Convert SQL results into PHP array - php

Question

I'm fairly new to PHP and I've been looking around and can't seem to find the specific answer I'm looking for.
I want to make a SQL query, such as this:
$result = mysqli_query($connection, $command)
if (!$result) { die("Query Failed."); }
// Create my array here ... I'm thinking of maybe having to
// make a class that can hold everything I need, but I dunno
while($row = mysqli_fetch_array($result))
{
// Put the row into an array or class here...
}
mysqli_close($connection);
// return my array or class
Basically I want to take the entire contents of the result and create an array that I can access in a similar fashion as the row. For example, if I have a field called 'uid' I want to be able to get that via myData['uid']. I guess since there could be several rows, maybe something more like myData[0]['uid'], myData[1]['uid'], etc.
Any help would be appreciated.

Answer 1

You can do:
$rows = [];
while($row = mysqli_fetch_array($result))
{
$rows[] = $row;
}

Answer 2

You might try to use mysqli_result::fetch_all() for arrays:
$result = mysqli_query($connection, $command)
if (!$result) { die("Query Failed."); }
$array = $result->fetch_all();
$result->free();
mysqli_close($connection);
NOTE: This works with MySQLND only.
For class, you might try to use something like this:
$result = mysqli_query($connection, $command)
if (!$result) { die("Query Failed."); }
while($model = $result->fetch_assoc()){
// Assuming ModelClass is declared
// And have method push() to append rows.
ModelClass::push($model);
}
$result->free();
mysqli_close($connection);
OR this:
// Base Model - abstract model class.
class ModelClass extends BaseModel {
// constructor
public function __construct(mysqli &$dbms){
// $this->dbms is MySQLi connection instance.
$this->dbms = &$dbms;
// $this->models is buffer for resultset.
$this->models = array();
}
// destructor
public function __destruct(){
unset($this->dbms, $this->models);
}
public function read(){
$result = $this->dbms->query($command);
if($this->dbms->errno){
throw new Exception($this->dbms->error, $this->dbms->errno);
}
$this->models = $result->fetch_all();
$result->free();
}
}

Answer 3

//object oriented style mysqli
//connect to your db
$mysqli = new mysqli("host", "user", "password", "dbname");
$result = $mysqli->query("SELECT * FROM `table`");
//use mysqli->affected_rows
for ($x = 1; $x <= $mysqli->affected_rows; $x++) {
$rows[] = $result->fetch_assoc();
}
//this will return a nested array
echo "<pre>";
print_r($rows);
echo "</pre>";
edit this and put it on a class and just call it anytime you're going to make a query with your database.

Answer 4

fetch_array: https://www.php.net/manual/en/mysqli-result.fetch-array.php
$result = $mysqli_connection->query($sql);
$row = $result->fetch_array(MYSQLI_ASSOC);
print_r($row);