MySQLi - search through an array - php

Question

I have the following code:
function resultToArray($result) {
$rows = array();
while($row = $result->fetch_assoc()) {
$rows[] = $row;
}
return $rows;
}
// Usage
$query = 'SELECT q17, COUNT(q17) FROM tresults GROUP BY q17';
$result = $mysqli->query($query);
$rows = resultToArray($result);
//print_r($rows); // Array of rows
$result->free();
Brings back the following (only an excerpt):
Array ( [0] => Array ( [q17] => [COUNT(q17)] => 7 ) [1] => Array ( [q17] => Admin & Clerical [COUNT(q17)] => 118 )......etc.
What I am struggling with is how to then return the data, basically, what I need is some code to pull out the data as follows:
WHERE Array = Admin & Clerical BRING BACK THE COUNT(q17) number
How do I search through the array, normally, I'd use something like:
if($rows['q17']==$q[$i]){echo$rows['COUNT(q17)'];}
But this doesn't work - I assume because there are two sets of data within each part of the array? Not sure how to deal with this.

Answer 1

You can achieve this by using MYSQL itself, by using HAVING clause instead of WHERE.
To do this rewrite your query like this.
$query = 'SELECT q17, COUNT(q17) as qcount FROM tresults GROUP BY q17 HAVING q17="Admin & Clerical" ';
echo $row[0]['qcount']; //return 118
if you still want to it with PHP after getting the result from the database, it's how it done:
function get_q17_count($rows, $q17){
foreach ($rows as $onerow) {
if($onerow['q17'] == $q17){
return $onerow['COUNT(q17)'];
}
}
}

Answer 2

function resultToArray($results) {
$rows = array();
while($row = $results->fetch_assoc()) {
$rows[] = $row;
}
return $rows;
}
// Usage
$querys = 'SELECT q17, COUNT(q17) FROM tresults GROUP BY q17';
$results = $mysqli->query($querys);
$rows = resultToArray($results);
//print_r($rows); // Array of rows
$results->free();
function searchForId($id, $array) {
foreach ($array as $key => $val) {
if ($val['q17'] === $id) {
return $val['COUNT(q17)'];
}
}
return null;
}
Called the function using:
$id = searchForId($q[$i], $rows);echo " (".$id.")";