Split an array in sub arrays of consecutive dates - php

Question

For a rent application, I have an array $dates like this:
Array
(
[2013-07-19] => 1
[2013-07-21] => 3
[2013-07-23] => 2
[2013-07-24] => 4
[2013-07-25] => 4
[2013-07-26] => 2
[2013-07-27] => 2
[2013-07-30] => 3
[2013-07-31] => 1
)
The date is the key, and the values are the number of items rent in that day for a specific product
How can I split this array in many sub arrays containing each a list of consecutive days?
Like this:
Array
(
[0] => Array
(
[2013-07-19] => 1
)
[1] => Array
(
[2013-07-21] => 3
)
[2] => Array
(
[2013-07-23] => 2
[2013-07-24] => 4
[2013-07-25] => 4
[2013-07-26] => 2
[2013-07-27] => 2
)
[3] => Array
(
[2013-07-30] => 3
[2013-07-31] => 1
)
)

Answer 1

$newArray = array();
foreach ($array as $date => $value)
{
// Make sure the newArray starts off with at least one element
if (empty($newArray))
$newArray[] = array();
// Calculate the difference in dates.
// (I like using DateTime, but use whichever method you like)
$dateTime = new DateTime($date);
$lastDateTime = new DateTime($lastDate);
$dateDiff = $dateTime->diff($lastDateTime);
// Add a new array to the end if the difference between this element and the last was more than a day
if ($dateDiff->days > 1)
$newArray[] = array();
// We can now be guaranteed that the last element of $newArray is the one we want to append to
$newArray[count($newArray) - 1][$date] = $value;
// Keep track of the last date you saw
$lastDate = $date;
}
Here it is in action: https://eval.in/38039

Answer 2

$newArray = array();
$i = 0;
foreach ($array as $date => $key) {
$thisDay = end(explode('-', $date));
$nextDay = end(explode('-', next($array[$date])));
if ($thisDay + 1 != $nextDay + 0)
$i++;
if (!isset($newArray[$i])) {
$newArray[$i] = array($date => $key);
} else {
if (!isset($newArray[$i][$date])) {
$newArray[$i][$date] = $key;
} else {
$newArray[$i][$date] = $key;
}//END IF
}//END IF
}//END FOREACH LOOP
This is the code i would use to do what you are asking.
UPDATE:
I was wrong above. i have altered the code to work this time:
$newArray = array();
$i = 0;
foreach ($array as $date => $key) {
$thisDay = end(explode('-', $date));
$nextDay = array_key_exists(date('Y-m-d', strtotime($date . ' +1 day')), $array);
if (!isset($newArray[$i])) {
$newArray[$i] = array($date => $key);
} else {
if (!isset($newArray[$i][$date])) {
$newArray[$i][$date] = $key;
} else {
$newArray[$i][$date] = $key;
}//END IF
}//END IF
if (!$nextDay)
$i++;
}//END FOREACH LOOP
Here is my test case:
<?php
$array = array(
'2013-07-19' => 1,
'2013-07-21' => 3,
'2013-07-23' => 2,
'2013-07-24' => 4,
'2013-07-25' => 4,
'2013-07-26' => 2,
'2013-07-27' => 2,
'2013-07-30' => 3,
'2013-07-31' => 1
);
echo '<pre>' . print_r($array, true) . '</pre>';
$newArray = array();
$i = 0;
foreach ($array as $date => $key) {
$thisDay = end(explode('-', $date));
$nextDay = array_key_exists(date('Y-m-d', strtotime($date . ' +1 day')), $array);
if (!isset($newArray[$i])) {
$newArray[$i] = array($date => $key);
} else {
if (!isset($newArray[$i][$date])) {
$newArray[$i][$date] = $key;
} else {
$newArray[$i][$date] = $key;
}//END IF
}//END IF
if (!$nextDay)
$i++;
}//END FOREACH LOOP
echo '<pre>' . print_r($newArray, true) . '</pre>';
?>

Answer 3

you can do it like this:
$data = array(
'2013-07-19' => 1,
'2013-07-21' => 3,
'2013-07-23' => 2,
'2013-07-24' => 4,
'2013-07-25' => 4,
'2013-07-26' => 2,
'2013-07-27' => 2,
'2013-07-30' => 3,
'2013-07-31' => 1
);
$result = array();
$ref = new DateTime('1821-11-11');
foreach ($data as $datum => $nb) {
if ($ref->add(new DateInterval('P1D'))->format('Y-m-d')!=$datum) {
$result[] = array();
$ref = new DateTime($datum);
}
$result[array_pop(array_keys($result))][$datum] = $nb;
}
print_r($result);