I got a table named "Serials" with 5 comumns
Serial, Code, Name, Redeemed, Redeem_date
i am selecting some fields from that table with this query:
$query = "SELECT `Name`,`Redeemed`,`Redeem_date` FROM `Serials` WHERE `Serial` = '$serial' AND `Code` = '$code'";
$db->setQuery($query);
$db->query();
But i dont know how to pass these values in the following variables so i can use them in if statements later
$name= //retured value from column Name
$redeemed= //retured value from column Redeemed
$redeem_date= //retured value from column Redeem_date
just like this..
// Your query here..
$query = "SELECT `Name`,`Redeemed`,`Redeem_date` FROM `Serials` WHERE `Serial` = '$serial' AND `Code` = '$code'";
$db->setQuery($query);
$results = $db->query();
//fetch data and stored into variables
while($row = fetch_array($results)){
$name = $row['Name'];
$redeemed = $row['Redeemed'];
$redeem_date = $row['Redeem_date'];
}
try something like this :
<?php
$result = $db->query("SELECT `Name`,`Redeemed`,`Redeem_date` FROM `Serials` WHERE `Serial` = '$serial' AND `Code` = '$code'");
while (list($name, $redeemed, $redeem_date) = $result->fetch(PDO::FETCH_NUM)) {
// DO SOMETHING
}
?>
while ($row = $db->fetch()) {
$name= $row['name'];
$redeemed= $row['redeemed'];
$redeem_date= $row['redeem_date'];
}
this one might fetch your results and assign to vars
Related
How can I get a single column value from mysqli? The result should be single row with only one column.
This is what I have tried:
$query = "SELECT MAX(`userid`) FROM `user`";
$rlt = mysqli_query($this->db, $query);
echo $rlt['userid'];
You are not fetching the row after executing the query:
$query = "SELECT MAX(`userid`) FROM `user'";
$rlt = mysqli_query($this->db,$query);
$row = mysqli_fetch_row($this->db, $rlt);
echo $row[0];
The alternative would be to use an alias for the computed field and use fetch_assoc:
$query = "SELECT MAX(`userid`) as `maxid` FROM `user'";
$rlt = mysqli_query($this->db,$query);
$row = mysqli_fetch_assoc($this->db, $rlt);
echo $row['maxid'];
try with create alias and fetch result after query execution also your quote of user' looking wrong
$query = "SELECT MAX(`userid`) as userid FROM `user`";
$rlt = mysqli_query($this->db,$query);
$r = mysqli_fetch_assoc($rlt);
echo $r['userid'];
or fetch only one row like:-
$r = mysqli_fetch_row($this->db, $rlt);
echo $r[0];
You should create alias here.
Use this one:
$query = "SELECT MAX(`userid`) as Max_Userid FROM `user'";
$rlt = mysqli_query($this->db,$query);
$row = mysqli_fetch_assoc($this->db, $rlt);
echo $row['Max_Userid'];
Note: Always use alias when you use mysql function in query with fields.
is there an issue with PHP not allowing multiple function parameters and returning the correct value. Here is the code:
function getConfig($name) {
$sql = "SELECT value FROM config WHERE name = '".$name."'";
$result = mysql_query($sql);
$row = mysql_fetch_assoc($result);
print $row["value"];
}
getConfig("name");
While the code above works, the code bellow similar does not work. Here is the code:
function getConfig($name, $from) {
$sql = "SELECT value '".$from."' config WHERE name = '".$name."'";
$result = mysql_query($sql);
$row = mysql_fetch_assoc($result);
print $row["value"];
}
getConfig("name", "config");
Why does that occur that the 1st function works and the second does not?
$sql = "SELECT value FROM '".$from."' WHERE name = '".$name."'";
// FROM TABLE_NAME
// and not TABLE_NAME TABLE_NAME
I have the following table:
CREATE TABLE list(
country TINYINT UNSIGNED NOT NULL,
name VARCHAR(10) CHARACTER SET latin1 NOT NULL,
name_index INT UNSIGNED NOT NULL,
UNIQUE KEY(country, name), PRIMARY KEY(country, name_index)) ENGINE = INNODB
I want to:
Given: ($country, $name, $new_index)
Check if a row with country = $country && name = $name exists.
If the row exists, get the index $index = name_index.
If the row doesn't exist, add it and then get the index.
I can do the following using many queries, but I am looking for an efficient way to do it, using only one query. Is this possible?
It's not possible with only one query.
You CAN do this:
$sql = "SELECT name_index FROM (your table) WHERE country = '$country' AND
name = '$name' LIMIT 1";
$query = mysql_query($sql);
$numrows = mysql_num_rows($query);
if($numrows == 1) {
$row = mysql_fetch_row($query);
$index = $row[0];
} else {
$sql = "INSERT INTO (your table) (country, name)
VALUES('$country','$name')";
$query = mysql_query($sql);
$check = mysql_num_rows($query);
if($check > 0) {
$sql = "SELECT name_index FROM (your table) WHERE country = '$country' AND
name = '$name' LIMIT 1";
$query = mysql_query($sql);
$row = mysql_fetch_row($query);
$index = $row[0];
} else {
echo "Error occured while trying to insert new row";
}
}
Hope this helps :).
I am trying to do a basic mysql update using AES_ENCRYPT in PHP but I cant get it work.
Here is my full code:
$key = "bac09c63f34c9845c707228b20cac5e0";
$query = " SELECT id, aes_decrypt(Column1, '$key') AS Column1, aes_decrypt(Column2, '$key') AS Column2 FROM parent WHERE Request = '{$Request}' ORDER BY ID ASC;";
$resultSet = mysql_query($query, $DB);
while ($row = mysql_fetch_array($resultSet)) {
$id = $row['ID'];
$rows[] = $row["Request"];
$Column1 = $row["Column1"];
$Column2 = $row["Column2"];
$SQL = "UPDATE parent SET Column1 = AES_ENCRYPT('$Column1','$key'), Column2 = AES_ENCRYPT('$Column2','$key') WHERE Parent_ID = '$id';";
if (!mysql_query($SQL, $DB))
die("Query Failed $SQL");
}
PHP error log is fine, there is no error. Only this:
Query Failed
UPDATE parent SET Column1 = AES_ENCRYPT('722225374673255299521908919676768...etc','bac09c63f34c9845c707228b20cac5e0')
Use this query -
UPDATE parent SET Column1 = AES_ENCRYPT('$Column1','$key'), Column2 = AES_ENCRYPT('$Column2','$key') WHERE Parent_ID = $id;
Assuming I have a uniqid key in my table and that same key is sent to my site in a get method, how do I pull that specific key out and assign all the data from the table to variables. This is what I have so far but cant seem to figure it out.
$query1 = "SELECT *
FROM todo_item2 as ti INNER JOIN todo_category2 as tc ON ti.todo_id = tc.todo_id'
WHERE todo_id = :todo_id";
$statement1 = $db->prepare($query1);
$statement1 -> execute(array(
'todo_id' =>$id
));
while ($row = $statement1->fetch())
{
$text = $row['todo'];
$cat = $row['category'];
$percent = $row['precent'];
$date = $row['due_date'];
}
You should ready about what execute actually does .. the parameters to execute (and I assume you're using PDO or something similar here) are the tokens of the query. What you want is something like:
$query = " ... WHERE todo_id = ?"
$stmt = $db->prepare($query);
$stmt->execute(array($id));
while ($row = $stmt->fetch()) {
//$row is now an associative array of row values.
}
// Start the Load
$query1 = "SELECT *
FROM todo_item2 as ti INNER JOIN todo_category2 as tc ON ti.todo_id = tc.todo_id
WHERE ti.todo_id = :todo_id";
$statement1 = $db->prepare($query1);
$statement1 -> execute(array(
'todo_id' =>$id
));
// Make Sure the Data Exists
if( $statement1->rowCount() == 0 )
{
die('Please Enter a Valid ID Tag - (id)');
}
while($row = $statement1->fetch())
{
$text = $row['todo'];
$cat = $row['category'];
$percent = $row['percent'];
$date = $row['due_date'];
}