PHP how to get the base domain/url? - php

Question

function url(){
if(isset($_SERVER['HTTPS'])){
$protocol = ($_SERVER['HTTPS'] && $_SERVER['HTTPS'] != "off") ? "https" : "http";
}
else{
$protocol = 'http';
}
return $protocol . "://" . $_SERVER['HTTP_HOST'];
}
For example with the function above, it works fine if I work with the same directory, but if I make a sub directory, and work in it, it will give me the location of the sub directory also for example. I just want example.com but it gives me example.com/sub if I'm working in the folder sub. If I'm using the main directory,the function works fine. Is there an alternative to $_SERVER['HTTP_HOST']?
Or how could I fix my function/code to get the main url only? Thanks.

Answer 1

Use SERVER_NAME.
echo $_SERVER['SERVER_NAME']; //Outputs www.example.com

Answer 2

You could use PHP's parse_url() function
function url($url) {
$result = parse_url($url);
return $result['scheme']."://".$result['host'];
}

Answer 3

Shortest solution:
$domain = parse_url('http://google.com', PHP_URL_HOST);

Answer 4

/**
* Suppose, you are browsing in your localhost
* http://localhost/myproject/index.php?id=8
*/
function getBaseUrl()
{
// output: /myproject/index.php
$currentPath = $_SERVER['PHP_SELF'];
// output: Array ( [dirname] => /myproject [basename] => index.php [extension] => php [filename] => index )
$pathInfo = pathinfo($currentPath);
// output: localhost
$hostName = $_SERVER['HTTP_HOST'];
// output: http://
$protocol = strtolower(substr($_SERVER["SERVER_PROTOCOL"],0,5))=='https'?'https':'http';
// return: http://localhost/myproject/
return $protocol.'://'.$hostName.$pathInfo['dirname']."/";
}

Answer 5

Use parse_url() like this:
function url(){
if(isset($_SERVER['HTTPS'])){
$protocol = ($_SERVER['HTTPS'] && $_SERVER['HTTPS'] != "off") ? "https" : "http";
}
else{
$protocol = 'http';
}
return $protocol . "://" . parse_url($_SERVER['REQUEST_URI'], PHP_URL_HOST);
}
Here is another shorter option:
function url(){
$pu = parse_url($_SERVER['REQUEST_URI']);
return $pu["scheme"] . "://" . $pu["host"];
}

Answer 6

Step-1
First trim the trailing backslash (/) from the URL. For example, If the URL is http://www.google.com/ then the resultant URL will be http://www.google.com
$url= trim($url, '/');
Step-2
If scheme not included in the URL, then prepend it. So for example if the URL is www.google.com then the resultant URL will be http://www.google.com
if (!preg_match('#^http(s)?://#', $url)) {
$url = 'http://' . $url;
}
Step-3
Get the parts of the URL.
$urlParts = parse_url($url);
Step-4
Now remove www. from the URL
$domain = preg_replace('/^www\./', '', $urlParts['host']);
Your final domain without http and www is now stored in $domain variable.
Examples:
http://www.google.com => google.com
https://www.google.com => google.com
www.google.com => google.com
http://google.com => google.com

Answer 7

2 lines to solve it
$actual_link = (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] === 'on' ? "https" : "http") . "://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$myDomain = preg_replace('/^www\./', '', parse_url($actual_link, PHP_URL_HOST));

Answer 8

/* Get sub domain or main domain url
* $url is $_SERVER['SERVER_NAME']
* $index int remove subdomain if acceess from sub domain my current url is https://support.abcd.com ("support" = 7 (char))
* $subDomain string
* $issecure string https or http
* return url
* call like echo getUrl($_SERVER['SERVER_NAME'],7,"payment",true,false);
* out put https://payment.abcd.com
* second call echo getUrl($_SERVER['SERVER_NAME'],7,null,true,true);
*/
function getUrl($url,$index,$subDomain=null,$issecure=false,$www=true) {
//$url=$_SERVER['SERVER_NAME']
$protocol=($issecure==true) ? "https://" : "http://";
$url= substr($url,$index);
$www =($www==true) ? "www": "";
$url= empty($subDomain) ? $protocol.$url :
$protocol.$www.$subDomain.$url;
return $url;
}

Answer 9

Use this code is whork :
if (!preg_match('#^http(s)?://#', $url)) {
$url = 'http://' . $url;
}
$urlParts = parse_url($url);
$url = preg_replace('/^www\./', '', $urlParts['host']);

Answer 10

This works fine if you want the http protocol also since it could be http or https.
$domainURL = $_SERVER['REQUEST_SCHEME']."://".$_SERVER['SERVER_NAME'];

Answer 11

Please try this:
$uri = $_SERVER['REQUEST_URI']; // $uri == example.com/sub
$exploded_uri = explode('/', $uri); //$exploded_uri == array('example.com','sub')
$domain_name = $exploded_uri[1]; //$domain_name = 'example.com'
I hope this will help you.

Answer 12

Tenary Operator helps keep it short and simple.
echo (isset($_SERVER['HTTPS']) ? 'http' : 'https' ). "://" . $_SERVER['SERVER_NAME'] ;

Answer 13

If you're using wordpress, use get_site_url:
get_site_url()