MySQL skipping first row - php

Question

I have seen other people with that problem but the solutions I've seen aren't helping me, or I don't know how to use them :P
<?php
$ordre = "nom";
$croissance = "ASC";
if(isset($_GET["ordre"])){
$ordre = $_GET["ordre"];
};
if(isset($_GET["croissance"])){
$croissance = $_GET["croissance"];
};
$con = mysql_connect('localhost','root','');
mysql_select_db('sdj_jeux', $con);
$sql = "SELECT * FROM jeux ORDER BY $ordre $croissance";
$result = mysql_query($sql, $con);
$row = mysql_fetch_array($result);
$couleurcompteur = 0;
while ($row = mysql_fetch_array($result)){
$couleurcompteur += 1;
if($couleurcompteur % 2){
$classe = "pale";
} else {
$classe = "fonce";
};
?>
My code is skipping the first row of my database and I don't understand why.

Answer 1

Remove the line:
$row = mysql_fetch_array($result);
The while loop will grab the first row on the first iteration.
Resulting code:
<?php
$ordre = "nom";
$croissance = "ASC";
if(isset($_GET["ordre"])){
$ordre = $_GET["ordre"];
};
if(isset($_GET["croissance"])){
$croissance = $_GET["croissance"];
};
$con = mysql_connect('localhost','root','');
mysql_select_db('sdj_jeux', $con);
$sql = "SELECT * FROM jeux ORDER BY $ordre $croissance";
$result = mysql_query($sql, $con);
$couleurcompteur = 0;
while ($row = mysql_fetch_array($result)){
$couleurcompteur += 1;
if($couleurcompteur % 2){
$classe = "pale";
} else {
$classe = "fonce";
};
?>

Answer 2

Right here is your problem:
$row = mysql_fetch_array($result);
$couleurcompteur = 0;
while ($row = mysql_fetch_array($result)){
You call mysql_fetch_array() once before the while. This throws out the first row since you don't use it. Remove that un-needed call.
NOTICE: Do not use MySQL_* for it has been deprecated as of PHP 5.5. Use MySQLi_* or PDO instead