Contents of array incorrect - php

Question

I currently have this SQL statement:
SELECT p.*,k.name FROM posts AS p
LEFT JOIN `post-keywords` AS pk ON p.id = pk.id_post
LEFT JOIN keywords AS k ON pk.id_keyword = p.id
ORDER BY p.id DESC LIMIT :num,:count
however, it doesn't work as expected. This is what the server returns:
array(7) {
[0]=>
array(5) {
["id"]=>
string(1) "2"
["title"]=>
string(28) "Everything about Internet"
["text"]=>
string(41) "Article itself"
["date"]=>
string(1) "0"
["name"]=>
NULL
}
[1]=>
array(5) {
["id"]=>
string(1) "1"
["title"]=>
string(16) "Internet"
["text"]=>
string(32) "Text text text"
["date"]=>
string(10) "1371186330"
["name"]=>
string(7) "tag1"
}
[2]=>
array(5) {
["id"]=>
string(1) "1"
["title"]=>
string(16) "Internet"
["text"]=>
string(32) "Text text text"
["date"]=>
string(10) "1371186330"
["name"]=>
string(7) "tag2"
}
[3]=>
array(5) {
["id"]=>
string(1) "1"
["title"]=>
string(16) "Internet"
["text"]=>
string(32) "Text text text"
["date"]=>
string(10) "1371186330"
["name"]=>
string(7) "tag3"
}
[4]=>
array(5) {
["id"]=>
string(1) "1"
["title"]=>
string(16) "Internet"
["text"]=>
string(32) "Text text text"
["date"]=>
string(10) "1371186330"
["name"]=>
string(7) "tag4"
}
[5]=>
array(5) {
["id"]=>
string(1) "1"
["title"]=>
string(16) "Internet"
["text"]=>
string(32) "Text text text"
["date"]=>
string(10) "1371186330"
["name"]=>
NULL
}
[6]=>
array(5) {
["id"]=>
string(1) "1"
["title"]=>
string(16) "Internet"
["text"]=>
string(32) "Text text text"
["date"]=>
string(10) "1371186330"
["name"]=>
NULL
}
}
How to retrieve an array from the server that contains multiple name fields:
array (5) {
["id"] =>
   string (1) "1"
   ["title"] =>
   string (16) "Internet"
   ["text"] =>
   string (32) "text text text"
   ["date"] =>
   string (10) "1371186330"
   ["name"] =>
   string (10) "word1"
   ["name"] =>
   string (10) "word2"
   ["name"] =>
   string (10) "word3"
}

Answer 1

Currently your query is 'overwriting' fields that have multiple entries with the same name. For example, you are getting p.name and k.name. You query doesn't make a difference, so it gets overwritten to (I presume) k.name.
To make sure you get them both, write something like: SELECT p.name AS p_name, k.name AS k_name