PHP Android No value for - php

Question

I have one problem, when i´m going to run the app i receive one System.err: no value for anotacoes!
I think my problem is on php code. If someone help me i'll appreciate a lot your help.
(Sorry for my bad english ;) )
<?php
// array for JSON response
$response = array();
$response1 = array();
mysql_connect("localhost","root",""); // host, username, password...
mysql_select_db("mobimapa"); // db name...
// check for post data
$pid = $_GET['pid'];
// get a product from products table
$result = mysql_query("SELECT id_anotacao FROM processo_anotacoes WHERE id_processo = $pid");
// check for empty result
if (mysql_num_rows($result) > 0) {
//$response["processo_anotacoes"] = array();
$processo_anotacoes = array();
while ($row = mysql_fetch_array($result)){
array_push($processo_anotacoes, $row["id_anotacao"]);
// $processo_anotacoes["id_anotacao"] = $row["id_anotacao"];
// $processo_anotacoes["id_processo"] = $row["id_processo"];
// success
//$response["success"] = 1;
// user node
// $response["processo_anotacoes"] = array();
}
// echo json_encode($processo_anotacoes);
}
$ids = join(', ',$processo_anotacoes);
$result1 = mysql_query("SELECT * FROM anotacoes WHERE id_anotacao IN ($ids)");
if (mysql_num_rows($result1) > 0) {
$response1["anotacoes"] = array();
// check for empty result
while ($row1 = mysql_fetch_array($result1)) {
//$result1 = mysql_fetch_array($result1);
$anotacoes = array();
$anotacoes["id_anotacao"] = $row1["id_anotacao"];
$anotacoes["nome"] = $row1["nome"];
$anotacoes["descricao"] = $row1["descricao"];
// success
$response1["success"] = 1;
// user node
$response1["anotacoes"] = array();
array_push($response1["anotacoes"], $anotacoes);
}
// echoing JSON response
echo json_encode($response1);
}
?>
08-12 17:09:03.308: D/All Products:(806):
{"success":1,"processo":[{"data":"2013-07-17","id_processo":"1","nome":"Processo
1","imagem":"Later"},{"data":"2013-08-04","id_processo":"2","nome":"Processo
2","imagem":"Later"}]} 08-12 17:09:03.518: I/Choreographer(806):
Skipped 110 frames! The application may be doing too much work on its
main thread. 08-12 17:09:29.238: D/Processo clicado(806): 2 08-12
17:09:29.838: D/Single Product Details(806):
{"product":[{"data":"2013-08-04","id_processo":"2","nome":"Processo
2","imagem":"Later"}],"success":1} 08-12 17:09:30.028: D/Anotacoes
Details(806):
{"success":1,"anotacoes":[{"descricao":"teste","id_anotacao":"3","nome":"Anotacao
3"}]}

Answer 1

The problem is with the PHP variable being passed to the 2nd SQL query. This not the complete code; but if you understand it, it will solve your problem:
$anotacaos = array();
while ($row = mysql_fetch_array($result))
array_push($anotacaos, $row["id_anotacao"]);
$ids = join(',',$anotacaos);
$result1 = mysql_query("SELECT * FROM anotacoes WHERE id_anotacao in ($ids)");
while ($row = mysql_fetch_array($result1))
//do something...