Here's the code:
<?php
if(isset($_POST['results']) && $_POST['results'] != -1) {
$db = new PDO('mysql:host=localhost;dbname=;charset=utf8', '', '');
echo "<table border='1'>
<tr>
<th>Courses</th>
</tr>";
$stmt = $db->prepare("SELECT title FROM course WHERE `subject_id`=?");
$stmt->execute(array($_POST['results']));
if ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
echo "<tr>";
echo "<td>", $row['title'], "</td>";
echo "</tr>";
}
} else {
echo "No results found";
} echo "</table>";
}
?>
This is just returning one result into the table, when there are more results to show.
Where am I going wrong?
remove the if, because it's change the pointer of array(fetch)
if ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { // get the first record, remove this if
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {// get the second record and reset $row
you can change to:
$row = $stmt->fetchAll(PDO::FETCH_ASSOC);
$total_rows = $stmt->rowCount();
if($total_rows > 0){
foreach($row as $item){
echo '<td>'. $item['title'] .'</td>';
}
}else{
echo 'no results';
}
Related
I'm pulling data from a database but only getting the first row into the dynamically produced html table.
I've tried adding another foreach loop but that isn't the answer… I'm out of ideas...
$conn = new PDO('mysql:host=localhost;dbname=jeuxvideo', $dbUserName, $dbPassword);
$sql = "SELECT * FROM jeuxvideo";
$result = $conn->prepare($sql);
$request = $result->execute();
echo "<table border='1'>";
echo "<tr><td>Id</td><td>Titre</td><td>Prix<td>Date de Sortie</td><td>Genre</td><td>Origine</td><td>Mode</td><td>Connexion</td></tr>\n";
$row = $result->fetch(PDO::FETCH_ASSOC);
echo "<tr>";
foreach ($row as $key => $value) {
echo "<td>$value</td>";
}
echo "</tr>";
echo "</table>";
This code pulls all the correct info and puts it in the right place in the html table, but for some Reason it doesn't collect the Following rows data...
This line only fetches one row:
$row = $result->fetch(PDO::FETCH_ASSOC);
You need to fetch as many rows it can give you. Once there are no more rows to fetch the function will return FALSE, so you can use with the while loop, like this:
while($row = $result->fetch(PDO::FETCH_ASSOC)) {
echo "<tr>";
foreach ($row as $key => $value) {
echo "<td>$value</td>";
}
echo "</tr>";
}
echo "</table>";
Since you don't have any variables you need prepared for your query, you can simply do:
<?php
$stmt = $pdo->query('SELECT * FROM jeuxvideo');
echo '<table>';
foreach ($stmt as $row) {
echo '<tr>';
echo "<td>$row['name']</td>";
echo "<td>$row['url']</td>";
echo "<td>$row['timestamp']</td>";
echo '</tr>';
}
echo '</table>';
A 2nd method would be:
<?php
$stmt = $pdo->query('SELECT * FROM jeuxvideo');
echo '<table>';
while ($row = $stmt->fetch()) {
echo '<tr>';
echo "<td>$row['name']</td>";
echo "<td>$row['url']</td>";
echo "<td>$row['timestamp']</td>";
echo '</tr>';
}
echo '</table>';
Try this
$conn = new PDO('mysql:host=localhost;dbname=jeuxvideo', $dbUserName, $dbPassword);
$sql = "SELECT * FROM jeuxvideo";
$result = $conn->prepare($sql);
$request = $result->execute();
echo "<table border='1'>";
echo "<tr><td>Id</td><td>Titre</td><td>Prix<td>Date de Sortie</td><td>Genre</td><td>Origine</td><td>Mode</td><td>Connexion</td></tr>\n";
$row = $request->fetch_all();
echo "<tr>";
foreach ($row as $key => $value) {
echo "<td>$value</td>";
}
echo "</tr>";
echo "</table>";
I want to read out data from an sql-database an show them in a table. This works well. Now, I would like to show only those columns with at least one value in it and not the empty ones (containing NULL, 0, empty string). This works with the following example:
enter code here
<TABLE width="500" border="1" cellpadding="1" cellspacing="1">
<?php
$query = mysql_query("SELECT * FROM guestbook", $db);
$results = array();
while($line = mysql_fetch_assoc($query)){
$results[] = $line;
$Name = array_column($results, 'Name');
$Home = array_column($results, 'Home');
$Date = array_column($results, 'Date');
$Emptycolumn = array_column($results, 'Emptycolumn');
$Comment = array_column($results, 'Comment');
$City = array_column($results, 'City');
}
echo "<TR>";
if(array_filter($Name)) {echo "<TH>Name</TH>";}
if(array_filter($Home)){echo "<TH>Home</TH>";}
if(array_filter($Date)){echo "<TH>Date</TH>";}
if(array_filter($Emptycolumn)){echo "<TH>Emptycolumn</TH>";}
if(array_filter($Comment)){echo "<TH>Comment</TH>";}
if(array_filter($City)){echo "<TH>City</TH>";}
echo "</TR>";
$query = mysql_query("SELECT * FROM guestbook", $db);
while($line = mysql_fetch_assoc($query)){
echo "<TR>";
if(array_filter($Name)) {echo "<TD>".$line['Name']."</TD>";}
if(array_filter($Home)) {echo "<TD>".$line['Home']."</TD>";}
if(array_filter($Date)) {echo "<TD>".$line['Date']."</TD>";}
if(array_filter($Emptycolumn)) {echo "<TD>".$line['Emptycolumn']."</TD>";}
if(array_filter($Comment)) {echo "<TD>".$line['Comment']."</TD>";}
if(array_filter($City)) {echo "<TD>".$line['City']."</TD>";}
echo "</TR>";
}
?>
</TABLE>
Since the column-names of my table are highly variable (depending on the query), the table is generated by looping through the result-array, first the column-names, then the values in the rows:
enter code here
$sql = "SELECT DISTINCT $selection FROM $tabelle WHERE
$whereclause"; //will be changed to PDO
$result = mysqli_query($db, $sql) or die("<b>No result</b>"); //Running
the query and storing it in result
$numrows = mysqli_num_rows($result); // gets number of rows in result
table
$numcols = mysqli_num_fields($result); // gets number of columns in
result table
$field = mysqli_fetch_fields($result); // gets the column names from the
result table
if ($numrows > 0) {
echo "<table id='myTable' >";
echo "<thead>";
echo "<tr>";
echo "<th>" . 'Nr' . "</th>";
for($x=0;$x<$numcols;$x++){
$key = array_search($field[$x]->name, $custom_column_arr);
if($key !== false){
echo "<th>" . $key . "</th>";
}else{
echo "<th>" . $field[$x]->name . "</th>";
}
}
echo "</tr></thead>";
echo "<tbody>";
$nr = 1;
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $nr . "</td>";
for ($k=0; $k<$numcols; $k++) { // goes around until there are no
columns left
echo "<td>" . $row[$field[$k]->name] . "</td>"; //Prints the data
}
echo "</tr>";
$nr = $nr + 1;
} // End of while-loop
echo "</tbody></table>";
}
}
mysqli_close($db);
Now, I tried to integrate the array_column() and array_filter()-blocks of the example above into the loops, but unfortunately, it didn´t work. I´m sure, this is easy for a professional and I would be very grateful, if someone could help me with this problem!
Thank you very much in advance!!
I have a database table called 'Modules' and I am trying to select all of the rows from that table and display them in a table. Each row has a column called MOrder which ranges from 1 - how ever many modules are available.
Here is my code:
$sql_query = "SELECT * FROM Modules WHERE CourseID = ". $CourseID ." ORDER BY MOrder ASC";
$result = mysqli_query($dbconfig, $sql_query);
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
$count = mysqli_num_rows($result);
echo '<div class="row">';
echo '<div class="col-md-12">';
echo '<table class="table">';
if($count > 0) {
$_SESSION['countMOrder'] = $count;
echo '<tr>';
echo '<th>Module Title</th> ';
echo '<th></th>';
echo '</tr>';
while ($row = mysqli_fetch_array($result)) {
echo '<tr>';
echo '<td>'. $row['Title'] .'</td> ';
echo '<td>Take Module</td>';
echo '</tr>';
}
}
echo '</table>';
echo '</div>';
echo '</div>';
?>
However, for whatever reason the statement is missing out the module with MOrder 1 and always starting with 2?
Why is this?
You are calling $row = mysqli_fetch_array($result, MYSQLI_ASSOC); in the third line of your pasted code, which is pulling the first array from the results.
This is then being overwritten in your while loop:
while ($row = mysqli_fetch_array($result)) { // <-- overwritten here with item 2
//...
}
Because in the 3rd line of your code you call
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
once, and then in the loop you start calling the
$row = mysqli_fetch_array($result)
again, thus overwriting the $row variable with the 2nd row. Get rid of the 1st $row = mysqli_fetch_array($result) line.
Try this code.
$sql_query = "SELECT * FROM Modules WHERE CourseID = ". $CourseID ." ORDER BY MOrder ASC";
$result = mysqli_query($dbconfig, $sql_query);
$count = mysqli_num_rows($result);
echo '<div class="row">';
echo '<div class="col-md-12">';
echo '<table class="table">';
if($count > 0) {
$_SESSION['countMOrder'] = $count;
echo '<tr>';
echo '<th>Module Title</th> ';
echo '<th></th>';
echo '</tr>';
while ($row = mysqli_fetch_array($result)) { //for every fetch we'll get one row.
echo '<tr>';
echo '<td>'. $row['Title'] .'</td> ';
echo '<td>Take Module</td>';
echo '</tr>';
}
}
echo '</table>';
echo '</div>';
echo '</div>';
At the beginning, you fetch the first row.
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
In while loop, fetch function returns second row.
I asked this question yesterday but no one replied after I tried to get further help. I've been trying to figure out the problem in the code I was given in my previous post but it's not giving me the results I want. Right now what it does is it writes a separator after each row but what I really want is if the name of the manager from the previous row is different then write a separator and keep going on with loop.
while ($row = mysqli_fetch_array($results)) {
$team = $row[0]['Manager'];
foreach($row as $rows){
if($rows['Manager'] !== $team){
echo "<tr><td colspan=\"3\">Separator</td></tr>";
}
echo "<tr>";
echo "<td>".$row['Manager']."</td>";
echo "<td>".$row['Employee_ID']."</td>";
echo "<td>".$row['Name']."</td>";
echo "</tr>";
}
}
You're mixing $row and $rows, you would be okay doing this:
$team = "";
while ($row = mysqli_fetch_array($results)) {
if($team && ($row['Manager'] != $team)){ // skip first separator
echo "<tr><td colspan=\"3\">Separator</td></tr>";
}
$team = $row['Manager'];
echo "<tr>";
echo "<td>".$row['Manager']."</td>";
echo "<td>".$row['Employee_ID']."</td>";
echo "<td>".$row['Name']."</td>";
echo "</tr>";
}
Am I missing something, or can you simply display the data, then assign it to the variable further in the loop?
while ($row = mysqli_fetch_array($results)) {
$team = $row[0]['Manager'];
foreach($row as $rows){
if($row['Manager'] !== $team){
echo "<tr><td colspan=\"3\">".$team."</td></tr>";
}
echo "<tr>";
echo "<td>".$row['Manager']."</td>";
echo "<td>".$row['Employee_ID']."</td>";
echo "<td>".$row['Name']."</td>";
echo "</tr>";
$team = $row[0]['Manager'];
}
}
What is $rowS['Manager'] ? $rowS is unknown. use $row['Manager'] like:
if($row['Manager'] !== $team){
echo "<tr><td colspan=\"3\">Separator</td></tr>";
}
while ($row = mysqli_fetch_array($results)) {
$team = $row[0]['Manager'];
foreach($row as $rows){
if($rows['Manager'] !== $team) {
$team = $row['Manager'];
echo "<tr><td colspan=\"3\">Separator</td></tr>";
}
echo "<tr>";
echo "<td>".$row['Manager']."</td>";
echo "<td>".$row['Employee_ID']."</td>";
echo "<td>".$row['Name']."</td>";
echo "</tr>";
}
}
Just move the value allocation $team = $rows['Manager']; in the if condition.
while ($row = mysqli_fetch_array($results)) {
$team = "";
foreach($row as $rows){
if($rows['Manager'] != $team){
echo "<tr><td colspan=\"3\">Separator</td></tr>";
$team = $rows['Manager'];
}
echo "<tr>";
echo "<td>".$rows['Manager']."</td>";
echo "<td>".$rows['Employee_ID']."</td>";
echo "<td>".$rows['Name']."</td>";
echo "</tr>";
}
}
Hi I'm attempting to display data retrieved from a mysql table horizontally in an html table using php. The code below works well except for the fact that it leaves out the first record (starts at the second record) in my database. I'm sure it has something to do with the counter but I can't seem to figure out how to get it to stop doing this. If anyone can point out my error I'd really appreciate it!
$items = 5;
$query = "SELECT * FROM members ";
$result = mysql_query($query)
or die(mysql_error());
$row = mysql_fetch_array($result);
if (mysql_num_rows($result) > 0) {
echo '<table border="1">';
$i = 0;
while($row = mysql_fetch_array($result)){
$first_name = $row['first_name'];
if ($i==0) {
echo "<tr>\n";
}
echo "\t<td align=\center\">$first_name</td>\n";
$i++;
if ($i == $items) {
echo "</tr>\n";
$i = 0;
}
}//end while loop
if ($i > 0) {
for (;$i < $items; $i++) {
echo "<td> </td>\n";
}
echo '</tr>';
}//end ($i>0) if
echo '</table>';
}else {
echo 'no records found';
}
try and remove the 1st
$row = mysql_fetch_array($result);
you are calling it twice, that's why it skips 1 row in your while loop
try this simpler.
$items = 5;
$query = "SELECT * FROM members ";
$result = mysql_query($query) or die(mysql_error());
if (mysql_num_rows($result) > 0) {
echo '<table border="1">';
while($row = mysql_fetch_array($result)){
$first_name = $row['first_name'];
echo "<tr>";
for ($i=0 ; $i <= $items ;$i++) {
echo "<td align='center'>".$first_name."</td>";
}
}//end while loop
echo "</tr>";
echo '</table>';
}else{ echo 'no records found'; }
I have run into this issue before. Try the do while loop instead. Example
do {
// code
} while($row = mysql_fetch_array($result)); //end while loop
$row = mysql_fetch_array($result);
1) remove this line of code from ur scripts
2) only use while loop code instead.