Populate multiple tables with data from mysql - php

I'm trying to populate multiple tables from mysql, ordering them by an id. I'm not sure how to do this and can't find much on it on here.
At the moment I am populating just one table from mysql but I've added a new column to my mysql table, which would be the specific id for each table - not sure how to loop this though.
In the predictions table I have a column called 'accid' . I'd like this column to group together a set of results with the same 'accid' and insert into an html table. How do I do this?
Here's what I have at the moment:
$result = mysql_query("SELECT results.home_team, results.away_team, results.home_id,
results.away_id, results.ht_score, results.ft_score, predictions.draw,
predictions.winningid
FROM results
LEFT JOIN predictions ON results.match_id = predictions.matchid
WHERE userid='".$_SESSION['id']."' ORDER BY home_team");
$num_rows = mysql_num_rows($result);
if($num_rows) {
$wonBet = true; #ADDED
$notlong = false;
while ($row = mysql_fetch_assoc($result)) {
echo "<tr>";
if(!$row["ht_score"]) {
$halftime = "-";
} else {
$halftime = $row["ht_score"];
}
if(!$row["ft_score"]) {
$fulltime = "-";
} else {
$fulltime = $row["ft_score"];
}
echo "<td>" . $row["home_team"] . "</td>" . "<td>" . " vs " . "</td>" . "<td>" . $row["away_team"] . "</td>" . "<td>" . $halftime . "</td>" . "<td>" . $fulltime . "</td>";
$value = $fulltime;
$apart = explode('-',$value);
if($apart[0] > $apart[1] && $row["home_id"]==$row["winningid"]) {
$hometeamwin = "Win";
} else if($apart[0] < $apart[1] && $row["away_id"]==$row["winningid"]) {
$hometeamwin = "Win";
} else if($apart[0] == $apart[1] && !$row["winningid"]) {
$hometeamwin = "Win";
} else {
$hometeamwin = "lose";
#ADDED
}
if($fulltime!=$row["ft_score"]) {
$hometeamwin = "";
}
if($hometeamwin == "lose"){ #ADDED
$wonBet = false; #ADDED
}
if($hometeamwin == ""){ #ADDED
$notlong = true; #ADDED
}
echo "<td>" . $hometeamwin . "</td>";
echo "</tr>";
}
echo '</table>';

To use the same query results more than once, fetch them into an array. Then you can loop as many times as you want over the same results.
Oh - and switch to PDO / MySQLi. .. and use prepared statements..

$data = array();
$result = mysql_query("SELECT results.home_team, results.away_team, results.home_id,
results.away_id, results.ht_score, results.ft_score, predictions.draw,
predictions.winningid
FROM results
LEFT JOIN predictions ON results.match_id = predictions.matchid
WHERE userid='".$_SESSION['id']."' ORDER BY home_team");
while($dbrow = mysql_fetch_assoc($result)) {
$data[] = $dbrow;
}
foreach($data as $row) {
//Table
}
foreach($data as $row) {
//Table 2
}
Some ideas about splitting by accid
while($dbrow = mysql_fetch_assoc($result)) {
$accid = $dbrow['accid'];
$data[$accid][] = $dbrow;
}
foreach($data as $accid -> rows) {
//Table Header
foreach($rows as $row) {
//Table Row
}
//Table Footer
}

Related

How to convert from mysqli to PDO with function that hides empty columns

I have an html-form to read out data from a DB that are then dislayed in an html-table. Columns that contain no values should not be displayed. This works well with the following code using array_column and array_filter:
$sql = "SELECT DISTINCT $selection FROM $table WHERE $where";
$result = mysqli_query($db, $sql) or die("<b>No results</b>"); //Running the query and storing it in result
$numrows = mysqli_num_rows($result); // gets number of rows in result table
$numcols = mysqli_num_fields($result); // gets number of columns in result table
$field = mysqli_fetch_fields($result); // gets the column names from the result table
$custom_column_arr = array('Color' => 'color_comment', 'Weight' => 'weight_comment');
if($numrows > 0) {
echo "<table id='myTable'>";
echo "<thead>";
$results = array();
while($row = mysqli_fetch_assoc($result)) {
$results[] = $row;
}
echo "<tr>";
echo "<th>" . 'Nr' . "</th>";
for($x = 0; $x < $numcols; $x++) {
$column[$x] = array_column($results, $field[$x]->name); // puts all existing values of a column into the field-name
if(array_filter($column[$x])) { // displays only those columns with at least one value in it
$key = array_search($field[$x]->name, $custom_column_arr);
if($key !== FALSE) {
echo "<th>" . $key . "</th>";
} else {
echo "<th>" . $field[$x]->name . "</th>";
}
}
}
echo "</tr></thead>";
echo "<tbody>";
$nr = 1;
$result = mysqli_query($db, $sql);
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $nr . "</td>";
for($k = 0; $k < $numcols; $k++) { // goes around until there are no columns left
$column[$k] = array_column($results, $field[$k]->name); // puts all existing values of a column into the field-name
if(array_filter($column[$k])) { // displays only those columns with at least one value in it
echo "<td>" . $row[$field[$k]->name] . "</td>"; //Prints the data } } echo "</tr>"; $nr = $nr + 1;
} // End of while-loop
echo "</tbody></table>";
}
}
mysqli_close($db);
}
Due to security reasons, I switched to PDO prepared statements to avoid SQL-injection:
enter code here
$sql = "SELECT DISTINCT $selection FROM $table WHERE color = :color AND weight = :weight";
$stmt = $pdo->prepare($sql);
$renalstatus = '10';
$bindValue = implode("/n ", $bindValue);
$stmt->bindValue(':color', $color, PDO::PARAM_STR);
$stmt->bindValue(':weight', $weight, PDO::PARAM_INT);
$stmt->execute();
$zeilen = $stmt->rowCount();
$spalten = $stmt->columnCount();
if($zeilen > 0) {
echo "<table id='myTable'>";
echo "<thead>";
$results = array();
while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
$results[] = $row;
}
echo "<tr>";
echo "<th>" . 'Nr' . "</th>";
for($x = 0; $x < $spalten; $x++) {
$column[$x] = array_column($results, $fields[$x]->name); // puts all existing values of a column into the field-name
if(array_filter($column[$x])) { // displays only those columns with at least one value in it
$key = array_search($fields[$x], $custom_column_arr);
if($key !== FALSE) {
echo "<th>" . $key . "</th>";
} else {
echo "<th>" . $fields[$x] . "</th>";
}
}
}
echo "</tr></thead>";
echo "<tbody>";
$nr = 1;
$stmt = $pdo->query($sql);
while($row = $stmt->fetch(PDO::FETCH_NUM)) {
echo "<tr>";
echo "<td>" . $nr . "</td>";
for($k = 0; $k < $spalten; $k++) { // goes around until there are no columns left
$column[$k] = array_column($results, $fields[$k]->name); // puts all existing values of a column into the field-name
if(array_filter($column[$k])) { // displays only those columns with at least one value in it
echo "<td>" . $row[$k] . "</td>"; //Prints the data}
}
echo "</tr>";
$nr = $nr + 1;
} // End of while-loop
echo "</tbody></table>";
}
}
$stmt->close();
The query results are correctly displayed as before. However, completely empty columns are displayed as well and shoul be hidden.
After having built the headline, in mysqli there is a second query before the rows are generated:
$result = mysqli_query($db, $sql);
Unfortunately, using PDO this does not work with:
$stmt = $pdo->query($sql); or $stmt->execute();
I would be more than happy if someone could help me make this function work again!

How to integrate array_column() and array_filter() into dynamic table generation of sql results

I want to read out data from an sql-database an show them in a table. This works well. Now, I would like to show only those columns with at least one value in it and not the empty ones (containing NULL, 0, empty string). This works with the following example:
enter code here
<TABLE width="500" border="1" cellpadding="1" cellspacing="1">
<?php
$query = mysql_query("SELECT * FROM guestbook", $db);
$results = array();
while($line = mysql_fetch_assoc($query)){
$results[] = $line;
$Name = array_column($results, 'Name');
$Home = array_column($results, 'Home');
$Date = array_column($results, 'Date');
$Emptycolumn = array_column($results, 'Emptycolumn');
$Comment = array_column($results, 'Comment');
$City = array_column($results, 'City');
}
echo "<TR>";
if(array_filter($Name)) {echo "<TH>Name</TH>";}
if(array_filter($Home)){echo "<TH>Home</TH>";}
if(array_filter($Date)){echo "<TH>Date</TH>";}
if(array_filter($Emptycolumn)){echo "<TH>Emptycolumn</TH>";}
if(array_filter($Comment)){echo "<TH>Comment</TH>";}
if(array_filter($City)){echo "<TH>City</TH>";}
echo "</TR>";
$query = mysql_query("SELECT * FROM guestbook", $db);
while($line = mysql_fetch_assoc($query)){
echo "<TR>";
if(array_filter($Name)) {echo "<TD>".$line['Name']."</TD>";}
if(array_filter($Home)) {echo "<TD>".$line['Home']."</TD>";}
if(array_filter($Date)) {echo "<TD>".$line['Date']."</TD>";}
if(array_filter($Emptycolumn)) {echo "<TD>".$line['Emptycolumn']."</TD>";}
if(array_filter($Comment)) {echo "<TD>".$line['Comment']."</TD>";}
if(array_filter($City)) {echo "<TD>".$line['City']."</TD>";}
echo "</TR>";
}
?>
</TABLE>
Since the column-names of my table are highly variable (depending on the query), the table is generated by looping through the result-array, first the column-names, then the values in the rows:
enter code here
$sql = "SELECT DISTINCT $selection FROM $tabelle WHERE
$whereclause"; //will be changed to PDO
$result = mysqli_query($db, $sql) or die("<b>No result</b>"); //Running
the query and storing it in result
$numrows = mysqli_num_rows($result); // gets number of rows in result
table
$numcols = mysqli_num_fields($result); // gets number of columns in
result table
$field = mysqli_fetch_fields($result); // gets the column names from the
result table
if ($numrows > 0) {
echo "<table id='myTable' >";
echo "<thead>";
echo "<tr>";
echo "<th>" . 'Nr' . "</th>";
for($x=0;$x<$numcols;$x++){
$key = array_search($field[$x]->name, $custom_column_arr);
if($key !== false){
echo "<th>" . $key . "</th>";
}else{
echo "<th>" . $field[$x]->name . "</th>";
}
}
echo "</tr></thead>";
echo "<tbody>";
$nr = 1;
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $nr . "</td>";
for ($k=0; $k<$numcols; $k++) { // goes around until there are no
columns left
echo "<td>" . $row[$field[$k]->name] . "</td>"; //Prints the data
}
echo "</tr>";
$nr = $nr + 1;
} // End of while-loop
echo "</tbody></table>";
}
}
mysqli_close($db);
Now, I tried to integrate the array_column() and array_filter()-blocks of the example above into the loops, but unfortunately, it didn´t work. I´m sure, this is easy for a professional and I would be very grateful, if someone could help me with this problem!
Thank you very much in advance!!

output data based on two tables

I need to output a table based on two other tables as shown below:
case: there are two table "tbl_schedule" and "tbl_report"
this is my script:
$sql = mysql_query("SELECT*, count(*) as schedule_date FROM mst_schedule WHERE schedule_date LIKE '%$date' GROUP BY schedule_account") or die (mysql_error());
while ($data = mysql_fetch_array($sql)) {
$account = schAccount($data['schedule_account']);
$sql2 = mysql_query("SELECT * FROM trn_reportsch WHERE schedule_id='$data[schedule_id]' GROUP BY schedule_id");
echo "<tr>";
echo "<td>".ucfirst($account['admin_fullname'])."</td>";
while ($data2 = mysql_fetch_array($sql2)) {
echo "<td>".$data2['rating']."</td>";
}
echo "<td>".$data['schedule_date']."</td>";
echo "</tr>";
}
So far I don't get the desired output. How should I change the script?
Your code is almost correct.
Add following lines:
$sql = mysql_query("SELECT*, count(*) as schedule_date FROM mst_schedule WHERE schedule_date LIKE '%$date' GROUP BY schedule_account") or die(mysql_error());
while ($data = mysql_fetch_array($sql)) {
$account = schAccount($data['schedule_account']);
$sql2 = mysql_query("SELECT * FROM trn_reportsch WHERE schedule_id='$data[schedule_id]' GROUP BY schedule_id");
echo "<tr>";
echo "<td>" . ucfirst($account['admin_fullname']) . "</td>";
$bad = $good = $vGood = 0; // <-- ADD THIS LINE
while ($data2 = mysql_fetch_array($sql2)) {
if($data2['rating'] <=2){ // BAD
$bad++;
} else if($data2['rating'] <= 3){ // GOOD
$good++;
} else if($data2['rating'] > 3){ // VERY GOOD
$vGood++;
}
}
echo "<td>" . $bad . "</td>"; // Display the final value for bad
echo "<td>" . $good . "</td>"; // Display the final value for good
echo "<td>" . $vGood . "</td>"; // Display the final value for very good
echo "<td>" . $data['schedule_date'] . "</td>";
echo "</tr>";
}

array_push only returns the last element pushed in?

The $orders variable only returned the last pushed element of the array , instead of returning all elements .. I did use array_push to push the elements to the array $orders but I only get the last element pushed in ...
// Create arrays to populate so that I can iterate over them to display the data on the charts
$views = array();
$orders = array();
if ($pid == 11 && $value > 1631 && $value <= 1635) {
$query = "SELECT label, hits FROM items WHERE item_id='$value' LIMIT 1";
$result = mysql_query($query);
$row = mysql_fetch_assoc($result);
echo "<td>" . $row['label'] . "</td>";
// orders
if ($row['hits'] != 0) {
echo "<td>" . $row['hits'] . "</td>";
}else{
echo "<td>0</td>";
}
} else {
$query = "SELECT label FROM items WHERE item_id='$value' LIMIT 1";
$result = mysql_query($query);
while($row = mysql_fetch_assoc($result)){
echo "<td>" . strip_tags(DecodeSpecialChars(html_entity_decode($row['label']))) . "</td>";
if(array_key_exists('label',$row)) {
array_push($orders,$row['label']); // pushing here ..
}
if ($pid != 58) {
// orders
if (isset($totals[$value]) && $totals[$value] != 0) {
echo "<td>" . $totals[$value] . "</td>";
}else{
echo "<td> 0 </td>";
}
}
}
var_dump($orders);
You have a limit 1 clause on your query... you will only get one result to push

Displaying data from database in table

I am trying to display data in table form with 3 columns. Each should have a main category with some drop down lists. I get all the information to display but all is in one column and the drop down information does not display with the correct heading.
echo "<table>";
while ($row = mysql_fetch_array($result)) {
$count = 1;
if ($count = 1) {
$sCatID = ($row['CatID']);
echo "<tr valign='top'><td><b><a href='#" . $sCatID . "'>" . $sCatID . "</a></b><br>";
// column 1 categories
$result2 = mysql_query("SELECT * FROM test_prefixSubCat WHERE CatID=$sCatID");
// sub-cats
while ($row2 = mysql_fetch_array($result2)) {
$sSub = ($row2['CatID']);
$sSubID = ($row2['SubID']);
echo "<dd><a href='#'>" . $sSub . "</a><br>";
echo "</td>";
}
$count = 2;
} elseif ($count = 2) {
$sCatID = ($row['CatID']);
echo "<td><b><a href='.$sCatID.'>" . $sCatID . "</a></b><br>";
// column 1 categories
$result2 = mysql_query("SELECT * FROM test_prefixSubCat WHERE CatID=$sCatID");
// sub-cats
while ($row2 = mysql_fetch_array($result2)) {
$sSub = ($row2['CatID']);
$sSubID = ($row2['SubID']);
echo "<dd><a href='#'>" . $row2['Sub'] . "</a><br>";
echo "</td>";
}
$count = 3;
} elseif ($count = 3) {
$sCatID = ($row['CatID']);
echo "<td><b><a href='.$sCatID.'>" . $sCatID . "</a></b><br>";
// column 1 categories
$result2 = mysql_query("SELECT * FROM test_prefixSubCat WHERE CatID=$sCatID");
// sub-cats
while ($row2 = mysql_fetch_array($result2)) {
$sSub = ($row2['CatID']);
$sSubID = ($row2['SubID']);
echo "<dd><a href='.$sSub.'>" . $sSub . "</a><br>";
echo "</td></tr>";
}
$count = 1;
}
}
if ($count = 2) {
echo "<td> </td><td> </td></tr>";
} elseif ($count = 3) {
echo "<td> </td></tr>";
}
echo "</table>";
It doesn't seem to close the rows and table correctly... And it is also putting some of the drop down items before it displays the first heading.
If i display it in only one column it is working fine.
You should use == instead of single = in your if statements. Else it would execute everytime as that condition is always true.

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