Loop for Arrays in php - php

Question

<?php
session_start();
$link = mysqli_connect("localhost", "xxx", "xxxxxx", "xxx");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$id = $_GET['id'];
if ($result = mysqli_query($link, "SELECT * FROM Subscribe WHERE STo = '".$id."' ORDER BY ID LIMIT 6")) {
while($row = mysqli_fetch_array($result))
{
$idS = $row['SWho'];
echo $idS;
if ($result = mysqli_query($link, "SELECT * FROM accounts WHERE ID = '".$idS."' ORDER BY ID LIMIT 6")) {
while($row = mysqli_fetch_array($result))
{
echo "<img src='Member_ProfilePics/";
echo $row['PP'] . '.' . $row['Ext'];
echo "' width=42 height=40 style='float: left'>";
}
}
}
//<img src='Member_ProfilePics/john.jpg' width=42 height=40 style='float: left'>
}
?>
here in my code, i want to output the list of STo. and connect to other database and output the following rows in each STo.
Sample to be output:
(picture of id=1) 1
(picture of id=2) 2
(picture of id=3) 3
(picture of id=4) 4
(picture of id=5) 5
(picture of id=6) 6
How?
my code is not looping.
Sample output of my code:
(picture of id=1) 1

Answer 1

You are using the same variables for both the loops:
if ($result = mysqli_query($link, "SELECT * FROM Subscribe WHERE STo = '".$id."' ORDER BY ID LIMIT 6")) {
while($row = mysqli_fetch_array($result)) {
....
if ($result = mysqli_query($link, "SELECT * FROM accounts WHERE ID = '".$idS."' ORDER BY ID LIMIT 6")) {
while($row = mysqli_fetch_array($result)) {
...
}
}
}
}
Try to change the seconda value to these
if ($result = mysqli_query($link, "SELECT * FROM Subscribe WHERE STo = '".$id."' ORDER BY ID LIMIT 6")) {
while($row = mysqli_fetch_array($result)) {
....
if ($result2 = mysqli_query($link, "SELECT * FROM accounts WHERE ID = '".$idS."' ORDER BY ID LIMIT 6")) {
while($row2 = mysqli_fetch_array($result2)) {
...
}
}
}
}