Query was empty PHP error - php

I am trying to build a cart using MySQL. I keep getting this error 'Query was empty' when I run this code. Please help I've tried several things such as putting the variables inside the string instead of concatenating it.
<?php ob_start(); ?><?php require_once("../include/membersite_config.php"); ?>
<?php
require('../products_reloaded/config.php');
session_start();
$user = $_REQUEST['user'];
$user = mysql_real_escape_string($user);
$itemNum = $_REQUEST['itemNum'];
$itemNum = mysql_real_escape_string($itemNum);
$quantity = $_POST['quantity'];
$quantity = intval($quantity);
$CheckForExistence = mysql_query("select * from cart where user = '$user' and p_number = '$itemNum'" );
$alreadyExistsChecker = mysql_num_rows($CheckForExistence);
if($alreadyExistsChecker >= 1)
{
$quantity +=1;
echo "this is equal to $alreadyExistsChecker";
}
if($alreadyExistsChecker == 0)
{
$getQuery = mysql_query("select * from product where p_number = '$itemNum'");
while($row = mysql_fetch_array($getQuery))
{
$name = $row['p_name'];
$image = $row['p_url'];
$price = $row['p_price'];
}
$name = mysql_real_escape_string($name);
$image = mysql_real_escape_string($image);
$price = intval($price);
$query = mysql_query('insert into cart values('.$user.','.$itemNum.','.$name.', '.$image.','.$quantity.', '.$price.')');
$result = mysql_query($query);
if (!$result) {
print "An error occured: " . mysql_error() . "\n";
}
}
header('http://www.definitionxjm.com/shopping/viewCart.php');
?>

What do you try to achieve with this line?
$result = mysql_query($query);
Just delete it and change the line above to
$result = mysql_query('insert into cart values('.$user.','.$itemNum.','.$name.', '.$image.','.$quantity.', '.$price.')');
[Edit]
Btw. you are forgetting the " (quotes) inside the query which causes an sql error to occur, leading to $query = false (see manual). $query (false) then gets converted to string, resulting in '' (an empty string) which you pass to mysql_query and that generates an "Query was empty"-Message, as it should because you tried to send an empty query.

It can also mean the table which is in consideration is empty.This condition arises when the "DELETE FROM table_name where ;" is used. Here if the table "table_name" has no data, it cannot delete anything and hence it shows an error stating that the query is empty.

Related

PHP count(): warning

I'm making a simple CRUD single page application using PHP connected to a msqli database. All parts of the page work except for the "EDIT" function. It returns the warming "count(): Parameter must be an array or an object that implements Countable line 8"
<?php
include('server.php');
if (isset($_GET['edit'])) {
$id = $_GET['edit'];
$update = true;
$record = mysqli_query($db, "SELECT * FROM eBook_MetaData WHERE id=$id");
if (count($record) == 1 ) {
$n = mysqli_fetch_array($record);
$creator = $n['creator'];
$title = $n['title'];
$type = $n['type'];
$identifier = $n['identifier'];
$date = $n['date'];
$language = $n['language'];
$description = $n['description'];
}
}
?>
any help with this would be appreciated.
Use mysql_num_rows for checking numbers of row
I have a feeling its your sql query too. Try this instead $record = mysqli_query($db, "SELECT * FROM eBook_MetaData WHERE id='$id'");

Query was Empty error in php using PDO [duplicate]

I am trying to build a cart using MySQL. I keep getting this error 'Query was empty' when I run this code. Please help I've tried several things such as putting the variables inside the string instead of concatenating it.
<?php ob_start(); ?><?php require_once("../include/membersite_config.php"); ?>
<?php
require('../products_reloaded/config.php');
session_start();
$user = $_REQUEST['user'];
$user = mysql_real_escape_string($user);
$itemNum = $_REQUEST['itemNum'];
$itemNum = mysql_real_escape_string($itemNum);
$quantity = $_POST['quantity'];
$quantity = intval($quantity);
$CheckForExistence = mysql_query("select * from cart where user = '$user' and p_number = '$itemNum'" );
$alreadyExistsChecker = mysql_num_rows($CheckForExistence);
if($alreadyExistsChecker >= 1)
{
$quantity +=1;
echo "this is equal to $alreadyExistsChecker";
}
if($alreadyExistsChecker == 0)
{
$getQuery = mysql_query("select * from product where p_number = '$itemNum'");
while($row = mysql_fetch_array($getQuery))
{
$name = $row['p_name'];
$image = $row['p_url'];
$price = $row['p_price'];
}
$name = mysql_real_escape_string($name);
$image = mysql_real_escape_string($image);
$price = intval($price);
$query = mysql_query('insert into cart values('.$user.','.$itemNum.','.$name.', '.$image.','.$quantity.', '.$price.')');
$result = mysql_query($query);
if (!$result) {
print "An error occured: " . mysql_error() . "\n";
}
}
header('http://www.definitionxjm.com/shopping/viewCart.php');
?>
What do you try to achieve with this line?
$result = mysql_query($query);
Just delete it and change the line above to
$result = mysql_query('insert into cart values('.$user.','.$itemNum.','.$name.', '.$image.','.$quantity.', '.$price.')');
[Edit]
Btw. you are forgetting the " (quotes) inside the query which causes an sql error to occur, leading to $query = false (see manual). $query (false) then gets converted to string, resulting in '' (an empty string) which you pass to mysql_query and that generates an "Query was empty"-Message, as it should because you tried to send an empty query.
It can also mean the table which is in consideration is empty.This condition arises when the "DELETE FROM table_name where ;" is used. Here if the table "table_name" has no data, it cannot delete anything and hence it shows an error stating that the query is empty.

MYSQL Results; no records found statement [duplicate]

This question already has an answer here:
Closed 10 years ago.
Possible Duplicate:
Display Data From MYSQL; SQL statement error
I have the code below displaying data from a MYSQL database (currently looking into sql injection issue) I need to insert an error message when no results are found...not sure where to position this! I have tried the code if( mysql_num_rows($result) == 0) {
echo "No row found!" but keep on gettin syntax errors, does anyone know the correct position in the code for this?
--
require 'defaults.php';
require 'database.php';
/* get properties from database */
$property = $_GET['bedrooms'] ;
$sleeps_min = $_GET['sleeps_min'] ;
$availability = $_GET['availability'] ;
$query = "SELECT * FROM `properties` WHERE bedrooms = '{$bedrooms}' AND sleeps_min = '{$sleeps_min}' AND availability = '{$availability}'";
$row=mysql_query($query);
$result = do_query("SELECT * FROM `properties` WHERE bedrooms = '{$bedrooms}' sleeps_min = '{$sleeps_min}' AND availability = '{$availability}'", $db_connection);
while ($row = mysql_fetch_assoc($result))
{
$r[] = $row;
}
?>
I have found few errors in your code that in line
$query = "SELECT * FROM `properties` WHERE bedrooms = '{$bedrooms}' AND sleeps_min = '{$sleeps_min}' AND availability = '{$availability}'";
$row=mysql_query($query);
You use bedrooms = '{$bedrooms}' but $bedrooms is not variable in whole cod it must be $preopery. I have made a few changes in your code given below please try it.
<?php
require 'defaults.php';
require 'database.php';
/* get properties from database */
/*if get $_GET['bedrooms'] value else ''*/
if (isset($_GET['bedrooms'])) {
$property = $_GET['bedrooms'];
} else {
$property = '';
}
/*if get $_GET['sleeps_min'] value else ''*/
if (isset($_GET['sleeps_min'])) {
$sleeps_min = $_GET['sleeps_min'];
} else {
$sleeps_min = '';
}
/*if get $_GET['availability'] value else ''*/
if (isset($_GET['availability'])) {
$availability = $_GET['availability'];
} else {
$availability = '';
}
$query = "SELECT * FROM `properties` WHERE bedrooms = '" . $property . "' AND sleeps_min = '" . $sleeps_min . "' AND availability = '" . $availability . "'";
$result = mysql_query($query) or die(mysql_error());
if ($result) {
while ($row = mysql_fetch_assoc($result)) {
$r[] = $row;
}
}
?>
Do var_dump($GET_) to debug whether you are getting valid strings. If any of these are blank, the query will try to match blank values instead of NULL. You should prevent this by doing:
if(!$_GET['bedrooms'] || $_GET['bedrooms'] == ''){
$property = 'NULL';
}//repeat for all three
$query = "SELECT * FROM `properties` WHERE 'bedrooms' = '$bedrooms' AND 'sleeps_min' = '$sleeps_min' AND 'availability' = '$availability'";
Instead of:
while ($row = mysql_fetch_assoc($result)) {
$r[] = $row;
}
You can simply do:
$r = mysql_fetch_array($query);
But enclose that in a conditional to see if your query found anything:
if(mysql_affected_rows() > 0){
//your code here will execute when there is at least one result
$r = mysql_fetch_array($query);
}
else{//There was either nothing or an error
if(mysql_affected_rows() == 0){
//There were 0 results
}
if(mysql_affected_rows() == -1) {
//This executes when there is an error
print mysql_error(); //not recommended except to debug
}
}

Data insert problem within foreach loop

The problem is that only some of the XML data is being Inserted into the my mysql database. 10 results are supposed to be entered into the database but it varies between 2 and 8 results. I have no idea why it is doing this and I have tried adding a sleep function to slow the script down, but the data that is inserted into the data base is never as much as when I echo it out on screen. Any help would be much appreciated..
function post_to_db($xml,$cat_id){
if ($xml->Items->Request->IsValid == 'True'){
$xml = $xml->Items->Item;
foreach($xml as $item){
$asin = (string)$item->ASIN;
$title = (string)$item->ItemAttributes->Title;
$content = (string)
$item->EditorialReviews->EditorialReview->Content;
$sku = (string)$item->ItemAttributes->SKU;
$brand = (string)$item->ItemAttributes->Brand;
$feature = (string)$item->ItemAttributes->Feature;
$model_no = (string)$item->ItemAttributes->Model;
$review = (string)$item->ItemLinks->ItemLink[5]->URL;
$check = "SELECT * FROM `products` WHERE `asin` = '$asin'";
$checked = mysql_query($check);
$numrows = mysql_num_rows($checked);
if ($numrows == 0){
$query = "INSERT INTO `products`".
"(`cat_id`,`asin`,`sku`,`brand`,".
"`model_no`,`title`,`content`,`feature`) ".
"VALUES".
"('$cat_id','$asin','$sku','$brand',".
"'$model_no','$title',".
"'$content','$feature')";
$result = mysql_query($query);
$post_id = mysql_insert_id();
$review_page[] = array($post_id=>$review);
}
}
}
return $review_page;
}
My guess would be some of your variables from XML are creating an invalid query (do they contain quotes?)
Instead of this for each variable:
$asin = (string)$item->ASIN;
Do this instead:
$asin = mysql_real_escape_string((string)$item->ASIN);
If the problem still persists, change your mysql_query line to this for debugging:
$result = mysql_query($query) or die(mysql_error());

Need Help With Implementing Simple Stuff with PHP and MYSQL

Here is my code -
<?php
$u = $_SESSION['username'];
while($fetchy = mysqli_fetch_array($allusers))
{
mysqli_select_db($connect,"button");
$select = "select * from button where sessionusername='$u' AND response = 'approve'";
$query = mysqli_query($connect,$select) or die('Oops, Could not connect');
$result= mysqli_fetch_array($query);
$email = mysqli_real_escape_string($connect,trim($result['onuser']));
echo $email;
if($email){
mysqli_select_db($connect,"users");
$select_name = "select name, icon from profile where email = '$email'";
$query_2 = mysqli_query($connect,$select_name) or die('Oops, Could not connect. Sorry.');
$results= mysqli_fetch_array($query_2);
$name = mysqli_real_escape_string($connect,trim($results['name']));
$icon = mysqli_real_escape_string($connect,trim($results['icon']));
echo $name;
}
}
NOw, there are two reponses in db. So, two names are getting echoed, but they both are SAME. Why so? Eg
DB - NAMEs - Apple and Orange.
Displayed - Apple Apple.
Database example -
SESSIONUSERNAME OnUSer
s#s.com apple
s#s.com orange
EDITED
Using #endophage's method -
AppleOrange and AppleOrange.
As your loop stands now, $u will always be the same, so $select will always have the same value, and so will $email, and so will $select_name, so it is no surprise that the same record keeps coming back.
Edit
If the $select_name query returns multiple results, then you need to loop through the results with a while loop like the other queries.
Try this, you had your while loop in the wrong place:
<?php
$u = $_SESSION['username'];
mysqli_select_db($connect,"button");
$select = "select * from button where sessionusername='$u' AND response = 'approve'";
$query = mysqli_query($connect,$select) or die('Oops, Could not connect');
while($result = mysqli_fetch_array($query))
{
$email = mysqli_real_escape_string($connect,trim($result['onuser']));
echo $email;
if($email){
mysqli_select_db($connect,"users");
$select_name = "select name, icon from profile where email = '$email'";
$query_2 = mysqli_query($connect,$select_name) or die('Oops, Could not connect. Sorry.');
$results= mysqli_fetch_array($query_2);
$name = mysqli_real_escape_string($connect,trim($results['name']));
$icon = mysqli_real_escape_string($connect,trim($results['icon']));
echo $name;
}
}

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