Good Day!
Guys can you help me to check why my is it that i cannot insert records using chekbox option on table..
Please Help..
Here's My Code...
--ADDING Subject Load for Teacher HTML Form-- (studsub.php)
<form action="setsubject.php" method="post">
<?php
include('../connect.php');
$id=$_GET['id'];
$result = mysql_query("SELECT * FROM student WHERE id='$id'");
while($row = mysql_fetch_array($result))
{
//$course=$row['course'];
//$year=$row['yearlevel'];
//$section=$row['section'];
$idnumber=$row['idnumber'];
echo '<br/>';
echo $row['lname'].", ".$row['fname'];
?>
<input type="hidden" name="studidnum" value="<?php echo $rows['idnumber']?>">
<?php }
?>
<br/><br/>
<label for="filter">Filter</label> <input type="text" name="filter" value="" id="filter" />
<table cellpadding="1" cellspacing="1" id="resultTable">
<thead>
<tr>
<th style="border-left: 1px solid #C1DAD7"><label>Assign</label></th>
<th style="border-left: 1px solid #C1DAD7"> Subject ID </th>
<th>Title</th>
<th>Units</th>
</tr>
</thead>
<tbody>
<?php
include('../connect.php');
$result = mysql_query("SELECT * FROM tbl_cur_sub where status='1' ");
while($row = mysql_fetch_array($result))
{
echo '<tr class="record">';
echo ' <td>' . '<input type="checkbox" name="subject[]" value="'.$rows['code'].'" />' . '</td> ' ;
echo '<td style="border-left: 1px solid #C1DAD7">'.$row['code'].'</td>';
echo '<td><div align="left">'.$row['subject'].'</div></td>';
echo '<td><div align="left">'.$row['units'].'</div></td>';
echo '</tr>';
}
?>
</tbody>
</table>
<br/>
Course<br>
<select name="course" class="ed">
<?php
include('../connect.php');
$results = mysql_query("SELECT * FROM course");
while($rows = mysql_fetch_array($results))
{
echo '<option>'.$rows['coursecode'].'</option>';
}
?>
</select>
<select name="yearlevel" class="ed">
<?php
include('../connect.php');
$results = mysql_query("SELECT * FROM tbl_yrlevel");
while($rows = mysql_fetch_array($results))
{
echo '<option>'.$rows['yearlevel'].'</option>';
}
?>
</select>
<select name="section" class="ed">
<option>A</option>
<option>B</option>
<option>C</option>
<option>D</option>
</select>
<br>
<br>
<input type="submit" value="Assign" id="button1">
</form>
--The Submission Page -- (setsubject.php)
<?php
include('../connect.php');
//Function to sanitize values received from the form. Prevents SQL injection
function clean($str)
{
$str = #trim($str);
if(get_magic_quotes_gpc())
{
$str = stripslashes($str);
}
return mysql_real_escape_string($str);
}
//Sanitize the POST values
$course = clean($_POST['course']);
$section = clean($_POST['section']);
$yearlevel = clean($_POST['yearlevel']);
$studidnum=$_POST['studidnum'];
$subject=$_POST['subject'];
$N = count($subject);
for($i=0; $i < $N; $i++)
{
mysql_query("INSERT INTO studentsubject (student, subject, section, course, level) VALUES ('$studidnum', '$subject[$i]','$section','$course', '$level')");
}
header("location: student.php");
mysql_close($con);
?>
--My Database--
TABLE: studentsubject
FIELDS: student, subject, section, course, level
Thanks IN advance for the Help..
TRY
mysql_query("SELECT * FROM tbl_cur_sub where status=1 ");
change the mysql statement...you need to differ the variable and string in the query
$result = mysql_query("SELECT * FROM student WHERE id='".$id."'");
Related
**Hello..i know my type of question has been answered in different questions before;but i tried them all..none worked!So please have a look on my issue.
I've a table that contains form input fields where values come from database.I didn't wanted the values to be edited.So used "readonly". But the problem is:By the inspect element of a browser when readonly is removed..then the value can be edited and blank input can be submitted !!! So i want to disable the editing or at least want to disable the submit button if input field is empty.**
The code of the table:
<?php
if (isset($_POST['show'])) {
$class = $_POST["Class"];
$sql = "SELECT * FROM students WHERE Class='$class' ORDER BY Roll ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
?>
<form action="" method="POST">
<table class="table table-bordered table-hover" style="width: 85%;text-align: center">
<tr >
<th>Roll</th>
<th>Student's Name</th>
<th>Attendance</th>
</tr>
<?php while ($row = $result->fetch_assoc()) { ?>
<tr>
<td><input value="<?php echo $row['Roll']; ?>" name="Roll[]" readonly required=""/></td>
<td><input value="<?php echo $row['Name']; ?>" name="Name[]" readonly required=""/></td>
<td><select name="Status[]">
<option value="0">0</option>
<option value="1">1</option>
</select></td>
</tr>
<?php } ?>
</table>
<input type="submit" name="save" value="Save" style="width: 50%;margin-left: 20%">
</form>
<?php
} else {
$message = "Sorry! No result!";
echo "<script type='text/javascript'>alert('$message');</script>";
}
$conn->close();
}
?>
The insertion code:
<?PHP
if (isset($_POST["save"])) {
foreach ($_POST["Roll"] as $rec => $value) {
$Roll = $_POST["Roll"][$rec];
$Name = $_POST["Name"][$rec];
$Status = $_POST["Status"][$rec];
$Date = date('Y-m-d');
$sql = "INSERT INTO `attendance`(`id`, `Date`, `Roll`, `Name`, `Status`) VALUES ('','$Date','$Roll','$Name','$Status')";
}
if ($conn->query($sql) === TRUE) {
$message = "Saved !";
echo "<script type='text/javascript'>alert('$message');</script>";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
}
?>
this is correct way to not input empty field
$class = $_POST["Class"];
if(!empty($class)) {
$sql = "SELECT * FROM students WHERE Class='$class' ORDER BY DESC or ASC";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
}
}
?>
I edited part of your code to disallow editing. I hope it serves your pourpose. i used disabled attribute on the input tags.
<tr>
<td><input value="<?php echo $row['Roll']; ?>" name="Roll[]" disabled/></td>
<td><input value="<?php echo $row['Name']; ?>" name="Name[]" disabled/></td>
<td><select name="Status[]">
<option value="0">0</option>
<option value="1">1</option>
</select></td>
</tr>
code:
<script>
$(document).ready(function(){
$(".menu").click(function(){
ids = $('.menu:checked').map(function() {
return this.id;
}).get().join(',');
console.log(ids);
$("#ids").val(ids);
});
});
</script>
<?php
if(isset($_POST['submit']))
{
$adminid = $_POST['admin'];
$menuids = explode(",", $_POST['ids']);
foreach ($menuids as $idd)
{
$sql = "update menu set admin_id = concat(admin_id,'$adminid',',') where id = '$idd'";
$result = mysqli_query($link,$sql);
}
if($result == true)
{
$msg .= "<p style='color:green'>successfull</p>";
}
else
{
$msg .= "<p style='color:red'>error!</p>";
}
}
?>
<form method="post">
<select name="admin" id="admin">
<option value="">---Select Admin---</option>
<?php
$sql = "select * from admin";
$result = mysqli_query($link,$sql);
while ($row = mysqli_fetch_array($result))
{
?>
<option value="<?php echo $row['id']; ?>"><?php echo $row['firstname']?></option>
<?php
}
?>
</select>
<table>
<tr>
<th>Share</th>
<th>Menu Name</th>
</tr>
<?php
$query = "select * from menu";
$results = mysqli_query($link,$query);
while ($fetch = mysqli_fetch_array($results))
{
?>
<tr>
<td>
<input type="checkbox" class="menu" id="<?php echo $fetch['id']; ?>" name="menuid" />
</td>
<td>
<?php echo $fetch['menu_name']; ?>
</td>
</tr>
<?php
}
?>
</table>
<input type="text" name="ids" id="ids" value=""/>
<input type="submit" name="submit" id="submit" />
</form>
In this code I am update a table having name menu in database. Now, I want to check only those checkbox where admin_id like ,1, or ,2, which is update by query. How can I fix this issue ?please please help.
Thank You
while ($fetch = mysqli_fetch_array($results))
{
?>
<tr>
<td>
<input type="checkbox" class="menu" value="<?php if($fetch['id']==1 or
$fetch['id']==2 ) { echo "checked";} else{} ?>" name="menuid" />
</td>
<td>
<?php echo $fetch['menu_name']; ?>
</td>
</tr>
<?php
}
?>
This question already has answers here:
Create PHP array from MySQL column
(12 answers)
Closed 22 days ago.
I tried to create a simple select dropdown menu from MySQL database. However, it does not work on my code.
Here is my code:
<?php
mysql_select_db($database_conn, $conn);
$query_RsCourse = "SELECT * FROM tbl_course ORDER BY courseid DESC";
$RsCourse = mysql_query($query_RsCourse, $conn) or die(mysql_error());
$totalRows_RsCourse = mysql_num_rows($RsCourse);
$count=0;
while ( $row = mysql_fetch_array($RsCourse, MYSQL_ASSOC)) {
$courseid=$row["courseid"];
$count++;
}
?>
<tr>
<td bgcolor="#CCCCCC"> Course Name</td>
<td bgcolor="#dfdfdf"> <select name="courseid">
<option value="" SELECTED>Selected Course</option>
<option value="<?php echo $courseid; ?>"><?php echo $row_RsCourse['$courseid']; ?></option>
</select>
</td>
</tr>
Any advice will be appreciated!
<?php
echo '<tr>
<td bgcolor="#CCCCCC"> Course Name</td>
<td bgcolor="#dfdfdf"> ';
mysql_select_db($database_conn, $conn);
$query_RsCourse = "SELECT * FROM tbl_course ORDER BY courseid DESC";
$RsCourse = mysql_query($query_RsCourse, $conn) or die(mysql_error());
$totalRows_RsCourse = mysql_num_rows($RsCourse);
if($totalRows_RsCourse)
{
echo '<select name="courseid"><option value="" SELECTED>Selected Course</option>';
$count=0;
while ($row = mysql_fetch_array($RsCourse, MYSQL_ASSOC))
{
$count++;
echo '<option value="'.$row['courseid'].'">'.$row['courseid'].'</option>';
}
echo '</select>';
}
else
{
echo 'No courses to show yet.'; // no rows in tbl_course
}
echo '</td>
</tr>';
?>
That was a mess, but hope you can go on from these new codes. Enjoy.
PS: this part >'.$row['courseid'].'</option> u can change to new one according to your table structure which one is not shown here.
<?php
echo '<tr>
<td bgcolor="#CCCCCC"> Course Name</td>
<td bgcolor="#dfdfdf"> ';
mysql_select_db($database_conn, $conn);
$query_RsCourse = "SELECT * FROM tbl_course ORDER BY courseid DESC";
$RsCourse = mysql_query($query_RsCourse, $conn) or die(mysql_error());
$totalRows_RsCourse = mysql_num_rows($RsCourse);
echo '<select name="courseid"><option value="" SELECTED>Selected Course</option>';
$count=0;
while ($row = mysql_fetch_array($RsCourse, MYSQL_ASSOC))
{
$count++;
echo '<option value="'.$row['courseid'].'">'.$row['courseid'].'</option>';
}
echo '</select></td>
</tr>';
?>
You can store everything in a buffer and print at once in the select below:
<?php
mysql_select_db($database_conn, $conn);
$query_RsCourse = "SELECT * FROM tbl_course ORDER BY courseid DESC";
$RsCourse = mysql_query($query_RsCourse, $conn) or die(mysql_error());
$coursesHtml = "";
while ( $row = mysql_fetch_array($RsCourse, MYSQL_ASSOC)) {
$coursesHtml .= "<option value='{$row["courseid"]}'>{$row["coursename"]}</option>";
}
?>
<tr>
<td bgcolor="#CCCCCC">Course Name</td>
<td bgcolor="#dfdfdf">
<select name="courseid">
<option value="" SELECTED>Selected Course</option>
<?= $coursesHtml ?>
</select>
</td>
</tr>
PS: Avoid use , style your html well with css using padding-left: 5px; or other features;
PS2: You should not show your page/form with tables structure, use divs with flexbox.
My table has 4 columns. "isbn, author, title, price".
I want to search one of them combining all 4 fields.
Like: if author "kayle" write 4 books with same price ($50) but with different title, for that in search page, if i select author:kayle and hit search, then it shows all books with all different or may be same prices and titles. Now i want to select author:kayle and price:$50 at the same time, and hit enter. For that it will show only $50 prices books wrote by kayle and it will appear in the table with 4 rows.
I try to combine it but stuck with the second step searching query. Here is my code if any one understand what i want to do, please share it. Here is my code:
<form method="post" action="search_form.php">
<input type="hidden" name="submitted" value="true"/>
<table border="1">
<tr>
<td style="padding:3px 10px; font-weight:bold;">ISBN</td>
<td style="padding:3px;">
<input type="hidden" name="category_isbn" id="category_isbn" value="isbn"/>
: <select name='criteria_isbn' id="criteria_isbn" onchange="ajaxFunction()">
<option selected="selected">- Select -</option>
<?php
$order = "SELECT isbn FROM books" or die (mysql_error());
$result = mysql_query($order);
while($data = mysql_fetch_array($result))
{
echo ("<option> $data[isbn] </option>");
}
?>
</select>
</td>
<td style="padding:3px 10px; font-weight:bold;">Author</td>
<td style="padding:3px;">
<input type="hidden" name="category_author" id="category_author" value="author"/>
: <select name='criteria_author' id="criteria_author" onchange="ajaxFunction()">
<option selected="selected">- Select -</option>
<?php
$order = "SELECT author FROM books" or die (mysql_error());
$result = mysql_query($order);
while($data = mysql_fetch_array($result))
{
echo ("<option> $data[author] </option>");
}
?>
</select>
</td>
<td style="padding:3px 10px; font-weight:bold;">Title</td>
<td style="padding:3px;">
<input type="hidden" name="category_title" id="category_title" value="title"/>
: <select name='criteria_title' id="criteria_title" onchange="ajaxFunction()">
<option selected="selected">- Select -</option>
<?php
$order = "SELECT title FROM books" or die (mysql_error());
$result = mysql_query($order);
while($data = mysql_fetch_array($result))
{
echo ("<option> $data[title] </option>");
}
?>
</select>
</td>
<td><input type="submit" /></td>
</tr>
</table>
</form>
<?php
if(isset($_POST['submitted']))
{
$category_isbn = $_POST['category_isbn'];
$criteria_isbn = $_POST['criteria_isbn'];
$query = "SELECT * FROM books WHERE $category_isbn LIKE '%".$criteria_isbn."%'";
$result = mysql_query($query) or die(mysql_error());
$num_rows = mysql_num_rows($result);
if(isset($_POST['criteria_isbn']))
{
$category_author = $_POST['category_author'];
$criteria_author = $_POST['criteria_author'];
$query = "SELECT * FROM books WHERE $category_author LIKE '%".$criteria_author."%'";
$result = mysql_query($query) or die(mysql_error());
$num_rows = mysql_num_rows($result);
if(isset($_POST['criteria_author']))
{
$category_title = $_POST['category_title'];
$criteria_title = $_POST['criteria_title'];
$query = "SELECT * FROM books WHERE $category_title LIKE '%".$criteria_title."%'";
$result = mysql_query($query) or die(mysql_error());
$num_rows = mysql_num_rows($result);
echo "$num_rows results found";
echo "<table border= 1>";
echo "<tr> <th>ISBN</th> <th>AUTHOR</th> <th>TITLE</th> <th>PRICE</th> </tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr><td>";
echo $row['isbn'];
echo "</td><td>";
echo $row['author'];
echo "</td><td>";
echo $row['title'];
echo "</td><td>";
echo $row['price'];
echo "</td></tr>";
}
echo "</table>";
}
}
}
?>
Thanks in advance.
try this
for first search
select* from table where author="kayle";
for second search
select * from table where author="kayle" and price="50";
I'm having a strange problem. I have a HTML page with PHP code which inserts data to a MySQL database. The data gets saved to the DB without any errors but in an incorrect order.
Here's a screenshot. The table on the right side displays the existing records. The first 2 records are shown correctly.
But when I save more records, it displays like this.
Even in the MySQL table, the records are inserted that way.
I'm not sure where exactly the problem is so I've shown the whole code for the page below. I've commented what each code block does. Please comment if you need me to clarify something.
The Location ID is an auto-generated code.
<html>
<head>
<script language="javascript">
function SelectAll(source)
{ //The code for the 'Select All' checkbox
checkboxes = document.getElementsByTagName("input");
for(var i in checkboxes)
{
if(checkboxes[i].type == 'checkbox')
{
checkboxes[i].checked = source.checked;
}
}
}
</script>
</head>
<body>
<?php
//Database connection initialization
require_once("db_handler.php");
$conn = iniCon();
$db = selectDB($conn);
/* Generating the new Location ID */
$query = "SELECT LID FROM locations ORDER BY LID DESC LIMIT 1";
$result = mysql_query($query, $conn);
$row = mysql_fetch_array($result);
$last_id = $row['LID'];
$id_letter = substr($last_id, 0, 1);
$id_num = substr($last_id, 1) + 1;
$id_num = str_pad($id_num, 3, "0", STR_PAD_LEFT);
//$id_num = sprintf("%03d", $id_num);
$new_id = $id_letter . $id_num;
/* Displaying the exsisting locations */
$query = "SELECT * FROM locations";
$result = mysql_query($query, $conn);
$count = mysql_num_rows($result);
?>
<! The table which displays the existing records >
<div id="display">
<b>Locations</b><br/><br/>
<form name="displayLocs" action="<?php echo $PHP_SELF; ?>" method="post" >
<table border="1">
<tr>
<th>Location ID</th>
<th>Code</th>
<th>Location</th>
<th><i>Delete</i></th>
</tr>
<?php
while($row = mysql_fetch_array($result))
{
?>
<tr>
<td align="center"><? echo $row["LID"]; ?></td>
<td align="center"><? echo $row["Code"]; ?></td>
<td><? echo $row["Location"]; ?></td>
<td align="center"><input type="checkbox" name="checkbox[]" value="<? echo $row["LID"]; ?>" /></td>
</tr>
<?php
}
?>
</table>
<br/>
<div id="buttons2">
<input type="checkbox" onclick="SelectAll(this)" />Select All <input type="reset" value="Clear" /> <input type="submit" value="Delete" name="deletebtn" />
</div>
</form>
</div>
<! New record saving area >
<b id="loc_caption_1">Enter a new location</b>
<div id="loca">
<form name="locForm" action="<?php echo $PHP_SELF; ?>" method="post" >
<table width="300" border="0">
<tr>
<td>Location ID</td>
<td><input type="text" name="lid" readonly="readonly" value="<?php echo $new_id; ?>" style="text-align:right" /></td>
</tr>
<tr>
<td>Code</td>
<td><input type="text" name="code" style="text-align:right" /></td>
</tr>
<tr>
<td>Location</td>
<td><input type="text" name="loc" style="text-align:right" /></td>
</tr>
</table>
</div>
<br/>
<div id="buttons">
<input type="reset" value="Clear" /> <input type="submit" value="Save" name="savebtn" />
</div>
</form>
<?php
//Saving record
if(isset($_POST["savebtn"]))
{
$id = $_POST["lid"];
$code = $_POST["code"];
$location = $_POST["loc"];
$query = "INSERT INTO locations(LID, Code, Location) VALUES('$id', '$code', '$location')";
$result = mysql_query($query, $conn);
if (!$result)
{
die("Error " . mysql_error());
}
else
{
echo "<br/><br/>";
echo "<strong>1 record added successfully!</strong>";
echo "<meta http-equiv=\"refresh\" content=\"3;URL=locations.php\">";
}
mysql_close($conn);
}
//Deleting selected records
if(isset($_POST["deletebtn"]))
{
for($i = 0; $i < $count; $i++)
{
$del_id = $_POST["checkbox"][$i];
$query = "DELETE FROM locations WHERE LID = '$del_id' ";
$result = mysql_query($query, $conn);
}
if (!$result)
{
die("Error " . mysql_error());
}
else
{
echo "<meta http-equiv=\"refresh\" content=\"0;URL=locations.php\">";
}
mysql_close($conn);
}
?>
</body>
</html>
Can anyone please tell me what is causing this and how to rectify it.
Thank you.
The records in the database are stored in the database in no particular order (well, there's some order to it, but it's up to the engine to determine it). If you want to get the results in a particular order, then you need to explicitly specify it when querying the data. In your case, make this change:
/* Displaying the exsisting locations */
$query = "SELECT * FROM locations ORDER BY lid";
$result = mysql_query($query, $conn);