALSE;
}
return TRUE;
}
The function runs through $array['amazon'][*] and checks condition for each value. If found FALSE for any it returns

Answer 2

Based on your comments of what you're trying to accomplish, I think the following may solve your dilemma. Let me know if I'm going the wrong direction with this or have any additional questions/concerns.
<?php
$forms = array(
'amazon' => array(
0 => array(
1 => 111,
),
1 => array(
1 => 222,
),
2 => array(
1 => 333
)
)
);
$value = 333;
$it_works = False;
foreach($forms['amazon'] as $array) {
if($array[1] == $value) {
$it_works = True;
break;
}
}
if($it_works === True) {
print 'It Works!';
}
?>

Answer 3

You can try this:
$itWorks = true;
for( $a = 0; $a < sizeof( $array[value] ); $a ++ ){
if ( $value != $array[value][$a][1] ){
$itWorks = false;
break;
}
}
if( $itWorks ){
echo "It works";
}
Of course you must replace [value] with a legitimate value

Answer 4

function check() {
for($i = 0; $i < count($array[$value]); $i++) {
if($value != $array[$value][$i][1])
return FALSE;
}
echo 'It works!';
}