prepared statement method.. confused - php

Question

I don't know what's missing or why it isn't displaying data. My code is working if I'm not using prepared statements. When I used prepared statements, it seems that code is not working anymore.
db.php
Class Database{
public $mysqli;
public function __construct($db_host, $db_user, $db_password, $db_name){
$this->con = new mysqli($db_host, $db_user, $db_password, $db_name);
}
public function selectUserInfo($id){
$stmt = $this->con->prepare("SELECT * FROM users WHERE os_id = ?");
$stmt->bind_param("s", $id);
if($stmt->execute() == FALSE){
trigger_error($stmt->error, E_USER_ERROR);
}else{
$data = array();
while($row = $stmt->fetch()){
$data[] = $row;
}
return $data;
}
}
}
config.php
define("DBHOST","somehost");
define("DBUSER","someroot");
define("DBPASS","somepassword");
define("DB","my_database");
this is how I would displayed it at my page.
require 'global/db.php';
require_once 'config.php';
$db = new Database(DBHOST, DBUSER, DBPASS, DB);
$data = $db->selectUserInfo($_GET['name']);
foreach ($data as $key) {
# code...
echo $key['os_fname'];
}

Answer 1

As we have defined, that the issue was with your foreach.
What is wrong is with how you're reading it, fetch does not have associative properties so need to use the bind_result.
Here is a hack that is also suggested at the fetch manual:
public function selectUserInfo($id)
{
$stmt = $this->con->prepare("SELECT * FROM users WHERE os_id=?");
$stmt->bind_param('i', $id);
if(!$stmt->execute())
{
trigger_error($stmt->error, E_USER_ERROR);
}
else
{
$bindVarArray = array();
$data = array();
$result;
$meta = $stmt->result_metadata();
while ($column = $meta->fetch_field())
{
$columnName = str_replace(' ', '_', $column->name);
$bindVarArray[] = &$result[$columnName];
}
call_user_func_array(array($stmt, 'bind_result'), $bindVarArray);
$index = 0;
while ($stmt->fetch() != null)
{
foreach ($result as $k => $v)
{
$data[$index][$k] = $v;
}
$index++;
}
return $data;
}
}
Then you can use your foreach to read it like this:
foreach ($data as $result)
{
echo $result['os_fname'], ' => ', $result['os_lname'], "\n";
}
And you can always use print_r to see how your resulting array is:
print_r($data);

Answer 2

your od_id type in DB is string or integer? if a integer
public function selectUserInfo($id){
$stmt = $this->con->prepare("SELECT * FROM users WHERE os_id = ?");
$stmt->bind_param("i", $id);//use 'i' instead of 's'
if($stmt->execute() == FALSE){
trigger_error($stmt->error, E_USER_ERROR);
}else{
$data = array();
while($row = $stmt->fetch()){
$data[] = $row;
}
return $data;
}
}