mysql_fetch_array() expect parameter 1 - php

Question

I tried to show some data from database with select option from the first page
but I got two error when the page tried to retrieve the data from database
the errors are
mysql_num_rows() expects parameter 1 to be resource, boolean given
and
mysql_fetch_array() expects parameter 1 to be resource, boolean given
this is my code
<?php
//connect to server
$connect = mysql_connect("localhost", "root", "");
//connect to database
//select the database
mysql_select_db("fak_databases");
//submit button
if($_POST['formSubmit'] == "Submit")
{
$country = $_POST['country'];
}
//query the database
if($country == TRUE) {
$order = "";
$sort = "asc";
$sql = "SELECT wipo_applicant1_city, applicant1_addr1 WHERE applicant1_country='$country' FROM auip_wipo_sample";
if(isset($_GET['orderby'])){
$order = $_GET['orderby'];
$sort = $_GET['sort'];
//limiting the possible values of order/sort variables
if($order != 'wipo_applicant1_city' && $order != 'applicant1_addr1')$order = "applicant1_addr1";
if($sort != 'asc' && $sort != 'desc')$sort = "asc";
$sql = "SELECT wipo_applicant1_city, applicant1_addr1 FROM auip_wipo_sample WHERE applicant1_country='$country' ORDER BY ".mysql_real_escape_string($order)." ".$sort;
//here we reverse the sort variable
if($sort == "asc"){
$sort = "desc";
}
else{
$sort = "asc";
}
}
}
$result = mysql_query($sql);
$num_rows = mysql_num_rows($result);
$row_counter = 0;
$icon = "";
echo "<table border=\"1\" cellspacing=\"0\">\n";
echo "<tr>\n";
// first column
echo "<th>";
$icon = "";
if($order == "wipo_applicant1_city"){
if($sort == "asc"){
$icon = "<img src=\"images/up.png\" class=\"arrowSpace\"/>";
}
if($sort == "desc"){
$icon = "<img src=\"images/down.png\" class=\"arrowSpace\"/>";
}
}
//print the result
echo "<a href='index.php?orderby=wipo_applicant1_city&sort=".$sort."'>City</a>".$icon;
echo "</th>\n";
// second column
echo "<th>";
$icon = "";
if($order == "applicant1_addr1"){
if($sort == "asc"){
$icon = "<img src=\"images/up.png\" class=\"arrowSpace\"/>";
}
if($sort == "desc"){
$icon = "<img src=\"images/down.png\" class=\"arrowSpace\"/>";
}
}
echo "<a href='index.php?orderby=applicant1_addr1&sort=".$sort."'>Address</a>".$icon;
echo "</th>\n";
echo "</tr>";
//fetch the result
while($row = mysql_fetch_array($result))
{
if($row_counter % 2){
$row_color="bgcolor='#FFFFFF'";
}else{
$row_color="bgcolor='#F3F6F8'";
}
echo "<tr class=\"TrColor\" ".$row_color.">";
echo "<td>" . $row['wipo_applicant1_city'] . "</td>\n";
echo "<td>" . $row['applicant1_addr1'] . "</td>\n";
echo "</tr>";
$row_counter++;
}
Print "</table>";
?>
the line got error are
$num_rows = mysql_num_rows($result);
and
while($row = mysql_fetch_array($result))
I think I already gave parameter in this line
$result = mysql_query($sql);
anyone know how to fix this?
thanks

Answer 1

try this
$sql = "SELECT wipo_applicant1_city, applicant1_addr1 FROM auip_wipo_sample WHERE
applicant1_country='".$country."'";