In a comma delimited string, in php, as such: "1,2,3,4,4,4,5" is it possible to say:
if(!/*4 is in string bla*/){
// add it via the .=
}else{
// do something
}
In arrays you can do in_array(); but this isn't a set of arrays and I don't want to have to convert it to an array ....
Try exploding it into an array before searching:
$str = "1,2,3,4,4,4,5";
$exploded = explode(",", $str);
if(in_array($number, $exploded)){
echo 'In array!';
}
You can also replace numbers and modify the array before "sticking it back together" with implode:
$strAgain = implode(",", $exploded);
You could do this with regex:
$re = '/(^|,)' + preg_quote($your_number) + '(,|$)/';
if(preg_match($re, $your_string)) {
// ...
}
But that's not exactly the clearest of code; someone else (or even yourself, months later) who had to maintain the code would probably not appreciate having something that's hard to follow. Having it actually be an array would be clearer and more maintainable:
$values = explode(',', $your_string);
if(in_array((str)$number, $values)) {
// ...
}
If you need to turn the array into a string again, you can always use implode():
$new_string = implode(',', $values);
Related
I found this code in another post which I found quite helpful but for me it's only half the equation. In line with the following code, I need to take the string from a database, explode it into the 2d array, edit values in the array and implode it back ready for storage in the same format. So specifically backwards in the same order as the existing script.
The code from the other post >>
$data = "i love funny movies \n i love stackoverflow dot com \n i like rock song";
$data = explode(" \n ", $data);
$out = array();
$step = 0;
$last = count($data);
$last--;
foreach($data as $key=>$item){
foreach(explode(' ',$item) as $value){
$out[$key][$step++] = $value;
}
if ($key!=$last){
$out[$key][$step++] = ' '; // not inserting last "space"
}
}
print '<pre>';
print_r($out);
print '</pre>';
The quoted code inserts separate array elements which just have a space as value. One can wonder what benefit those bring.
Here are two functions you could use:
function explode2D($row_delim, $col_delim, $str) {
return array_map(function ($line) use ($col_delim) {
return explode($col_delim, $line);
}, explode($row_delim, $str));
}
function implode2D($row_delim, $col_delim, $arr) {
return implode($row_delim,
array_map(function ($row) use ($col_delim) {
return implode($col_delim, $row);
}, $arr));
}
They are each other's opposite, and work much like the standard explode and implode functions, except that you need to specify two delimiters: one to delimit the rows, and another for the columns.
Here is how you would use it:
$data = "i love funny movies \n i love stackoverflow dot com \n i like rock song";
$arr = explode2D(" \n ", " ", $data);
// manipulate data
// ...
$arr[0][2] = "scary";
$arr[2][2] = "balad";
// convert back
$str = implode2D(" \n ", " ", $arr);
See it run on repl.it.
Suppose I have a string:
$str="1,3,6,4,0,5";
Now user inputs 3.
I want that to remove 3 from the above string such that above string should become:
$str_mod="1,6,4,0,5";
Is there any function to do the above?
You can split it up, remove the one you want then whack it back together:
$str = "1,3,6,4,0,5";
$userInput = 3;
$bits = explode(',', $str);
$result = array_diff($bits, array($userInput));
echo implode(',', $result); // 1,6,4,0,5
Bonus: Make $userInput an array at the definition to take multiple values out.
preg_replace('/\d[\D*]/','','1,2,3,4,5,6');
in place of \d just place your digit php
If you don't want to do string manipulations, you can split the string into multiple pieces, remove the ones you don't need, and join the components back:
$numberToDelete = 3;
$arr = explode(',',$string);
while(($idx = array_search($numberToDelete, $components)) !== false) {
unset($components[$idx]);
}
$string = implode(',', $components);
The above code will remove all occurrences of 3, if you want only the first one yo be removed you can replace the while by an if.
This question already has answers here:
PHP: How can I explode a string by commas, but not wheres the commas are within quotes?
(2 answers)
Closed 8 years ago.
I'm trying to figure out how to add double quote between text which separates by a comma.
e.g. I have a string
$string = "starbucks, KFC, McDonalds";
I would like to convert it to
$string = '"starbucks", "KFC", "McDonalds"';
by passing $string to a function. Thanks!
EDIT: For some people who don't get it...
I ran this code
$result = mysql_query('SELECT * FROM test WHERE id= 1');
$result = mysql_fetch_array($result);
echo ' $result['testing']';
This returns the strings I mentioned above...
Firstly, make your string a proper string as what you've supplied isn't. (pointed out by that cutey Fred -ii-).
$string = 'starbucks, KFC, McDonalds';
$parts = explode(', ', $string);
As you can see the explode sets an array $parts with each name option. And the below foreach loops and adds your " around the names.
$d = array();
foreach ($parts as $name) {
$d[] = '"' . $name . '"';
}
$d Returns:
"starbucks", "KFC", "McDonalds"
probably not the quickest way of doing it, but does do as you requested.
As this.lau_ pointed out, its most definitely a duplicate.
And if you want a simple option, go with felipsmartins answer :-)
It should work like a charm:
$parts = split(', ', 'starbucks, KFC, McDonalds');
echo('"' . join('", "', $parts) . '"');
Note: As it has noticed in the comments (thanks, nodeffect), "split" function has been DEPRECATED as of PHP 5.3.0. Use "explode", instead.
Here is the basic function, without any checks (i.e. $arr should be an array in array_map and implode functions, $str should be a string, not an array in explode function):
function get_quoted_string($str) {
// Here you will get an array of words delimited by comma with space
$arr = explode (', ', $str);
// Wrapping each array element with quotes
$arr = array_map(function($x){ return '"'.$x.'"'; }, $arr);
// Returning string delimited by comma with space
return implode(', ', $arr);
}
Came in my mind a really nasty way to do it. explode() on comma, foreach value, value = '"' . $value . '"';, then run implode(), if you need it as a single value.
And you're sure that's not an array? Because that's weird.
But here's a way to do it, I suppose...
$string = "starbucks, KFC, McDonalds";
// Use str_replace to replace each comma with a comma surrounded by double-quotes.
// And then shove a double-quote on the beginning and end
// Remember to escape your double quotes...
$newstring = "\"".str_replace(", ", "\",\"", $string)."\"";
hey there I have this,
$following_user_id .= $row['following_user_id'];
and I get
44443344330
then I use the implode() function and seperate with commans
44,44,33,44,33,0,
but I don't want the last comma on the last number?
Is this possible?
$following_user_ids = array();
//loop this:
$following_user_ids[] = $row['following_user_id'];
$user_ids_string = implode(',',$following_user_ids);
You can split the string into an array of characters, then implode the array.
$array = preg_split('//', $following_user_id, -1, PREG_SPLIT_NO_EMPTY);
echo implode( ',', $array );
Collect your data into an array of strings and use the implode function:
$uids = array();
while($row = mysql_fetch_assoc($result)){
array_push($uids, $row['following_user_id']);
}
$following_user_id = implode(',', $uids);
Check implode: http://php.net/manual/en/function.implode.php
Code example: I'm assuming your using some sort of loop?
$arrUsers = new array();
... your loop code here ...
array_push($arrUsers, $row['following_user_id']);
... end loop code ..
$following_user_id = impload(",", $arrUsers);
Implode should not be inserting a comma at the end of that string there. Are you sure there isn't an empty string at the end of your array sequence?
Either way, to fix the string you have, just get rid of the last character of the string:
$concatUserIds = "44,44,33,44,33,0,";
$concatUserIds = substr($concatUserIds, 0, strlen($concatUserIds) - 1);
Further, if you're not going to be using the non-comma delimited number set, why don't you just add a comma every time you add a user id. That way you don't even have to use the implode function.
This works for me:
<?php
$following_user_id.= $row['following_user_id'];
$following_user_id=preg_replace('/(?<=\d)(?=(\d)+(?!\d))/',',',$following_user_id);
echo $following_user_id."<br>";
?>
Try using arrays, example
<?php
$arr = array();
$arr[] = 'foo';
$arr[] = 'bar';
echo implode(',', $arr);
hey there I have this,
$following_user_id .= $row['following_user_id'];
and I get
44443344330
then I use the implode() function and seperate with commans
44,44,33,44,33,0,
but I don't want the last comma on the last number?
Is this possible?
$following_user_ids = array();
//loop this:
$following_user_ids[] = $row['following_user_id'];
$user_ids_string = implode(',',$following_user_ids);
You can split the string into an array of characters, then implode the array.
$array = preg_split('//', $following_user_id, -1, PREG_SPLIT_NO_EMPTY);
echo implode( ',', $array );
Collect your data into an array of strings and use the implode function:
$uids = array();
while($row = mysql_fetch_assoc($result)){
array_push($uids, $row['following_user_id']);
}
$following_user_id = implode(',', $uids);
Check implode: http://php.net/manual/en/function.implode.php
Code example: I'm assuming your using some sort of loop?
$arrUsers = new array();
... your loop code here ...
array_push($arrUsers, $row['following_user_id']);
... end loop code ..
$following_user_id = impload(",", $arrUsers);
Implode should not be inserting a comma at the end of that string there. Are you sure there isn't an empty string at the end of your array sequence?
Either way, to fix the string you have, just get rid of the last character of the string:
$concatUserIds = "44,44,33,44,33,0,";
$concatUserIds = substr($concatUserIds, 0, strlen($concatUserIds) - 1);
Further, if you're not going to be using the non-comma delimited number set, why don't you just add a comma every time you add a user id. That way you don't even have to use the implode function.
This works for me:
<?php
$following_user_id.= $row['following_user_id'];
$following_user_id=preg_replace('/(?<=\d)(?=(\d)+(?!\d))/',',',$following_user_id);
echo $following_user_id."<br>";
?>
Try using arrays, example
<?php
$arr = array();
$arr[] = 'foo';
$arr[] = 'bar';
echo implode(',', $arr);