Cakephp query only displays last value of array - php

Question

I'm sure I'm doing something wrong here but I can't figure it out. I have tried several ways but no luck.
This is my controller:
$result = mysql_query("SELECT name FROM spa_packages") or die(mysql_error());
$names=array();
while ($row = mysql_fetch_row($result)) $names[]=$row[0];
mysql_free_result($result);
foreach ($names as $asd => $lol) {}
$this->set('anything', $lol);
This is where I display it:
if(!empty($anything)) {
echo " '<option value=" . $anything . '">' . $anything . '</option>';
}

Answer 1

Further to my comment and in more of an answer. You are doing something wrong. There is absolutely no reason to use mysql_ functions at all (they are deprecated) and you shouldn't be using any direct db access in an MVC framework like CakePHP
Your code should be more along the lines of
In your Controllers/SpaPackagesController.php index action:
$spaPacakges = $this->SpaPackage->find('all');
$this->set('spaPackages', $spaPackages):
In your Views/SpaPackages/index.ctp
<?php foreach ($spaPackages as $package): ?>
<!-- some html -->
<?php endforeach;?>
You really need to run through some CakePHP beginner tutorials as your question shows a big misunderstanding in how the framework works

Answer 2

Looks like you are trying to do this:
$result = mysql_query("SELECT name FROM spa_packages") or die(mysql_error());
$names = array();
while ($row = mysql_fetch_assoc($result)) {
$names[] = $row["name"]
}
$this->set('anything', $names);
mysql_free_result($result);
And:
if(!empty($anything)) {
foreach($anything as $name){
echo " '<option value=" . $name . '">' . $name . '</option>';
}
}