mysql table creation with PDO fails - php

Question

I'm rewriting my php code for mysql database access (now using a class definitions). While I had the old code (using old style functions) working I struggle to get the code for creating tables right - I think the problem relates in particular to the right definition of the sql statement, pls see code below. The new aspect (for me) compared to the old code is that the sql table creation command now must include the name of a database different than the master_database for which the PDO connection is set up (within the class constructor).
I looked at http://dev.mysql.com/doc/refman/5.6/en/create-table.html (I use mysql v5.6) - the part starting with "The table name can be specified as db_name.tbl_name to ..." but I cant get the sql syntax right. If I'm right the sql syntax is wrong what should be the right syntax in the code below for $sql (using the construction with various variables)?
Thnx for your help in advance.
Simplified code:
<?php
define('DB_HOST', '***');
define('DB_NAME', 'MASTER_DATABASE'); //different name
define('DB_USER', 'root');
define('DB_PASS', '*****');
//class definitions
class Database {
private $_db = null; //databasehandler
public function __construct() {
try {
$this->_db = new PDO('mysql:host='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS, array(
PDO::MYSQL_ATTR_USE_BUFFERED_QUERY => true
));
$this->_db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$this->_db->query('SET CHARACTER SET utf8');
} catch (PDOException $e) {
exit('Error while connecting to database.'.$e->getMessage());
}
}
private function printErrorMessage($message) {
echo $message;
}
public function createDBTable($dbname,$dbtable,$tablestructure) {
try {
$sql = "CREATE TABLE `".$dbname."'.'".$dbtable.$tablestructure; //NOT CORRECT YET
$success = $this->_db->exec($sql);
return ($success > 0) ? true:false;
}
catch(PDOException $e){
$this->printErrorMessage($e->getMessage());
}
}
}//class
//code using class defs
$dbname = 'Mydatabase'; //just an existing database
$dbtable = 'Persons';
$tablestructure = '(FirstName CHAR(30),LastName CHAR(30),Age INT)';
$mydb = new Database();
if($mydb->createDBTable($dbname,$dbtable,$tablestructure)){
echo 'table creation success';
}
else{
echo 'table creation failure';
}
?>

Answer 1

You can replace you create table line as:-
$sql = "CREATE TABLE ".$dbname.".".$dbtable."".$tablestructure; //NOT CORRECT YET
Also instead of:-
$success = $this->_db->exec($sql);
Use the below lines:-
$stmt = $this->_db->prepare($sql);
$success = $stmt->execute();
Without the above 2 lines, the $succes variable will have value of 0 and although the table can be created, it would echo table creation failed.
Hope this helps.